結果

問題 No.2180 Comprehensive Line Segments
ユーザー MasKoaTS
提出日時 2022-12-17 13:39:51
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 2,247 bytes
コンパイル時間 460 ms
コンパイル使用メモリ 82,104 KB
実行使用メモリ 214,828 KB
最終ジャッジ日時 2024-11-17 01:37:14
合計ジャッジ時間 77,776 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3 TLE * 1
other AC * 15 WA * 2 TLE * 8
権限があれば一括ダウンロードができます

ソースコード

diff # 

from __future__ import annotations
import sys
from itertools import permutations
from fractions import Fraction as frac
input = sys.stdin.readline


class Vector2:
	def __init__(self, x, y):
		self.x = x
		self.y = y

	def __str__(self):
		return str((self.x, self.y))

	__repr__ = __str__

	def __eq__(self, other):
		return (self.x == other.x and self.y == other.y)

	def __hash__(self):
		return hash((self.x, self.y))

	def __add__(self, other):
		return Vector2(self.x + other.x, self.y + other.y)

	def __sub__(self, other):
		return Vector2(self.x - other.x, self.y - other.y)

	def __mul__(self, other):
		return self.x * other.y - self.y * other.x

	def normalize(self) -> Vector2:
		assert(self.x != 0 or self.y != 0)
		norm = self.x ** 2 + self.y ** 2
		self.x *= abs(self.x) / norm
		self.y *= abs(self.y) / norm
		return self


def sgn(x: frac) -> int:
	if(x > 0):
		return 1
	if(x < 0):
		return -1
	return 0


"""
Main Code
"""

N = int(input())
P = [Vector2(*map(frac, input().split())) for _ in [0] * N]

if(N == 1):
	print(1)
	exit(0)

vec_lis = [[None]*N for _ in [0]*N]
for i in range(N - 1):
	for j in range(i + 1, N):
		vec_lis[i][j] = (P[j] - P[i]).normalize()
		vec_lis[j][i] = (P[i] - P[j]).normalize()

ans = N
dp = [[[N]*N for _ in [0]*N] for _ in [0]*(1 << N)]
num = [*range(N)]
for i, j in permutations(num, 2):
	dp[(1 << i) | (1 << j)][i][j] = 1

goal = (1 << N) - 1
for b_now in range(3, goal):
	for v_prev, v_now in permutations(num, 2):
		if(dp[b_now][v_prev][v_now] == N or not((b_now >> v_prev) & 1) or not((b_now >> v_now) & 1)):
			continue
		c_next = c_now = dp[b_now][v_prev][v_now]
		v1 = vec_lis[v_prev][v_now]
		for v_next1, v_next2 in permutations(num, 2):
			if((((b_now >> v_next1) & 1) and v_now != v_next1) or ((b_now >> v_next2) & 1)):
				continue
			b_next = b_now | (1 << v_next1) | (1 << v_next2)
			v2, v3 = vec_lis[v_now][v_next1], vec_lis[v_next1][v_next2]
			if(v_now == v_next1):
				c_next = c_now + (v1 != v3)
			else:
				d = (v1 == v2) + (v2 == v3)
				if(d == 0):
					d = (sgn(v1 * v2) == sgn(v2 * v3) == sgn(v1 * v3))
				c_next = c_now + 2 - d
			if(dp[b_next][v_next1][v_next2] <= c_next):
				continue
			dp[b_next][v_next1][v_next2] = c_next

ans = min(min(dp[goal]))
print(ans)
0