結果
| 問題 | No.2202 贅沢てりたまチキン |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-02-03 21:39:08 |
| 言語 | C++23 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 220 ms / 2,000 ms |
| コード長 | 4,413 bytes |
| コンパイル時間 | 3,089 ms |
| コンパイル使用メモリ | 254,816 KB |
| 実行使用メモリ | 16,572 KB |
| 最終ジャッジ日時 | 2024-07-02 19:28:28 |
| 合計ジャッジ時間 | 6,075 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 28 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
using ull = uint64_t;
using ll = int64_t;
using vi = vector<int>;
using vll = vector<ll>;
using vs = vector<string>;
using ld = long double;
using P = pair<ll,ll>;
using G = vector<vector<int>>;
#define LO(...) (void)0
#define debug(x) (void)0
#define reps(i,a,n) for(ll i##_len = (ll)(n), i = (a); i < i##_len; ++i)
#define rep(i,n) reps(i,0,(n))
#define rrep(i,n) reps(i,1,(n)+1)
#define repd(i,n) for(ll i=(n)-1;i>=0;i--)
#define rrepd(i,n) for(ll i=(n);i>=1;i--)
#define inp(i) ll i; cin >> i;
#define inps(s) string s; cin >> s;
#define inpp(p) cin >> (p).first >> (p).second
#define inpv(v,N) vll v(N);rep(i,N)cin>>v[i];
#define inpvs(v,N) vs v(N);rep(i,N)cin>>v[i];
#define all(v) begin(v),end(v)
#define Yes cout<<"Yes\n"
#define No cout<<"No\n"
#define allok(i,N,pred) [&]()->bool{bool allok_=1;rep(i,N)if(!(pred))allok_=0;return allok_;}()
#define anyok(i,N,pred) [&]()->bool{bool anyok_=0;rep(i,N)if(pred)anyok_=1;return anyok_;}()
void YESNO(bool b){cout<<(b?"YES\n":"NO\n");}void yesno(bool b){cout<<(b?"yes\n":"no\n");}void YesNo(bool b){cout<<(b?"Yes\n":"No\n");}
#define SP cout << " "
#define ENDL cout << "\n"
#define setfp cout << fixed << setprecision(16)
template<typename C>void ou(const C&v){cout<<v;}
template<typename C>void ous(const C&v){cout<<v<<" ";}
template<typename C>void oul(const C&v){cout<<v<<"\n";}
template<typename C>void ouv(const C &v){for(auto &&e:v){cout << e;if(&e != &v.back()) cout << ' ';}cout << "\n";}
template<typename C>void ouvadd(const C &v){for(auto &&e:v){cout << e+1;if(&e != &v.back()) cout << ' ';}cout << "\n";}
template<typename T>bool chmax(T &a, const T &b){return a<b?(a=b,1):0;}
template<typename T>bool chmin(T &a, const T &b){return b<a?(a=b,1):0;}
template<typename T>void so(T &a){sort(begin(a),end(a));}
template<typename T,typename C>void so(T &a,C c){sort(begin(a),end(a),c);}
template<typename T>void rso(T &a){sort(rbegin(a),rend(a));}
template<typename T,typename C>void rso(T &a,C c){sort(rbegin(a),rend(a),c);}
constexpr ll INF = 1e18;
#ifndef ATCODER_DSU_HPP
#define ATCODER_DSU_HPP 1
#include <algorithm>
#include <cassert>
#include <vector>
namespace atcoder {
// Implement (union by size) + (path compression)
// Reference:
// Zvi Galil and Giuseppe F. Italiano,
// Data structures and algorithms for disjoint set union problems
struct dsu {
public:
dsu() : _n(0) {}
explicit dsu(int n) : _n(n), parent_or_size(n, -1) {}
int merge(int a, int b) {
assert(0 <= a && a < _n);
assert(0 <= b && b < _n);
int x = leader(a), y = leader(b);
if (x == y) return x;
if (-parent_or_size[x] < -parent_or_size[y]) std::swap(x, y);
parent_or_size[x] += parent_or_size[y];
parent_or_size[y] = x;
return x;
}
bool same(int a, int b) {
assert(0 <= a && a < _n);
assert(0 <= b && b < _n);
return leader(a) == leader(b);
}
int leader(int a) {
assert(0 <= a && a < _n);
if (parent_or_size[a] < 0) return a;
return parent_or_size[a] = leader(parent_or_size[a]);
}
int size(int a) {
assert(0 <= a && a < _n);
return -parent_or_size[leader(a)];
}
std::vector<std::vector<int>> groups() {
std::vector<int> leader_buf(_n), group_size(_n);
for (int i = 0; i < _n; i++) {
leader_buf[i] = leader(i);
group_size[leader_buf[i]]++;
}
std::vector<std::vector<int>> result(_n);
for (int i = 0; i < _n; i++) {
result[i].reserve(group_size[i]);
}
for (int i = 0; i < _n; i++) {
result[leader_buf[i]].push_back(i);
}
result.erase(
std::remove_if(result.begin(), result.end(),
[&](const std::vector<int>& v) { return v.empty(); }),
result.end());
return result;
}
private:
int _n;
// root node: -1 * component size
// otherwise: parent
std::vector<int> parent_or_size;
};
} // namespace atcoder
#endif // ATCODER_DSU_HPP
int main() {
inp(N);
inp(M);
G g;
g.resize(N);
atcoder::dsu ds(N*2);
rep(i,M){
inp(a);
inp(b);
a--,b--;
g[a].push_back(b);
g[b].push_back(a);
ds.merge(a, b+N);
ds.merge(a+N, b);
}
YesNo(allok(i,N,ds.same(i,i+N)));
}