結果
| 問題 | No.2183 LCA on Rational Tree |
| ユーザー |
shobonvip
|
| 提出日時 | 2023-01-08 04:03:30 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 453 ms / 2,000 ms |
| コード長 | 2,762 bytes |
| 記録 | |
| コンパイル時間 | 525 ms |
| コンパイル使用メモリ | 82,048 KB |
| 実行使用メモリ | 78,852 KB |
| 最終ジャッジ日時 | 2024-12-15 05:47:20 |
| 合計ジャッジ時間 | 2,784 ms |
|
ジャッジサーバーID (参考情報) |
judge2 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 6 |
ソースコード
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n")+(not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s:self.buffer.write(s.encode("ascii"))
self.read = lambda:self.buffer.read().decode("ascii")
self.readline = lambda:self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda:sys.stdin.readline().rstrip("\r\n")
from math import gcd
# plist を素数リストを使って高速化
def plist(m:int, ps:list) -> list:
pf = []
for i in ps:
flag = False
while m%i == 0:
flag = True
m //= i
if flag: pf.append(i)
if m>1 : pf.append(m)
return pf
def gogo(p:int, q:int, lst:list):
pl = plist(q-p, ps)
while q-p > 1:
x = 10 ** 18
for i in pl:
if (q-p)%i == 0:
x = min(x, i-(p%i))
g = gcd(p+x, q+x)
lst.append((q-p, p, p+x))
p, q = (p+x)//g, (q+x)//g
lst.append((1, p, 9 * 10 ** 18))
# 素数列挙
ps = []
er = [0] * 32001
for i in range(2, 32001):
if er[i] == 0:
ps.append(i)
for j in range(2*i, 32001, i):
er[j] = 1
# ここから本編
Q = int(input())
assert 1 <= Q <= 3000
for _ in range(Q):
lst1 = []
lst2 = []
p1,q1,p2,q2 = map(int,input().split())
assert p1 < q1
assert p2 < q2
assert gcd(p1, q1) == 1
assert gcd(p2, q2) == 1
assert q1 <= 10 ** 9
assert q2 <= 10 ** 9
assert p1 >= 1
assert p2 >= 1
gogo(p1,q1,lst1)
gogo(p2,q2,lst2)
g_begin = dict()
g_end = dict()
for i, st, ed in lst1:
g_begin[i] = st
g_end[i] = ed
ans1 = 0
ans2 = 0
for i, st, ed in lst2:
if i in g_begin.keys():
if max(0, min(ed, g_end[i]) - max(st, g_begin[i])) > 0:
ans1 = max(st, g_begin[i])
ans2 = i + ans1
break
print(ans1, ans2)
shobonvip