結果
| 問題 | No.526 フィボナッチ数列の第N項をMで割った余りを求める | 
| コンテスト | |
| ユーザー |  | 
| 提出日時 | 2022-12-30 23:04:22 | 
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 75 ms / 2,000 ms | 
| コード長 | 449 bytes | 
| コンパイル時間 | 1,585 ms | 
| コンパイル使用メモリ | 165,640 KB | 
| 実行使用メモリ | 6,820 KB | 
| 最終ジャッジ日時 | 2024-11-25 21:33:44 | 
| 合計ジャッジ時間 | 2,536 ms | 
| ジャッジサーバーID (参考情報) | judge4 / judge3 | 
(要ログイン)
| ファイルパターン | 結果 | 
|---|---|
| sample | AC * 3 | 
| other | AC * 12 | 
コンパイルメッセージ
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/istream:39,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/sstream:38,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/complex:45,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ccomplex:39,
                 from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/x86_64-pc-linux-gnu/bits/stdc++.h:54,
                 from main.cpp:1:
In member function 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(long long int) [with _CharT = char; _Traits = std::char_traits<char>]',
    inlined from 'int main()' at main.cpp:22:11:
/home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:202:25: warning: 'pre' may be used uninitialized [-Wmaybe-uninitialized]
  202 |       { return _M_insert(__n); }
      |                ~~~~~~~~~^~~~~
main.cpp: In function 'int main()':
main.cpp:12:6: note: 'pre' was declared here
   12 |   ll pre, prepre;
      |      ^~~
            
            ソースコード
#include <bits/stdc++.h>
#define rep(i,n) for(int i=0; i<n; ++i)
using namespace std;
using std::abs;
using P = pair<long long, long long>;
typedef long long ll;
const ll INF = 100000000000000000LL;
int main(void) {
 ll N, M;
  cin >> N >> M;
  ll pre, prepre;
  rep(i, N) {
    if(i == 0) prepre = 0;
    else if(i == 1) pre = 1;
    else {
      ll tmp = (prepre + pre) % M;
      prepre = pre;
      pre = tmp;
    }
  }
  cout << pre << endl;
}
            
            
            
        