結果
問題 | No.2215 Slide Subset Sum |
ユーザー |
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提出日時 | 2023-02-12 12:29:03 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 653 ms / 3,000 ms |
コード長 | 3,058 bytes |
コンパイル時間 | 1,167 ms |
コンパイル使用メモリ | 125,728 KB |
最終ジャッジ日時 | 2025-02-10 14:44:07 |
ジャッジサーバーID (参考情報) |
judge3 / judge3 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 45 |
ソースコード
#include <iostream>#include <algorithm>#include <iomanip>#include <vector>#include <queue>#include <deque>#include <set>#include <map>#include <tuple>#include <cmath>#include <numeric>#include <functional>#include <cassert>#include <stack>#include <atcoder/modint>#define debug_value(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << #x << "=" << x << endl;#define debug(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << x << endl;template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }using namespace std;typedef long long ll;template<typename T>vector<vector<T>> vec2d(int n, int m, T v){return vector<vector<T>>(n, vector<T>(m, v));}template<typename T>vector<vector<vector<T>>> vec3d(int n, int m, int k, T v){return vector<vector<vector<T>>>(n, vector<vector<T>>(m, vector<T>(k, v)));}template<typename T>void print_vector(vector<T> v, char delimiter=' '){if(v.empty()) {cout << endl;return;}for(int i = 0; i+1 < v.size(); i++) cout << v[i] << delimiter;cout << v.back() << endl;}using mint = atcoder::modint998244353;ostream& operator<<(ostream& os, const mint& m){os << m.val();return os;}int main(){ios::sync_with_stdio(false);cin.tie(0);cout << setprecision(10) << fixed;int n, m, k; cin >> n >> m >> k;vector<int> a(n);for(int i = 0; i < n; i++) cin >> a[i];stack<int> stack_left, stack_right;auto dp = vec2d(n, k, mint(0));vector<mint> e(k); e[0] = 1;auto right_top = [&](){if(stack_right.empty()) return &e;return &dp[stack_right.top()];};auto push_left = [&](int i){dp[i].assign(k, mint(0));auto &v = stack_left.empty() ? e : dp[stack_left.top()];for(int j = 0; j < k; j++){dp[i][j] += v[j];dp[i][(j+a[i])%k] += v[j];}stack_left.push(i);};auto push_right = [&](int i){dp[i].assign(k, mint(0));auto &v = stack_right.empty() ? e : dp[stack_right.top()];for(int j = 0; j < k; j++){dp[i][j] += v[j];dp[i][(j+a[i])%k] += v[j];}stack_right.push(i);};auto pop = [&](){if(stack_left.empty()){while(!stack_right.empty()){int i = stack_right.top(); stack_right.pop();push_left(i);}}stack_left.pop();};auto ans = [&](){auto &v = stack_left.empty() ? e : dp[stack_left.top()];auto &u = stack_right.empty() ? e : dp[stack_right.top()];mint ret = 0;for(int i = 0; i < k; i++){ret += v[i]*u[(k-i)%k];}return ret;};for(int i = 0; i < m; i++) push_right(i);for(int i = m; i < n; i++){cout << ans()-1 << endl;push_right(i);pop();}cout << ans()-1 << endl;}