結果
| 問題 | No.2215 Slide Subset Sum |
| ユーザー |
👑  p-adic
|
| 提出日時 | 2023-02-11 00:37:27 |
| 言語 | C++17(clang) (17.0.6 + boost 1.83.0) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 7,845 bytes |
| コンパイル時間 | 7,581 ms |
| コンパイル使用メモリ | 184,788 KB |
| 実行使用メモリ | 10,880 KB |
| 最終ジャッジ日時 | 2024-07-07 18:12:17 |
| 合計ジャッジ時間 | 13,500 ms |
|
ジャッジサーバーID （参考情報） |
judge1 / judge3 |
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テストケース
テストケース表示| 入力 | 結果 | 実行時間 実行使用メモリ |
|---|---|---|
| testcase_00 | AC | 506 ms
8,960 KB |
| testcase_01 | AC | 195 ms
5,248 KB |
| testcase_02 | TLE | - |
| testcase_03 | -- | - |
| testcase_04 | -- | - |
| testcase_05 | -- | - |
| testcase_06 | -- | - |
| testcase_07 | -- | - |
| testcase_08 | -- | - |
| testcase_09 | -- | - |
| testcase_10 | -- | - |
| testcase_11 | -- | - |
| testcase_12 | -- | - |
| testcase_13 | -- | - |
| testcase_14 | -- | - |
| testcase_15 | -- | - |
| testcase_16 | -- | - |
| testcase_17 | -- | - |
| testcase_18 | -- | - |
| testcase_19 | -- | - |
| testcase_20 | -- | - |
| testcase_21 | -- | - |
| testcase_22 | -- | - |
| testcase_23 | -- | - |
| testcase_24 | -- | - |
| testcase_25 | -- | - |
| testcase_26 | -- | - |
| testcase_27 | -- | - |
| testcase_28 | -- | - |
| testcase_29 | -- | - |
| testcase_30 | -- | - |
| testcase_31 | -- | - |
| testcase_32 | -- | - |
| testcase_33 | -- | - |
| testcase_34 | -- | - |
| testcase_35 | -- | - |
| testcase_36 | -- | - |
| testcase_37 | -- | - |
| testcase_38 | -- | - |
| testcase_39 | -- | - |
| testcase_40 | -- | - |
| testcase_41 | -- | - |
| testcase_42 | -- | - |
| testcase_43 | -- | - |
| testcase_44 | -- | - |
| testcase_45 | -- | - |
| testcase_46 | -- | - |
コンパイルメッセージ
main.cpp:167:18: warning: unqualified call to 'std::move' [-Wunqualified-std-cast-call]
167 | v.push_back( move( f ) );
| ^
| std::
1 warning generated.
ソースコード
// #pragma GCC optimize ( "O3" )
// #pragma GCC optimize( "unroll-loops" )
// #pragma GCC target ( "sse4.2,fma,avx2,popcnt,lzcnt,bmi2" )
#include <bits/stdc++.h>
using namespace std;
using uint = unsigned int;
using ll = long long;
#define ATT __attribute__( ( target( "sse4.2,fma,avx2,popcnt,lzcnt,bmi2" ) ) )
#define TYPE_OF( VAR ) remove_const<remove_reference<decltype( VAR )>::type >::type
#define UNTIE ios_base::sync_with_stdio( false ); cin.tie( nullptr )
#define CEXPR( LL , BOUND , VALUE ) constexpr LL BOUND = VALUE
#define CIN( LL , A ) LL A; cin >> A
#define ASSERT( A , MIN , MAX ) assert( ( MIN ) <= A && A <= ( MAX ) )
#define CIN_ASSERT( A , MIN , MAX ) CIN( TYPE_OF( MAX ) , A ); ASSERT( A , MIN , MAX )
#define GETLINE( A ) string A; getline( cin , A )
#define GETLINE_SEPARATE( A , SEPARATOR ) string A; getline( cin , A , SEPARATOR )
#define FOR( VAR , INITIAL , FINAL_PLUS_ONE ) for( TYPE_OF( FINAL_PLUS_ONE ) VAR = INITIAL ; VAR < FINAL_PLUS_ONE ; VAR ++ )
#define FOREQ( VAR , INITIAL , FINAL ) for( TYPE_OF( FINAL ) VAR = INITIAL ; VAR <= FINAL ; VAR ++ )
#define FOREQINV( VAR , INITIAL , FINAL ) for( TYPE_OF( INITIAL ) VAR = INITIAL ; VAR >= FINAL ; VAR -- )
