結果

問題 No.2210 equence Squence Seuence
ユーザー k1suxuk1suxu
提出日時 2023-02-10 23:25:20
言語 C++23
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 522 ms / 2,000 ms
コード長 5,467 bytes
コンパイル時間 3,541 ms
コンパイル使用メモリ 260,304 KB
実行使用メモリ 8,052 KB
最終ジャッジ日時 2024-07-07 17:22:34
合計ジャッジ時間 8,708 ms
ジャッジサーバーID
(参考情報)
judge1 / judge5
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,812 KB
testcase_01 AC 2 ms
6,940 KB
testcase_02 AC 1 ms
6,944 KB
testcase_03 AC 71 ms
6,940 KB
testcase_04 AC 90 ms
6,944 KB
testcase_05 AC 133 ms
6,944 KB
testcase_06 AC 121 ms
6,940 KB
testcase_07 AC 336 ms
6,940 KB
testcase_08 AC 2 ms
6,940 KB
testcase_09 AC 2 ms
6,940 KB
testcase_10 AC 1 ms
6,940 KB
testcase_11 AC 1 ms
6,940 KB
testcase_12 AC 2 ms
6,940 KB
testcase_13 AC 522 ms
7,552 KB
testcase_14 AC 437 ms
7,552 KB
testcase_15 AC 405 ms
7,168 KB
testcase_16 AC 413 ms
7,168 KB
testcase_17 AC 430 ms
7,424 KB
testcase_18 AC 2 ms
6,940 KB
testcase_19 AC 2 ms
6,940 KB
testcase_20 AC 2 ms
6,944 KB
testcase_21 AC 2 ms
6,944 KB
testcase_22 AC 1 ms
6,940 KB
testcase_23 AC 275 ms
7,336 KB
testcase_24 AC 179 ms
6,940 KB
testcase_25 AC 220 ms
6,944 KB
testcase_26 AC 311 ms
8,052 KB
testcase_27 AC 73 ms
6,944 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

// #pragma GCC target("avx")
// #pragma GCC optimize("O3")
// #pragma GCC optimize("unroll-loops")

#include <bits/stdc++.h>
using namespace std;

#define rep(i,n) for(int i = 0; i < (int)n; i++)
#define FOR(n) for(int i = 0; i < (int)n; i++)
#define repi(i,a,b) for(int i = (int)a; i < (int)b; i++)
#define all(x) x.begin(),x.end()
//#define mp make_pair
#define vi vector<int>
#define vvi vector<vi>
#define vvvi vector<vvi>
#define vvvvi vector<vvvi>
#define pii pair<int,int>
#define vpii vector<pair<int,int>>

template<typename T>
void chmax(T &a, const T &b) {a = (a > b? a : b);}
template<typename T>
void chmin(T &a, const T &b) {a = (a < b? a : b);}

using ll = long long;
using ld = long double;

const ll INF = numeric_limits<long long>::max() / 2;
const ld pi = 3.1415926535897932384626433832795028;
const ll mod = 998244353;
int dx[] = {-1, 0, 1, 0, -1, -1, 1, 1};
int dy[] = {0, -1, 0, 1, -1, 1, -1, 1};

using ull = unsigned long long;

struct Rolling_Hash {
    static const unsigned long long rh_mod = (1ull << 61ull) - 1;
    vector<unsigned long long> power;
    unsigned long long base;

    static inline unsigned long long add(unsigned long long a, unsigned long long b) {
        if((a += b) >= rh_mod) a -= rh_mod;
        return a;
    }

    static inline unsigned long long mul(unsigned long long a, unsigned long long b) {
        __uint128_t c = (__uint128_t) a * b;
        return add(c >> 61, c & rh_mod);
    }

    static inline unsigned long long generate_base() {
        mt19937_64 mt(chrono::steady_clock::now().time_since_epoch().count());
        uniform_int_distribution< unsigned long long > rand(1, Rolling_Hash::rh_mod - 1);
        return rand(mt);
    }

    inline void expand(size_t sz) {
        if((int)power.size() < (int)sz + 1) {
        int pre_sz = (int) power.size();
        power.resize(sz + 1);
        for(int i = pre_sz - 1; i < (int)sz; i++) {
            power[i + 1] = mul(power[i], base);
        }
        }
    }

