結果
問題 | No.2157 崖 |
ユーザー | mikam |
提出日時 | 2022-12-09 22:19:37 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 4,001 bytes |
コンパイル時間 | 4,865 ms |
コンパイル使用メモリ | 270,456 KB |
実行使用メモリ | 35,456 KB |
最終ジャッジ日時 | 2024-10-14 22:18:37 |
合計ジャッジ時間 | 57,068 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 3 ms
5,248 KB |
testcase_02 | AC | 3 ms
5,248 KB |
testcase_03 | WA | - |
testcase_04 | AC | 3 ms
5,248 KB |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | AC | 3 ms
5,248 KB |
testcase_09 | WA | - |
testcase_10 | AC | 3 ms
5,248 KB |
testcase_11 | WA | - |
testcase_12 | AC | 3 ms
5,248 KB |
testcase_13 | WA | - |
testcase_14 | WA | - |
testcase_15 | WA | - |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | WA | - |
testcase_20 | TLE | - |
testcase_21 | TLE | - |
testcase_22 | WA | - |
testcase_23 | AC | 2 ms
6,816 KB |
testcase_24 | AC | 4 ms
6,820 KB |
ソースコード
#include <atcoder/all> using namespace atcoder; #include <bits/stdc++.h> using namespace std; // #include <boost/multiprecision/cpp_int.hpp> #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define rep2(i,a,b) for (int i = (int)(a); i < (int)(b); i++) #define all(v) v.begin(),v.end() #define inc(x,l,r) ((l)<=(x)&&(x)<(r)) #define Unique(x) sort(all(x)), x.erase(unique(all(x)), x.end()) typedef long long ll; #define int ll using ld = long double; using vi = vector<int>; using vs = vector<string>; using P = pair<int,int>; using vp = vector<P>; // using Bint = boost::multiprecision::cpp_int; template<typename T> using priority_queue_greater = priority_queue<T, vector<T>, greater<T>>; template<typename T> ostream &operator<<(ostream &os,const vector<T> &v){rep(i,v.size())os<<v[i]<<(i+1!=v.size()?" ":"");return os;} template<typename T> istream &operator>>(istream& is,vector<T> &v){for(T &in:v)is>>in;return is;} template<class... T> void _IN(T&... a){(cin>> ... >> a);} template<class T> void _OUT(T& a){cout <<a<< '\n';} template<class T,class... Ts> void _OUT(const T&a, const Ts&... b){cout<< a;(cout<<...<<(cout<<' ',b));cout<<'\n';} #define INT(...) int __VA_ARGS__; _IN(__VA_ARGS__) #define STR(...) string __VA_ARGS__; _IN(__VA_ARGS__) #define pcnt __builtin_popcountll int sign(int x){return (x>0)-(x<0);} int ceil(int x,int y){assert(y!=0);if(sign(x)==sign(y))return (x+y-1)/y;return -((-x/y));} int floor(int x,int y){assert(y!=0);if(sign(x)==sign(y))return x/y;if(y<0)x*=-1,y*=-1;return x/y-(x%y<0);} int abs(int x,int y){return abs(x-y);} bool ins(string s,string t){return s.find(t)!=string::npos;} P operator+ (const P &p, const P &q){ return P{p.first+q.first,p.second+q.second};} P operator- (const P &p, const P &q){ return P{p.first-q.first,p.second-q.second};} template<typename T1,typename T2> ostream &operator<< (ostream &os, const pair<T1,T2> &p){os << p.first <<" "<<p.second;return os;} ostream &operator<< (ostream &os, const modint1000000007 &m){os << m.val();return os;} istream &operator>> (istream &is, modint1000000007 &m){ll in;is>>in;m=in;return is;} ostream &operator<< (ostream &os, const modint998244353 &m){os << m.val();return os;} istream &operator>> (istream &is, modint998244353 &m){ll in;is>>in;m=in;return is;} template<typename T1,typename T2> bool chmax(T1 &a, const T2 b) {if (a < b) {a = b; return true;} else return false; } template<typename T1,typename T2> bool chmin(T1 &a, const T2 b) {if (a > b) {a = b; return true;} else return false; } void yesno(bool ok,string y="Yes",string n="No"){ cout<<(ok?y:n)<<endl;} int di[]={-1,0,1,0,-1,-1,1,1}; int dj[]={0,1,0,-1,-1,1,-1,1}; const int INF = 8e18; //using mint = modint1000000007; //using mint = modint998244353; signed main() { cin.tie(0); ios_base::sync_with_stdio(false); cout << fixed << setprecision(20); INT(n,m); vector D(n,vi(m));cin>>D; rep(i,n)sort(all(D[i])); int ok = 2e9; int ng = -1; auto f = [&](int x){ //x以下は遷移できる vector dp(n,vi(m)); rep(j,m){ auto nj = upper_bound(all(D[0]),D[1][j])-D[0].begin()-1; if(nj>=0 && D[1][j]-D[0][nj]<=x)dp[1][j] = 1; } for(int i=1;i<n-1;i++){ rep(j,m-1)dp[i][j+1]+=dp[i][j]; auto sum = [&](int l,int r){ int res = dp[i][r-1]; if(l)res -= dp[i][l-1]; return res; }; rep(j,m){ int l = lower_bound(all(D[i]),D[i+1][j]-x)-D[i].begin(); int r = upper_bound(all(D[i]),D[i+1][j])-D[i].begin(); if(sum(l,r))dp[i+1][j] = 1; } } rep(j,m)if(dp[n-1][j])return true; return false; }; while(abs(ng-ok)>1){ int mid = ng+(ok-ng)/2; if(f(mid))ok=mid; else ng = mid; } if(ok==2e9)ok=-1; cout << ok << endl; return 0; }