結果

問題 No.2197 Same Dish
ユーザー Y68170842Y68170842
提出日時 2023-01-21 16:05:30
言語 C++17
(gcc 13.2.0 + boost 1.83.0)
結果
AC  
実行時間 83 ms / 2,000 ms
コード長 5,405 bytes
コンパイル時間 4,479 ms
コンパイル使用メモリ 268,752 KB
実行使用メモリ 8,088 KB
最終ジャッジ日時 2023-09-06 04:58:47
合計ジャッジ時間 6,578 ms
ジャッジサーバーID
(参考情報)
judge14 / judge15
このコードへのチャレンジ(β)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 1 ms
4,376 KB
testcase_01 AC 1 ms
4,376 KB
testcase_02 AC 2 ms
4,376 KB
testcase_03 AC 2 ms
4,376 KB
testcase_04 AC 1 ms
4,380 KB
testcase_05 AC 1 ms
4,376 KB
testcase_06 AC 1 ms
4,380 KB
testcase_07 AC 2 ms
4,376 KB
testcase_08 AC 1 ms
4,376 KB
testcase_09 AC 2 ms
4,380 KB
testcase_10 AC 1 ms
4,380 KB
testcase_11 AC 1 ms
4,376 KB
testcase_12 AC 2 ms
4,376 KB
testcase_13 AC 12 ms
4,376 KB
testcase_14 AC 74 ms
6,908 KB
testcase_15 AC 82 ms
6,924 KB
testcase_16 AC 54 ms
5,776 KB
testcase_17 AC 48 ms
5,380 KB
testcase_18 AC 83 ms
7,244 KB
testcase_19 AC 83 ms
6,980 KB
testcase_20 AC 83 ms
7,100 KB
testcase_21 AC 75 ms
8,088 KB
testcase_22 AC 70 ms
6,800 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#if !__INCLUDE_LEVEL__

#include __FILE__

template<int MOD> struct Fp {
		long long val;
		constexpr Fp(long long v = 0) noexcept : val(v % MOD) {
				if (val < 0) val += MOD;
		}
		constexpr int getmod() { return MOD; }
		constexpr Fp operator - () const noexcept {
				return val ? MOD - val : 0;
		}
		constexpr Fp operator + (const Fp& r) const noexcept { return Fp(*this) += r; }
		constexpr Fp operator - (const Fp& r) const noexcept { return Fp(*this) -= r; }
		constexpr Fp operator * (const Fp& r) const noexcept { return Fp(*this) *= r; }
		constexpr Fp operator / (const Fp& r) const noexcept { return Fp(*this) /= r; }
		constexpr Fp& operator += (const Fp& r) noexcept {
				val += r.val;
				if (val >= MOD) val -= MOD;
				return *this;
		}
		constexpr Fp& operator -= (const Fp& r) noexcept {
				val -= r.val;
				if (val < 0) val += MOD;
				return *this;
		}
		constexpr Fp& operator *= (const Fp& r) noexcept {
				val = val * r.val % MOD;
				return *this;
		}
		constexpr Fp& operator /= (const Fp& r) noexcept {
				long long a = r.val, b = MOD, u = 1, v = 0;
				while (b) {
						long long t = a / b;
						a -= t * b; swap(a, b);
						u -= t * v; swap(u, v);
				}
				val = val * u % MOD;
				if (val < 0) val += MOD;
				return *this;
		}
		constexpr bool operator == (const Fp& r) const noexcept {
				return this->val == r.val;
		}
		constexpr bool operator != (const Fp& r) const noexcept {
				return this->val != r.val;
		}
		friend constexpr ostream& operator << (ostream &os, const Fp<MOD>& x) noexcept {
				return os << x.val;
		}
		friend constexpr Fp<MOD> modpow(const Fp<MOD> &a, long long n) noexcept {
				if (n == 0) return 1;
				auto t = modpow(a, n / 2);
				t = t * t;
				if (n & 1) t = t * a;
				return t;
		}
};
// const int MOD = 1000000007;
const int MOD = 998244353;
using mint = Fp<MOD>;