    Rolling_Hash() {
        base = generate_base();
        power = {1};
    }

    vector<unsigned long long> make_hash(const string &s) const {
        int sz = s.size();
        vector<unsigned long long> hashed(sz + 1);
        for(int i = 0; i < (int)sz; i++) {
            hashed[i + 1] = add(mul(hashed[i], base), s[i]);
        }
        return hashed;
    }

    template<typename T>
    vector<unsigned long long> make_hash(const vector<T> &s) const {
        int sz = s.size();
        vector<unsigned long long> hashed(sz + 1);
        for(int i = 0; i < (int)sz; i++) {
        hashed[i + 1] = add(mul(hashed[i], base), s[i]);
        }
        return hashed;
    }
    vector<unsigned long long> make_hash_string(const string &s) const {
        vector<char> ss;
        for(char c : s) ss.push_back(c);
        return make_hash<char>(ss);
    }

    unsigned long long query(const vector<unsigned long long> &s, int l, int r) {
        expand(r - l);
        return add(s[r], rh_mod - mul(s[l], power[r - l]));
    }

    unsigned long long combine(unsigned long long h1, unsigned long long h2, size_t h2len) {
        expand(h2len);
        return add(mul(h1, power[h2len]), h2);
    }

    int lcp(const vector<unsigned long long> &a, int l1, int r1, const vector<unsigned long long> &b, int l2, int r2) {
        int len = min(r1 - l1, r2 - l2);
        int low = 0, high = len + 1;
        while(high - low > 1) {
            int mid = (low + high) / 2;
            if(query(a, l1, l1 + mid) == query(b, l2, l2 + mid)) low = mid;
            else high = mid;
        }
        return low;
    }

    bool issame(const vector<unsigned long long> &a, int l1, int r1, const vector<unsigned long long> &b, int l2, int r2) {
        assert(r1-l1 == r2-l2);
        return query(a, l1, r1) == query(b, l2, r2);
    }
    bool issame(const vector<unsigned long long> &a, int l1, const vector<unsigned long long> &b, int l2, int len) {
        return issame(a, l1, l1+len, b, l2, l2+len);
    }

    template<typename T>
    int greater(const vector<T> &raw, const vector<unsigned long long> &hash, int l1, int r1, int l2, int r2) {
        // repi(i, l1, r1) cout << raw[i]; cout << " ";
        // repi(i, l2, r2) cout << raw[i]; cout << "\n";
        int LCP = lcp(hash, l1, r1, hash, l2, r2);
        if(LCP == min(r1 - l1, r2 - l2)) return 2;//same
        //0: l1の方がでかい, 1: l2の方がでかい
        return raw[l1+LCP] < raw[l2+LCP];
    }
};
//make function that can combine two hash tables
//combine_hashes(vull l, vull r) -> return vull l+r (hash addition)

void solve() {
    Rolling_Hash rh;
    int n, k;
    cin >> n >> k;
    vi s(n);
    FOR(n) cin >> s[i];
    vector<ull> hash = rh.make_hash<int>(s);

    vector<int> ans(n);
    iota(all(ans), 0);
    sort(all(ans), [&](int i, int j) {
        int now;
        // cout << i << " " << j << endl;
        if(i < j) {
            now = rh.greater<int>(s, hash, i+1, j+1, i, j);
        }else {
            now = rh.greater<int>(s, hash, j, i, j+1, i+1);
        }
        // cout << now << endl;
        if(now == 2) {
            return false;
        }
        if(now == 1) {
            return true;
        }
        if(now == 0) {
            return false;
        }
        assert(false);
        return false;
    });

    FOR(n) if(i != ans[k-1]) cout << s[i] << " "; cout << "\n";
}

signed main() {
    cin.tie(nullptr);
    ios::sync_with_stdio(false);
    solve();
    return 0;
}
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