結果

問題 No.2176 LRM Question 1
ユーザー noya2noya2
提出日時 2023-01-06 21:33:03
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 26 ms / 2,000 ms
コード長 5,295 bytes
コンパイル時間 5,201 ms
コンパイル使用メモリ 268,608 KB
実行使用メモリ 7,424 KB
最終ジャッジ日時 2024-05-07 21:02:24
合計ジャッジ時間 5,843 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge2
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 2 ms
5,248 KB
testcase_02 AC 21 ms
7,404 KB
testcase_03 AC 2 ms
5,376 KB
testcase_04 AC 16 ms
7,360 KB
testcase_05 AC 3 ms
5,376 KB
testcase_06 AC 2 ms
5,376 KB
testcase_07 AC 3 ms
5,376 KB
testcase_08 AC 16 ms
7,372 KB
testcase_09 AC 15 ms
7,268 KB
testcase_10 AC 19 ms
6,656 KB
testcase_11 AC 2 ms
5,376 KB
testcase_12 AC 2 ms
5,376 KB
testcase_13 AC 26 ms
7,424 KB
testcase_14 AC 21 ms
7,296 KB
testcase_15 AC 17 ms
6,528 KB
testcase_16 AC 14 ms
6,016 KB
testcase_17 AC 3 ms
5,376 KB
testcase_18 AC 25 ms
7,040 KB
testcase_19 AC 18 ms
5,888 KB
testcase_20 AC 8 ms
5,376 KB
testcase_21 AC 10 ms
5,376 KB
testcase_22 AC 2 ms
5,376 KB
testcase_23 AC 9 ms
5,376 KB
testcase_24 AC 13 ms
5,376 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#line 1 "c.cpp"
#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,n) for (int i = 0; i < int(n); ++i)
#define repp(i,n,m) for (int i = m; i < int(n); ++i)
#define reb(i,n) for (int i = int(n)-1; i >= 0; --i)
#define all(v) v.begin(),v.end()
using namespace std;
using namespace atcoder;
using ll = long long;
using ull = unsigned long long;
using ld = long double;
using P = pair<int, int>;
using PL = pair<long long, long long>;
using pdd = pair<long double, long double>;
using pil = pair<int,ll>;
using pli = pair<ll,int>;
template<class T>istream &operator>>(istream &is,vector<T> &v){for(auto &e:v)is>>e;return is;}
template<typename T>bool range(T a,T b,T x){return (a<=x&&x<b);}
template<typename T>bool rrange(T a,T b,T c,T d,T x,T y){return (range(a,c,x)&&range(b,d,y));}
template<typename T>void rev(vector<T> &v){reverse(v.begin(),v.end());}
void revs(string &s) {reverse(s.begin(),s.end());}
template<typename T>void sor(vector<T> &v, int f=0){sort(v.begin(),v.end());if(f!=0) rev(v);}
template<typename T>bool chmin(T &a,const T &b){if(a>b){a=b;return true;}return false;}
template<typename T>bool chmax(T &a,const T &b){if(a<b){a=b;return true;}return false;}
template<typename T>void uniq(vector<T> &v){sor(v);v.erase(unique(v.begin(),v.end()),v.end());}
template<typename T1, typename T2>void print(pair<T1,T2> a);
template<typename T>void print(vector<T> v);
template<typename T>void print(vector<vector<T>> v);
void print(){ putchar(' '); }
void print(bool a){ printf("%d", a); }
void print(int a){ printf("%d", a); }
void print(long a){ printf("%ld", a); }
void print(long long a){ printf("%lld", a); }
void print(char a){ printf("%c", a); }
void print(char a[]){ printf("%s", a); }
void print(const char a[]){ printf("%s", a); }
void print(long double a){ printf("%.15Lf", a); }
void print(const string& a){ for(auto&& i : a) print(i); }
void print(unsigned int a){ printf("%u", a); }
void print(unsigned long long a) { printf("%llu", a); }
template<class T> void print(const T& a){ cout << a; }
int out(){ putchar('\n'); return 0; }
template<class T> int out(const T& t){ print(t); putchar('\n'); return 0; }
template<class Head, class... Tail> int out(const Head& head, const Tail&... tail){ print(head); putchar(' '); out(tail...); return 0; }
template<typename T1,typename T2>void print(pair<T1,T2> a){print(a.first);print(),print(a.second);}
template<typename T>void print(vector<T> v){for(auto ite=v.begin();ite!=v.end();){print(*ite);if(++ite!=v.end())print();}}
template<typename T>void print(vector<vector<T>> v){for(auto ite=v.begin();ite!=v.end();){print(*ite);if(++ite!=v.end())out();}}
void yes(){out("Yes");}
void no (){out("No");}
void yn (bool t){if(t)yes();else no();}
void fast_io(){cin.tie(0); ios::sync_with_stdio(0); cout<<fixed<<setprecision(20);}
void o(){out("!?");}