#define FOR_ITR( ARRAY , ITR , END ) for( auto ITR = ARRAY .begin() , END = ARRAY .end() ; ITR != END ; ITR ++ )
#define REPEAT( HOW_MANY_TIMES ) FOR( VARIABLE_FOR_REPEAT , 0 , HOW_MANY_TIMES )
#define QUIT return 0
#define COUT( ANSWER ) cout << ( ANSWER ) << "\n";
#define RETURN( ANSWER ) COUT( ANSWER ); QUIT
#define DOUBLE( PRECISION , ANSWER ) cout << fixed << setprecision( PRECISION ) << ( ANSWER ) << "\n"; QUIT
#define POWER( ANSWER , ARGUMENT , EXPONENT ) \
TYPE_OF( ARGUMENT ) ANSWER{ 1 }; \
{ \
TYPE_OF( ARGUMENT ) ARGUMENT_FOR_SQUARE_FOR_POWER = ( ARGUMENT ); \
TYPE_OF( EXPONENT ) EXPONENT_FOR_SQUARE_FOR_POWER = ( EXPONENT ); \
while( EXPONENT_FOR_SQUARE_FOR_POWER != 0 ){ \
if( EXPONENT_FOR_SQUARE_FOR_POWER % 2 == 1 ){ \
ANSWER *= ARGUMENT_FOR_SQUARE_FOR_POWER; \
} \
ARGUMENT_FOR_SQUARE_FOR_POWER *= ARGUMENT_FOR_SQUARE_FOR_POWER; \
EXPONENT_FOR_SQUARE_FOR_POWER /= 2; \
} \
} \
#define POWER_MOD( ANSWER , ARGUMENT , EXPONENT , MODULO ) \
TYPE_OF( ARGUMENT ) ANSWER{ 1 }; \
{ \
TYPE_OF( ARGUMENT ) ARGUMENT_FOR_SQUARE_FOR_POWER = ( MODULO + ( ( ARGUMENT ) % MODULO ) ) % MODULO; \
TYPE_OF( EXPONENT ) EXPONENT_FOR_SQUARE_FOR_POWER = ( EXPONENT ); \
while( EXPONENT_FOR_SQUARE_FOR_POWER != 0 ){ \
if( EXPONENT_FOR_SQUARE_FOR_POWER % 2 == 1 ){ \
ANSWER = ( ANSWER * ARGUMENT_FOR_SQUARE_FOR_POWER ) % MODULO; \
} \
ARGUMENT_FOR_SQUARE_FOR_POWER = ( ARGUMENT_FOR_SQUARE_FOR_POWER * ARGUMENT_FOR_SQUARE_FOR_POWER ) % MODULO; \
EXPONENT_FOR_SQUARE_FOR_POWER /= 2; \
} \
} \
#define FACTORIAL_MOD( ANSWER , ANSWER_INV , INVERSE , MAX_I , LENGTH , MODULO ) \
static ll ANSWER[LENGTH]; \
static ll ANSWER_INV[LENGTH]; \
static ll INVERSE[LENGTH]; \
{ \
ll VARIABLE_FOR_PRODUCT_FOR_FACTORIAL = 1; \
ANSWER[0] = VARIABLE_FOR_PRODUCT_FOR_FACTORIAL; \
FOREQ( i , 1 , MAX_I ){ \
ANSWER[i] = ( VARIABLE_FOR_PRODUCT_FOR_FACTORIAL *= i ) %= MODULO; \
} \
ANSWER_INV[0] = ANSWER_INV[1] = INVERSE[1] = VARIABLE_FOR_PRODUCT_FOR_FACTORIAL = 1; \
FOREQ( i , 2 , MAX_I ){ \
ANSWER_INV[i] = ( VARIABLE_FOR_PRODUCT_FOR_FACTORIAL *= INVERSE[i] = MODULO - ( ( ( MODULO / i ) * INVERSE[MODULO % i] ) % MODULO ) ) %= MODULO; \
} \
} \
// 通常の二分探索（単調関数-目的値が一意実数解を持つ場合にそれを超えない最大の整数を返す）
#define BS( ANSWER , MINIMUM , MAXIMUM , EXPRESSION , TARGET ) \
ll ANSWER = MAXIMUM; \
{ \
ll VARIABLE_FOR_BINARY_SEARCH_L = MINIMUM; \
ll VARIABLE_FOR_BINARY_SEARCH_U = ANSWER; \
ll VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( TARGET ) - ( EXPRESSION ); \
if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH == 0 ){ \
VARIABLE_FOR_BINARY_SEARCH_L = ANSWER; \
} else { \
ANSWER = ( VARIABLE_FOR_BINARY_SEARCH_L + VARIABLE_FOR_BINARY_SEARCH_U ) / 2; \
} \
while( VARIABLE_FOR_BINARY_SEARCH_L != ANSWER ){ \
VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( TARGET ) - ( EXPRESSION ); \
if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH == 0 ){ \
break; \
} else { \
if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH > 0 ){ \
