結果

問題 No.1492 01文字列と転倒
ユーザー T101010101
提出日時 2023-02-12 11:35:46
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
MLE  
実行時間 -
コード長 3,778 bytes
コンパイル時間 4,023 ms
コンパイル使用メモリ 255,200 KB
最終ジャッジ日時 2025-02-10 14:41:54
ジャッジサーバーID
(参考情報)
judge1 / judge5
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 2
other AC * 12 MLE * 10
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#pragma region Macros
#include <bits/extc++.h>
using namespace std;
using namespace __gnu_pbds;
// using namespace __gnu_cxx;
// #include <atcoder/maxflow>
// using namespace atcoder;
// #include <boost/multiprecision/cpp_int.hpp>
// namespace mp = boost::multiprecision;
// using Bint = mp::cpp_int;
#define TO_STRING(var) # var
#define pb emplace_back
#define int ll
#define endl '\n'
using ll = long long;
using ld = long double;
const ld PI = acos(-1);
const ld EPS = 1e-10;
const int INF = 1 << 30;
const ll INFL = 1LL << 61;
// const int MOD = 998244353;
const int MOD = 1000000007;
__attribute__((constructor))
void constructor() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
// ifstream in("input.txt");
// cin.rdbuf(in.rdbuf());
cout << fixed << setprecision(15);
}
template<int mod> class modint{
public:
int val = 0;
modint(int x = 0) { while (x < 0) x += mod; val = x % mod; }
modint(const modint &r) { val = r.val; }
modint operator -() { return modint(-val); }
modint operator +(const modint &r) { return modint(*this) += r; }
modint operator -(const modint &r) { return modint(*this) -= r; }
modint operator *(const modint &r) { return modint(*this) *= r; }
modint operator /(const modint &r) { return modint(*this) /= r; }
modint &operator +=(const modint &r) {
val += r.val;
if (val >= mod) val -= mod;
return *this;
}
modint &operator -=(const modint &r) {
if (val < r.val) val += mod;
val -= r.val;
return *this;
}
modint &operator *=(const modint &r) {
val = val * r.val % mod;
return *this;
}
modint &operator /=(const modint &r) {
int a = r.val, b = mod, u = 1, v = 0;
while (b) {
int t = a / b;
a -= t * b; swap(a, b);
u -= t * v; swap(u, v);
}
val = val * u % mod;
if (val < 0) val += mod;
return *this;
}
bool operator ==(const modint& r) { return this -> val == r.val; }
bool operator <(const modint& r) { return this -> val < r.val; }
bool operator !=(const modint& r) { return this -> val != r.val; }
};
using mint = modint<MOD>;
istream &operator >>(istream &is, mint& x) {
int t; is >> t;
x = t;
return (is);
}
ostream &operator <<(ostream &os, const mint& x) {
return os << x.val;
}
mint modpow(const mint &a, int N) {
if (N == 0) return 1;
mint t = modpow(a, N / 2);
t = t * t;
if (N & 1) t = t * a;
return t;
}
int modpow(int x, int N, int mod) {
int ret = 1;
while (N > 0) {
if (N % 2 == 1) ret = ret * x % mod;
x = x * x % mod;
N /= 2;
}
return ret;
}
int ceil(int x, int y) { return (x > 0 ? (x + y - 1) / y : x / y); }
#pragma endregion
signed main() {
int N, M;
cin >> N >> M;
vector<vector<vector<int>>> dp(2 * N + 1, vector<vector<int>>(N + 1, vector<int>(N * N + 1)));
dp[0][0][0] = 1;
for (int i = 0; i < 2 * N; i++) { // i01
for (int j = (i + 1) / 2; j <= min(i, N); j++) { // 0j
for (int k = 0; k < N * N; k++) { // k
// 1
dp[i + 1][j][k] += dp[i][j][k];
dp[i + 1][j][k] %= M;
if (k + i - j < 0 or k + i - j > N * N or j == N) continue;
// (i - j)1.01
dp[i + 1][j + 1][k + i - j] += dp[i][j][k];
dp[i + 1][j + 1][k + i - j] %= M;
}
}
}
for (int i = 0; i <= N * N; i++) {
cout << dp[2 * N][N][i] << endl;
}
}
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