namespace noya2{

const int INF = 1001001007;
const long long mod1 = 998244353;
const long long mod2 = 1000000007;
const long long inf = 2e18;
const long double pi = 3.14159265358979323;
const long double eps = 1e-7;
const vector<int> dx = {0,1,0,-1,1,1,-1,-1};
const vector<int> dy = {1,0,-1,0,1,-1,-1,1};
const string ALP = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const string alp = "abcdefghijklmnopqrstuvwxyz";
const string NUM = "0123456789";

} // namespace noya2
using namespace noya2;

//using mint = modint998244353;
//using mint = modint1000000007;
using mint = modint;
void out(mint a){out(a.val());}
void out(vector<mint> a){vector<ll> b(a.size()); rep(i,a.size()) b[i] = a[i].val(); out(b);}
void out(vector<vector<mint>> a){for (auto v : a) out(v);}
istream &operator>>(istream &is,vector<mint> &v){for(auto &e:v){ll _x;is>>_x;e=_x;}return is;}

#line 2 "binom.hpp"

#line 4 "binom.hpp"

namespace noya2{

template<typename T>
struct MINT{
    MINT(int lim = -1){init(lim);}
    static T fact(int x) {init(x); return kaijo[x];}
    static T ifact(int x){init(x); return kainv[x];}
    static T ncr(int n, int r){
        if (n < r || r < 0) return T(0);
        init(n);
        return kaijo[n] * kainv[r] * kainv[n-r];
    }
    static T npr(int n, int r){
        if (n < r || r < 0) return T(0);
        init(n);
        return kaijo[n] * kainv[n-r];
    }
  private:
    static std::vector<T> kaijo, kainv;
    static void init(int lim){
        if (lim <= -1) lim = 300000;
        if ((int)kaijo.size() > lim) return ;
        int siz = kaijo.size();
        kaijo.resize(lim+1), kainv.resize(lim+1);
        for (int i = siz; i <= lim; i++) kaijo[i] = kaijo[i-1] * T(i);
        kainv[lim] = kaijo[lim].inv();
        for (int i = lim-1; i >= siz; i--) kainv[i] = kainv[i+1] * T(i+1);
    }
};
template<typename T>
std::vector<T>MINT<T>::kaijo = vector<T>(2,T(1));
template<typename T>
std::vector<T>MINT<T>::kainv = vector<T>(2,T(1));

} // namespace noya2
#line 80 "c.cpp"

void solve(){
    ll l, r, m; cin >> l >> r >> m;
    mint::set_mod(m);
    vector<mint> fact(m+1,1);
    rep(i,m) fact[i+1] = fact[i] * (i+1);
    auto get = [&](ll N){
        mint res = 0;
        mint prd = 1;
        for (ll n = 1; n <= min(N,m-1); n++){
            prd *= fact[n];
            res += prd;
        }
        return res;
    };
    mint ans = get(r) - get(l-1);
    out(ans.val());
}

int main(){
    fast_io();
    int t = 1; //cin >> t;
    while(t--) solve();
}
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