VARIABLE_FOR_BINARY_SEARCH_L = ANSWER; \
} else { \
VARIABLE_FOR_BINARY_SEARCH_U = ANSWER; \
} \
ANSWER = ( VARIABLE_FOR_BINARY_SEARCH_L + VARIABLE_FOR_BINARY_SEARCH_U ) / 2; \
} \
} \
} \
\
// 二進法の二分探索（単調関数-目的値が一意実数解を持つ場合にそれを超えない最大の整数を返す）
#define BS2( ANSWER , MINIMUM , MAXIMUM , EXPRESSION , TARGET ) \
ll ANSWER = MINIMUM; \
{ \
ll VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 = 1; \
ll VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( MAXIMUM ) - ANSWER; \
while( VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 <= VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH ){ \
VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 *= 2; \
} \
VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 /= 2; \
ll VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 = ANSWER; \
while( VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 != 0 ){ \
ANSWER = VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 + VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2; \
VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( TARGET ) - ( EXPRESSION ); \
if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH == 0 ){ \
VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 = ANSWER; \
break; \
} else if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH > 0 ){ \
VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 = ANSWER; \
} \
VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 /= 2; \
} \
ANSWER = VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2; \
} \
\
template <typename T> inline T Absolute( const T& a ){ return a > 0 ? a : -a; }
template <typename T> inline T Residue( const T& a , const T& p ){ return a >= 0 ? a % p : p - 1 - ( ( - ( a + 1 ) ) % p ); }
#include <atcoder/all>
using namespace atcoder;
inline CEXPR( ll , P , 998244353 );
uint K = 1;
uint K2 = 2;
vector<ll> mul( vector<ll> f0 , vector<ll> f1 )
{
vector<ll> ans = convolution( f0 , f1 );
int size = ans.size();
while( size > K ){
size--;
ll& ans_curr = ans[size - K];
if( ( ans_curr += ans[size] ) >= P ){
ans_curr -= P;
}
ans.pop_back();
}
return ans;
}
inline vector<ll> e(){ return vector<ll>( 1 , 1 ); }
ATT int main()
{
UNTIE;
CIN( int , N );
CIN( int , M );
cin >> K;
K2 = ( K << 1 );
vector<vector<ll> > v{};
REPEAT( M ){
CIN( uint , Ai );
vector<ll> f( Ai + 1 );
f[0]++;
f[Ai]++;
v.push_back( move( f ) );
}
segtree<vector<ll>,mul,e> a[2] = { segtree<vector<ll>,mul,e>( v ) , segtree<vector<ll>,mul,e>( M ) };
ll answer = a[0].all_prod()[0];
CEXPR( ll , P_minus , P - 1 );
COUT( answer > 0 ? --answer : P_minus );
int i_prev = 0;
int i_curr = 1;
int length = 0;
N -= M;
REPEAT( N ){
CIN( uint , Ai );
vector<ll> f( Ai + 1 );
f[0]++;
f[Ai]++;
segtree<vector<ll>,mul,e>& a_curr = a[i_curr];
segtree<vector<ll>,mul,e>& a_prev = a[i_prev];
a_curr.set( length++ , f );
answer = mul( a_prev.prod( length , M ) , a_curr.all_prod() )[0];
COUT( answer > 0 ? --answer : P_minus );
if( length == M ){
a_prev = segtree<vector<ll>,mul,e>( M );
swap( i_curr , i_prev );
length = 0;
}
}
QUIT;
}