結果
問題 | No.2211 Frequency Table of GCD |
ユーザー |
|
提出日時 | 2023-02-11 09:17:58 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 374 ms / 2,000 ms |
コード長 | 2,176 bytes |
コンパイル時間 | 3,252 ms |
コンパイル使用メモリ | 230,200 KB |
実行使用メモリ | 8,064 KB |
最終ジャッジ日時 | 2024-07-08 00:34:20 |
合計ジャッジ時間 | 11,978 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 26 |
ソースコード
#include <bits/stdc++.h>#include "atcoder/all"#define debug cout << "OK" << endl;template<typename T>inline bool chmax(T& a, const T b) { if (a < b) { a = b; return true; } return false; }template<typename T>inline bool chmin(T& a, const T b) { if (a > b) { a = b; return true; } return false; }inline int Code(char c) {if ('A' <= c and c <= 'Z')return (int)(c - 'A');if ('a' <= c and c <= 'z')return (int)(c - 'a');if ('0' <= c and c <= '9')return (int)(c - '0');assert(false);}using namespace std;using namespace atcoder;#define int long longconstexpr int MOD = 998244353;constexpr int INF = (1LL << 63);using minit = modint998244353;template<typename T>ostream& operator << (ostream& st, const vector<T>& v) {for (const T value : v) {st << value << " ";}return st;}template<typename T>istream& operator >> (istream& st, vector<T>& v) {for (T& value : v) {st >> value;}return st;}struct edge {int to, cost;};int Rand() {return (rand() % 32768) * 32768 + (rand() % 32768);}int pow_(const int a, const int b, const int m = INF) {int res = 1;int base = a;for (int i = 0; i < 64; i++) {if (b & (1ll << i))res *= base;res %= m;base = base * base;base %= m;}return res;}////class Solver {public:int T;Solver() :T(1) {}~Solver(){}void multi();void solve() const;void sp(int x)const;};void Solver::multi() {cin >> T;return;}void Solver::sp(const int x)const {cout << fixed << setprecision(x) << endl;return;}void Solver::solve() const {int N, M;cin >> N >> M;vector<int> A(N);cin >> A;vector<int> cnt(M + 1, 0);for (const int a : A) {cnt[a]++;}vector<int> ans(M + 1, 0);for (int k = M; 1 <= k; k--) {int pk = 0;minit res = 0;for (int e = 1; e * k <= M; e++) {pk += cnt[e * k];res -= ans[e * k];}res += pow_(2, pk, MOD) - 1;ans[k] = res.val();}for (int i = 1; i <= M; i++)cout << ans[i] << endl;}signed main() {Solver solver;//solver.multi();//solver.sp();for (int i = 0; i < solver.T; i++)solver.solve();return 0;}/** わらびのコードこーどすぺーす(σ・∀・)σゲッツ!!*/