結果
問題 | No.2212 One XOR Matrix |
ユーザー | fastmath |
提出日時 | 2023-02-10 21:59:01 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 58 ms / 2,000 ms |
コード長 | 3,834 bytes |
コンパイル時間 | 1,394 ms |
コンパイル使用メモリ | 147,704 KB |
実行使用メモリ | 11,536 KB |
最終ジャッジ日時 | 2024-07-07 16:14:03 |
合計ジャッジ時間 | 2,981 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,812 KB |
testcase_01 | AC | 2 ms
6,940 KB |
testcase_02 | AC | 2 ms
6,940 KB |
testcase_03 | AC | 2 ms
6,940 KB |
testcase_04 | AC | 2 ms
6,940 KB |
testcase_05 | AC | 2 ms
6,940 KB |
testcase_06 | AC | 2 ms
6,940 KB |
testcase_07 | AC | 5 ms
6,940 KB |
testcase_08 | AC | 18 ms
8,712 KB |
testcase_09 | AC | 58 ms
11,536 KB |
ソースコード
#include <iostream> #include <cstdio> #include <cstdlib> #include <algorithm> #include <cmath> #include <vector> #include <set> #include <map> #include <unordered_set> #include <unordered_map> #include <queue> #include <ctime> #include <cassert> #include <complex> #include <string> #include <cstring> #include <chrono> #include <random> #include <bitset> #include <fstream> #include <array> #include <functional> #include <stack> #include <memory> using namespace std; #define int long long #define ii pair <int, int> #define app push_back #define all(a) a.begin(), a.end() #define bp __builtin_popcountll #define ll long long #define mp make_pair #define x first #define y second #define Time (double)clock()/CLOCKS_PER_SEC #ifdef LOCAL #define debug(x) std::cerr << #x << ": " << x << '\n'; #define debug2(x, y) std::cerr << #x << ", " << #y << ": " << x << ", " << y << '\n'; #define debug3(x, y, z) std::cerr << #x << ", " << #y << ", " << #z << ": " << x << ", " << y << ", " << z << '\n'; #else #define debug(x) #define debug2(x, y) #define debug3(x, y, z) #endif #define FORI(i,a,b) for (int i = (a); i < (b); ++i) #define FOR(i,a) FORI(i,0,a) #define ROFI(i,a,b) for (int i = (b)-1; i >= (a); --i) #define ROF(i,a) ROFI(i,0,a) #define rep(a) FOR(_,a) #define each(a,x) for (auto& a: x) #define FORN(i, n) FORI(i, 1, n + 1) using vi = vector<int>; template <typename T> std::istream& operator >>(std::istream& input, std::pair <T, T> & data) { input >> data.x >> data.y; return input; } template <typename T> std::istream& operator >>(std::istream& input, std::vector<T>& data) { for (T& x : data) input >> x; return input; } template <typename T> std::ostream& operator <<(std::ostream& output, const pair <T, T> & data) { output << "(" << data.x << "," << data.y << ")"; return output; } template <typename T> std::ostream& operator <<(std::ostream& output, const std::vector<T>& data) { for (const T& x : data) output << x << " "; return output; } ll div_up(ll a, ll b) { return a/b+((a^b)>0&&a%b); } // divide a by b rounded up ll div_down(ll a, ll b) { return a/b-((a^b)<0&&a%b); } // divide a by b rounded down ll math_mod(ll a, ll b) { return a - b * div_down(a, b); } #define tcT template<class T #define tcTU tcT, class U tcT> using V = vector<T>; tcT> bool ckmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; } // set a = min(a,b) tcT> bool ckmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; } ll gcd(ll a, ll b) { while (b) { tie(a, b) = mp(b, a % b); } return a; } int Bit(int mask, int bit) { return (mask >> bit) & 1; } V <V <vi> > t(2, V <vi> (4, vi(4))); int a[1 << 10][1<<10]; void solve0(int x, int y, int p, int s, int m) { if (p == 2) { FOR (i, 1 << p) { FOR (j, 1 << p) { a[x+i][y+j]=t[0][i][j]+s; } } return; } int h = 1 << (p - 1); solve0(x,y,p-1,s,m/4); solve0(x,y+h,p-1,s+m/2,m/4); solve0(x+h,y,p-1,s+m,m/4); solve0(x+h,y+h,p-1,s+m+m/2,m/4); } void solve1(int x, int y, int p, int s, int m) { if (p == 2) { FOR (i, 1 << p) { FOR (j, 1 << p) { a[x+i][y+j]=t[1][i][j]+s; } } return; } int h = 1 << (p - 1); solve1(x,y,p-1,s,m/4); solve0(x,y+h,p-1,s+m/2,m/4); solve0(x+h,y,p-1,s+m,m/4); solve1(x+h,y+h,p-1,s+m+m/2,m/4); } signed main() { #ifdef LOCAL #else #define endl '\n' ios_base::sync_with_stdio(0); cin.tie(0); #endif int pt = 0; FOR (i, 4) { FOR(j,4) { t[0][i][j] = pt++; } } t[1] = {{7, 14, 0, 8}, {4, 12, 2, 11}, {15, 9, 6, 1}, {13, 10, 5, 3}}; int n; cin >> n; if (n == 1) { cout << -1 << endl; exit(0); } int m = 1 << (2 * n - 1); solve1(0,0,n,0,m); FOR(i,1<<n){ FOR(j,1<<n) { cout << a[i][j] << ' '; } cout<<endl; } int x= 0; FOR (i, 1<<n) { x ^= a[i][5]; } debug(x); }