// (a**n)%mod
// const int MOD = 1000000007;
// const int MOD = 998244353;
ll modpow(ll a,ll n){
		ll res=1;
		while(n>0){
				if(n&1){
						res=res*a%MOD;
				}
				a=a*a%MOD;
				n>>=1;
		}
		return res;
}

struct Solver {
void solve() {
	int n,k;cin>>n>>k;
	V<int> l(n),r(n);
	V<P> lr;
	rep(i,n){
		cin>>l[i]>>r[i];
		lr.emplace_back(l[i],r[i]);
	}
	sort(all(lr));
	mint ans=modpow(k,n);
	mint now=1;
	
	min_heap<int> pq;
	rep(i,n){
		while(pq.size()!=0&&pq.top()<=lr[i].first)pq.pop();
		now*=(k-pq.size());
		pq.emplace(lr[i].second);
	}
	cout<<ans-now<<endl;
}};

signed main() {
	int ts = 1;
	// scanf("%lld",&ts);
	rep(ti,ts) {
		Solver solver;
		solver.solve();
	}
	return 0;
}

#else

#include <bits/stdc++.h>
#include <atcoder/all>
using namespace atcoder;
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
// using namespace __gnu_pbds;

using namespace std;

#define int ll

using ll=long long;
using ld = long double;
using uint = unsigned;
using ull = unsigned long long;
using P=pair<int,int>;
using TP=tuple<int,int,int>;
template <class T> using V = vector<T>;
template <class T> using max_heap = priority_queue<T>;
template <class T> using min_heap = priority_queue<T, vector<T>, greater<>>;

#define FOR1(a) for (ll _ = 0; _ < ll(a); ++_)
#define FOR2(i, a) for (ll i = 0; i < ll(a); ++i)
#define FOR3(i, a, b) for (ll i = a; i < ll(b); ++i)
#define FOR4(i, a, b, c) for (ll i = a; i < ll(b); i += (c))
#define FOR1_R(a) for (ll i = (a)-1; i >= ll(0); --i)
#define FOR2_R(i, a) for (ll i = (a)-1; i >= ll(0); --i)
#define FOR3_R(i, a, b) for (ll i = (b)-1; i >= ll(a); --i)
#define FOR4_R(i, a, b, c) for (ll i = (b)-1; i >= ll(a); i -= (c))
#define overload4(a, b, c, d, e, ...) e
#define rep(...) overload4(__VA_ARGS__, FOR4, FOR3, FOR2, FOR1)(__VA_ARGS__)
#define rrep(...) overload4(__VA_ARGS__, FOR4_R, FOR3_R, FOR2_R, FOR1_R)(__VA_ARGS__)
#define fore(i,a) for(auto &i:a)

#define all(x) x.begin(),x.end() 
#define sz(x) ((int)(x).size())
#define bp(x) (__builtin_popcountll((long long)(x)))
#define elif else if
#define mpa make_pair
#define bit(n) (1LL<<(n))
#define LB(c, x) distance((c).begin(), lower_bound(all(c), (x)))
#define UB(c, x) distance((c).begin(), upper_bound(all(c), (x)))
#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end())

template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
template<typename T>string join(const T&v,const string& d=""){stringstream s;rep(i,sz(v))(i?s<<d:s)<<v[i];return s.str();}
template<typename T>ostream& operator<<(ostream&o,const vector<T>&v){if(sz(v))o<<join(v," ");return o;}
template<typename T1,typename T2>ostream& operator<<(ostream&o,const pair<T1,T2>&v){return o<<v.first<<","<<v.second;}
template<typename T1,typename T2>bool mins(T1& x,const T2&y){if(x>y){x=y;return true;}else return false;}
template<typename T1,typename T2>bool maxs(T1& x,const T2&y){if(x<y){x=y;return true;}else return false;}
template<typename Tx, typename Ty>Tx dup(Tx x, Ty y){return (x+y-1)/y;}
template<typename T>ll suma(const vector<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;}
template<typename T>ll suma(const V<V<T>>&a){ll res(0);for(auto&&x:a)res+=suma(x);return res;}
template<typename T>void uni(T& a){sort(rng(a));a.erase(unique(rng(a)),a.end());}
template<typename T>void prepend(vector<T>&a,const T&x){a.insert(a.begin(),x);}

const int INF = 1001001001;
const ll INFL = 3e18;
const int MAX = 2e6+5;


#endif

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