結果

問題 No.2178 Payable Magic Items
ユーザー deuteridayodeuteridayo
提出日時 2023-01-06 23:49:51
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 2,992 ms / 4,000 ms
コード長 2,983 bytes
コンパイル時間 5,138 ms
コンパイル使用メモリ 280,428 KB
実行使用メモリ 70,780 KB
最終ジャッジ日時 2024-12-14 17:29:50
合計ジャッジ時間 31,933 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,820 KB
testcase_01 AC 2 ms
6,820 KB
testcase_02 AC 2 ms
6,816 KB
testcase_03 AC 2 ms
6,816 KB
testcase_04 AC 2 ms
6,820 KB
testcase_05 AC 336 ms
16,256 KB
testcase_06 AC 49 ms
6,820 KB
testcase_07 AC 2 ms
6,816 KB
testcase_08 AC 144 ms
9,856 KB
testcase_09 AC 19 ms
6,816 KB
testcase_10 AC 2 ms
6,816 KB
testcase_11 AC 2,844 ms
70,576 KB
testcase_12 AC 2,068 ms
40,952 KB
testcase_13 AC 2,963 ms
70,696 KB
testcase_14 AC 2,843 ms
70,772 KB
testcase_15 AC 2,992 ms
70,780 KB
testcase_16 AC 2,940 ms
70,728 KB
testcase_17 AC 2,343 ms
66,560 KB
testcase_18 AC 11 ms
6,820 KB
testcase_19 AC 401 ms
17,152 KB
testcase_20 AC 4 ms
6,820 KB
testcase_21 AC 10 ms
6,820 KB
testcase_22 AC 12 ms
6,816 KB
testcase_23 AC 4 ms
6,816 KB
testcase_24 AC 2,652 ms
68,944 KB
testcase_25 AC 2,175 ms
65,280 KB
testcase_26 AC 447 ms
17,664 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<bits/stdc++.h>
#include<atcoder/all>
using namespace std;
using namespace atcoder;
using lint = long long;
using ulint = unsigned long long;
#define endl '\n'
int const INF = 1<<30;
lint const INF64 = 1LL<<61;
// lint const mod = 1e9+7;
// using mint = modint1000000007;
long const mod = 998244353;
using mint = modint998244353;
lint ceilDiv(lint x, lint y){if(x >= 0){return (x+y-1)/y;}else{return x/y;}}
lint floorDiv(lint x, lint y){if(x >= 0){return x/y;}else{return (x-y+1)/y;}}
lint Sqrt(lint x){lint upper = 1e9;lint lower = 0;while(upper - lower > 0){lint mid = (1+upper + lower)/2;if(mid * mid > x){upper = mid-1;}else{lower = mid;}}return upper;}
lint gcd(lint a,lint b){if(a<b)swap(a,b);if(a%b==0)return b;else return gcd(b,a%b);}
lint lcm(lint a,lint b){return (a / gcd(a,b)) * b;}
lint chmin(vector<lint>&v){lint ans = INF64;for(lint i:v){ans = min(ans, i);}return ans;}
lint chmax(vector<lint>&v){lint ans = -INF64;for(lint i:v){ans = max(ans, i);}return ans;}
double dist(double x1, double y1, double x2, double y2){return sqrt(pow(x1-x2, 2) + pow(y1-y2,2));}
string toString(lint n){string ans = "";if(n == 0){ans += "0";}else{while(n > 0){int a = n%10;char b = '0' + a;string c = "";c += b;n /= 10;ans = c + ans;}}return ans;}
string toString(lint n, lint k){string ans = toString(n);string tmp = "";while(ans.length() + tmp.length() < k){tmp += "0";}return tmp + ans;}
vector<lint>prime;void makePrime(lint n){prime.push_back(2);for(lint i=3;i<=n;i+=2){bool chk = true;for(lint j=0;j<prime.size() && prime[j]*prime[j] <= i;j++){if(i % prime[j]==0){chk=false;break;}}if(chk)prime.push_back(i);}}
lint Kai[20000001]; bool firstCallnCr = true; 
lint ncrmodp(lint n,lint r,lint p){ if(firstCallnCr){ Kai[0] = 1; for(int i=1;i<=20000000;i++){ Kai[i] = Kai[i-1] * i; Kai[i] %= mod;} firstCallnCr = false;} if(n<0)return 0;
if(n < r)return 0;if(n==0)return 1;lint ans = Kai[n];lint tmp = (Kai[r] * Kai[n-r]) % p;for(lint i=1;i<=p-2;i*=2){if(i & p-2){ans *= tmp;ans %= p;}tmp *= tmp;tmp %= p;}return ans;}
#define rep(i, n) for(int i = 0; i < n; i++)
#define repp(i, x, y) for(int i = x; i < y; i++)
#define vec vector
#define pb push_back
#define se second
#define fi first

struct edge{
    int to;
};
using graph = vector<vector<edge>>;


queue<string>que;
map<string ,int>anss;
map<string, bool>m;

    lint n,k;

bool f(string s) {
    if(anss[s] != 0) {
        if(anss[s] == 1) return true;
        else return false;
    }
    // cerr << s << endl;
    
    bool chk = false;
    rep(i, k) {
        if(s[i] != '4') {
            s[i]++;
            chk |= f(s);
            chk |= m[s];
            s[i]--;
        }
    }
    if(chk) {
        anss[s] = 1;
    } else {
        anss[s] = 2;
    }
    return chk;
}

int main(){
    cin >> n >> k;
    string t[n];
    rep(i, n) {
        string s;
        cin >> s;
        t[i] = s;
        m[s] = true;
    }
    int ans = 0;
    rep(i, n) {
        if(f(t[i]))ans++;
    }
    cout << ans << endl;
}

0