結果

問題 No.2182 KODOKU Stone
ユーザー tokusakurai
提出日時 2023-01-08 16:10:04
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 65 ms / 2,000 ms
コード長 4,406 bytes
コンパイル時間 2,203 ms
コンパイル使用メモリ 199,488 KB
最終ジャッジ日時 2025-02-10 01:10:09
ジャッジサーバーID
（参考情報） 		judge3 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 37
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (n); i++)
#define per(i, n) for (int i = (n)-1; i >= 0; i--)
#define rep2(i, l, r) for (int i = (l); i < (r); i++)
#define per2(i, l, r) for (int i = (r)-1; i >= (l); i--)
#define each(e, v) for (auto &e : v)
#define MM << " " <<
#define pb push_back
#define eb emplace_back
#define all(x) begin(x), end(x)
#define rall(x) rbegin(x), rend(x)
#define sz(x) (int)x.size()
using ll = long long;
using pii = pair<int, int>;
using pil = pair<int, ll>;
using pli = pair<ll, int>;
using pll = pair<ll, ll>;
template <typename T>
using minheap = priority_queue<T, vector<T>, greater<T>>;
template <typename T>
using maxheap = priority_queue<T>;
template <typename T>
bool chmax(T &x, const T &y) {
    return (x < y) ? (x = y, true) : false;
}
template <typename T>
bool chmin(T &x, const T &y) {
    return (x > y) ? (x = y, true) : false;
}
template <typename T>
int flg(T x, int i) {
    return (x >> i) & 1;
}
template <typename T>
void print(const vector<T> &v, T x = 0) {
    int n = v.size();
    for (int i = 0; i < n; i++) cout << v[i] + x << (i == n - 1 ? '\n' : ' ');
    if (v.empty()) cout << '\n';
}
template <typename T>
void printn(const vector<T> &v, T x = 0) {
    int n = v.size();
    for (int i = 0; i < n; i++) cout << v[i] + x << '\n';
}
template <typename T>
int lb(const vector<T> &v, T x) {
    return lower_bound(begin(v), end(v), x) - begin(v);
}
template <typename T>
int ub(const vector<T> &v, T x) {
    return upper_bound(begin(v), end(v), x) - begin(v);
}
template <typename T>
void rearrange(vector<T> &v) {
    sort(begin(v), end(v));
    v.erase(unique(begin(v), end(v)), end(v));
}
template <typename T>
vector<int> id_sort(const vector<T> &v, bool greater = false) {
    int n = v.size();
    vector<int> ret(n);
    iota(begin(ret), end(ret), 0);
    sort(begin(ret), end(ret), [&](int i, int j) { return greater ? v[i] > v[j] : v[i] < v[j]; });
    return ret;
}
template <typename S, typename T>
pair<S, T> operator+(const pair<S, T> &p, const pair<S, T> &q) {
    return make_pair(p.first + q.first, p.second + q.second);
}
template <typename S, typename T>
pair<S, T> operator-(const pair<S, T> &p, const pair<S, T> &q) {
    return make_pair(p.first - q.first, p.second - q.second);
}
template <typename S, typename T>
istream &operator>>(istream &is, pair<S, T> &p) {
    S a;
    T b;
    is >> a >> b;
    p = make_pair(a, b);
    return is;
}
template <typename S, typename T>
ostream &operator<<(ostream &os, const pair<S, T> &p) {
    return os << p.first << ' ' << p.second;
}
struct io_setup {
    io_setup() {
        ios_base::sync_with_stdio(false);
        cin.tie(NULL);
        cout << fixed << setprecision(15);
    }
} io_setup;
const int inf = (1 << 30) - 1;
const ll INF = (1LL << 60) - 1;
// const int MOD = 1000000007;
const int MOD = 998244353;
int main() {
    int N;
    cin >> N;
    vector<int> a(N);
    rep(i, N) cin >> a[i];
    vector<vector<int>> c(N);
    rep(i, N) {
        int K;
        cin >> K;
        c[i].resize(K);
        rep(j, K) cin >> c[i][j];
    }
    int MAX = 300000;
    vector<int> cnt2(MAX + 1, 0);
    int l = 0, r = inf; // [l,r)
    while (r - l > 1) {
        fill(all(cnt2), 0);
        int m = (l + r) / 2;
        int cnt1 = 0, ma1 = -inf;
        int ma2 = -inf;
        rep(i, N) {
            int K = sz(c[i]);
            int C = 0;
            each(e, c[i]) {
                if (e >= m) C++;
            }
            if (C == K) {
                cnt1++;
                chmax(ma1, C);
            } else {
                cnt2[C]++;
                chmax(ma2, C);
            }
        }
        bool flag = false;
        int ma3 = ma2;
        per(i, N) {
            if (ma1 >= a[i]) {
                flag = true;
            } else if (ma3 >= a[i]) {
                flag = true;
            } else if (ma2 >= a[i] && cnt1 > 0) {
                flag = true;
            } else if (i == 0 && cnt1 > 0) {
                flag = true;
            }
            if (cnt2[a[i] - 1] > 0) {
                cnt2[a[i] - 1]--;
                while (ma3 >= 0 && cnt2[ma3] == 0) ma3--;
            } else {
                if (cnt1 == 0) break;
                cnt1--;
                if (cnt1 == 0) ma1 = -inf;
            }
        }
        (flag ? l : r) = m;
    }
    cout << l << '\n';
}
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