結果
問題 | No.2194 兄弟の掛け引き |
ユーザー |
|
提出日時 | 2023-01-21 11:57:48 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 3 ms / 1,000 ms |
コード長 | 7,214 bytes |
コンパイル時間 | 2,282 ms |
コンパイル使用メモリ | 216,260 KB |
最終ジャッジ日時 | 2025-02-10 06:07:36 |
ジャッジサーバーID (参考情報) |
judge2 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 14 |
ソースコード
#include <bits/stdc++.h>using namespace std;using ll = long long;//#include <atcoder/modint>//using namespace atcoder;//using mint = modint998244353;# define M_PI 3.14159265358979323846 /* pi */#define watch(x) cout << (#x) << " is " << (x) << endl//#pragma GCC target ("avx2")#pragma GCC optimization ("O3")//const int MOD = (1e9+7);template < typename T = int > ostream& operator << (ostream &out, const vector < T > &v){for (const T &x: v) out << x << ' ';return out;}void printmat(const vector<vector<int>>& mat) {for (auto row : mat) {for (auto elem : row)cout << elem << " ";cout << "\n";}}void printdq(const deque<int>& v) {for (auto elem : v)cout << elem << " ";cout << endl;}void printv(const vector<int>& v) {for (auto elem : v)cout << elem << " ";cout << "\n";}void printvll(const vector<ll>& v) {for (auto elem : v)cout << elem << " ";cout << endl;}void printd(const deque<int>& v) {for (auto elem : v)cout << elem << " ";cout << endl;}void printvp(const vector<pair<int,int>>& vp) {for (auto pr : vp) {cout << pr.first << " " << pr.second;cout << "\n";}}void printvs(const vector<set<int>>& vs) {for (auto row : vs) {for (auto elem : row)cout << elem << ", ";cout << endl;}}void printht(const unordered_map<int, int>& ht) {for (auto elem : ht)cout << elem.first << " : " << elem.second << endl;}void printmp(const map<ll, ll>& ht) {for (auto elem : ht)cout << elem.first << " : " << elem.second << endl;}void printst(const set<int>& st) {for (auto elem : st)cout << elem << " ";cout << endl;}bool isPrime(long long n) {if (n <= 1)return false;if (n <= 3)return true;if (n % 2 == 0 || n % 3 == 0)return false;for (long long i = 5; i * i <= n; i = i + 6)if (n % i == 0 || n % (i + 2) == 0)return false;return true;}map<long long, long long> primeFactors(long long n) {map<long long, long long> ans;while (n % 2 == 0) {ans[2]++;n = n/2;}for (long long i = 3; i*i <= (n); i = i + 2) {while (n % i == 0) {ans[i]++;n = n/i;}}if (n > 2)ans[n]++;return ans;}int find_f(const vector<int>& uf, int i) {while (uf[i]!=i)i = uf[i];return i;}bool union_f(vector<int>& uf, vector<int>& sz, int a, int b) {a = find_f(uf, a);b = find_f(uf, b);//cout << "a, b = " << a << ", " << b << endl;if (a==b) return false;if (sz[a] < sz[b]) {//cout << "sz[a], sz[b] = " << sz[a] << ", " << sz[b] << endl;//cout << "a, b = " << a << ", " << b << endl;swap(a,b);//cout << "a, b = " << a << ", " << b << endl;}sz[a] += sz[b];uf[b] = a;return true;}long long modexp(long long b, long long e, long long M) {if (!e) return 1;b %= M;long long x = modexp(b * b % M, e / 2, M);if (e % 2) {return b * x % M;} else {return x;}}ll gcdExtended(ll a, ll b, ll* x, ll* y) {if (a == 0) {*x = 0, *y = 1;return b;}ll x1, y1;ll gcd = gcdExtended(b % a, a, &x1, &y1);*x = y1 - (b / a) * x1;*y = x1;return gcd;}ll modInverse(ll a, ll m) {ll x, y, res=-1;ll g = gcdExtended(a, m, &x, &y);if (g != 1) {//cout << "Inverse doesn't exist";res = -1;} else {// m is added to handle negative xres = (x % m + m) % m;}return res;}int lenOfLIS(vector<int>& v) {int n = v.size(), len = 0;vector<int> dp(n,0);for (int num : v) {int i = lower_bound(dp.begin(), dp.begin()+len, num) - dp.begin();dp[i] = num;if (i == len) {len++;}}return len;}const int MOD = 1e9 + 7;struct mi {int v; explicit operator int() const { return v; }mi() { v = 0; }mi(long long _v) : v(_v % MOD) { v += (v < 0) * MOD; }};mi& operator+=(mi& a, mi b) {if ((a.v += b.v) >= MOD) a.v -= MOD;return a;}mi& operator-=(mi& a, mi b) {if ((a.v -= b.v) < 0) a.v += MOD;return a;}mi operator+(mi a, mi b) { return a += b; }mi operator-(mi a, mi b) { return a -= b; }mi operator*(mi a, mi b) { return mi((long long) a.v * b.v); }mi& operator*=(mi& a, mi b) { return a = a * b; }mi pow(mi a, long long p) {assert(p >= 0);return p == 0 ? 1 : pow(a * a, p / 2) * (p & 1 ? a : 1);}mi inv(mi a) { assert(a.v != 0); return pow(a, MOD - 2); }mi operator/(mi a, mi b) { return a * inv(b); }// Returns sum of arr[0..index]. This function assumes// that the array is preprocessed and partial sums of// array elements are stored in BITree[].int getSum(int BITree[], int index){int sum = 0; // Initialize result// index in BITree[] is 1 more than the index in arr[]index = index + 1;// Traverse ancestors of BITree[index]while (index>0){// Add current element of BITree to sumsum += BITree[index];// Move index to parent node in getSum Viewindex -= index & (-index);}return sum;}// Updates a node in Binary Index Tree (BITree) at given index// in BITree. The given value 'val' is added to BITree[i] and// all of its ancestors in tree.void updateBIT(int BITree[], int n, int index, int val){// index in BITree[] is 1 more than the index in arr[]index = index + 1;// Traverse all ancestors and add 'val'while (index <= n){// Add 'val' to current node of BI TreeBITree[index] += val;// Update index to that of parent in update Viewindex += index & (-index);}}// Constructs and returns a Binary Indexed Tree for given// array of size n.int *constructBITree(vector<int>& arr, int n){// Create and initialize BITree[] as 0int *BITree = new int[n+1];for (int i=1; i<=n; i++)BITree[i] = 0;// Store the actual values in BITree[] using update()for (int i=0; i<n; i++)updateBIT(BITree, n, i, arr[i]);// Uncomment below lines to see contents of BITree[]//for (int i=1; i<=n; i++)// cout << BITree[i] << " ";return BITree;}int main() {ios_base::sync_with_stdio(false);cin.tie(NULL);int T=1, caseIdx=0;//cin >> T;while (T--) {//caseIdx++;ll a, b, c;cin >> a >> b >> c;vector<int> ans;for (int i=1; i<=1e6; i++) {ll x = a*i;if (x-b<=0);elsex -= b;if (x==c)ans.push_back(i);}if (ans.size()) {for (auto elem : ans)cout << elem << "\n";}elsecout << - 1 << endl;//cout << fixed << setprecision(9);//cout << ans << "\n";//cout << "Case #" << caseIdx << ": " << ans << "\n";}}