結果

問題 No.1170 Never Want to Walk
ユーザー 草苺奶昔草苺奶昔
提出日時 2023-02-14 22:20:37
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 449 ms / 2,000 ms
コード長 3,305 bytes
コンパイル時間 295 ms
コンパイル使用メモリ 82,460 KB
実行使用メモリ 120,872 KB
最終ジャッジ日時 2024-07-17 10:11:24
合計ジャッジ時間 9,519 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 63 ms
67,168 KB
testcase_01 AC 60 ms
67,684 KB
testcase_02 AC 59 ms
67,716 KB
testcase_03 AC 61 ms
68,560 KB
testcase_04 AC 60 ms
68,776 KB
testcase_05 AC 60 ms
68,980 KB
testcase_06 AC 60 ms
67,212 KB
testcase_07 AC 63 ms
67,748 KB
testcase_08 AC 63 ms
68,740 KB
testcase_09 AC 62 ms
67,484 KB
testcase_10 AC 65 ms
68,548 KB
testcase_11 AC 61 ms
68,556 KB
testcase_12 AC 93 ms
77,896 KB
testcase_13 AC 91 ms
77,464 KB
testcase_14 AC 91 ms
77,468 KB
testcase_15 AC 93 ms
77,720 KB
testcase_16 AC 90 ms
77,832 KB
testcase_17 AC 92 ms
77,664 KB
testcase_18 AC 91 ms
77,476 KB
testcase_19 AC 92 ms
77,784 KB
testcase_20 AC 95 ms
77,892 KB
testcase_21 AC 94 ms
77,820 KB
testcase_22 AC 90 ms
77,800 KB
testcase_23 AC 94 ms
77,736 KB
testcase_24 AC 94 ms
77,592 KB
testcase_25 AC 89 ms
77,744 KB
testcase_26 AC 93 ms
77,936 KB
testcase_27 AC 379 ms
120,376 KB
testcase_28 AC 375 ms
120,292 KB
testcase_29 AC 449 ms
120,872 KB
testcase_30 AC 385 ms
120,440 KB
testcase_31 AC 407 ms
120,008 KB
testcase_32 AC 275 ms
120,544 KB
testcase_33 AC 327 ms
119,976 KB
testcase_34 AC 326 ms
120,136 KB
testcase_35 AC 340 ms
120,744 KB
testcase_36 AC 277 ms
120,020 KB
testcase_37 AC 313 ms
120,500 KB
testcase_38 AC 284 ms
120,356 KB
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ソースコード

diff #

# https://nyaannyaan.github.io/library/data-structure/range-union-find.hpp
# 区间并查集 RangeUnionFind


from bisect import bisect_left, bisect_right


class RangeUnionFind:
    ___slots___ = ("_data", "_left", "_right")

    def __init__(self, n: int):
        self._data = [-1] * n
        self._left = list(range(n))  # 每个组的左边界
        self._right = [i + 1 for i in range(n)]  # 每个组的右边界

    def find(self, x: int) -> int:
        if self._data[x] < 0:
            return x
        self._data[x] = self.find(self._data[x])
        return self._data[x]

    def union(self, x: int, y: int) -> bool:
        rootX = self.find(x)
        rootY = self.find(y)
        if rootX == rootY:
            return False
        if self._data[rootX] > self._data[rootY]:
            rootX, rootY = rootY, rootX
        self._data[rootX] += self._data[rootY]
        self._data[rootY] = rootX
        if self._left[rootY] < self._left[rootX]:
            self._left[rootX] = self._left[rootY]
        if self._right[rootY] > self._right[rootX]:
            self._right[rootX] = self._right[rootY]
        return True

    def unionRange(self, start: int, end: int) -> int:
        """合并`左闭右开区间[start, end)`,返回新合并的个数(次数)"""
        if start < 0:
            start = 0
        if end > len(self._data):
            end = len(self._data)
        if start >= end:
            return 0
        m, count = 0, 0
        while True:
            m = self._right[self.find(start)]
            if m >= end:
                break
            self.union(start, m)
            count += 1
        return count

    def isConnected(self, x: int, y: int) -> bool:
        return self.find(x) == self.find(y)

    def size(self, x: int) -> int:
        return -self._data[self.find(x)]


if __name__ == "__main__":

    # uf = RangeUnionFind(10)
    # print(uf.unionRange(0, 5))
    # print(uf.unionRange(0, 5))
    # print(uf.isConnected(0, 4))
    # print(uf.size(0))

    # 2158. 每天绘制新区域的数量
    # https://leetcode-cn.com/problems/amount-of-new-area-painted-each-day/
    # 1 <= paint.length <= 1e5
    # paint[i].length == 2
    # 0 <= starti < endi <= 5 * 104
    from typing import List

    class Solution:
        def amountPainted(self, paint: List[List[int]]) -> List[int]:
            uf = RangeUnionFind(int(5e4) + 10)
            res = [0] * len(paint)
            for i, (start, end) in enumerate(paint):
                res[i] = uf.unionRange(start, end + 1)
            return res

    # No.1170 Never Want to Walk
    # https://yukicoder.me/problems/no/1170
    # 数轴上有n个车站,第i个位置在xi
    # 如果两个车站之间的距离di与dj满足 A<=|di-dj|<=B,则这两个车站可以相互到达,否则不能相互到达
    # 对每个车站,求出从该车站出发,可以到达的车站的数量
    # 1<=n<=2e5 0<=A<=B<=1e9 0<=x1<=x2<...<=xn<=1e9
    n, A, B = map(int, input().split())
    pos = list(map(int, input().split()))
    uf = RangeUnionFind(n)
    for i, p in enumerate(pos):
        left = bisect_left(pos, p + A)
        right = bisect_right(pos, p + B)
        if left != right:
            uf.union(i, left)
        uf.unionRange(left, right)

    for i in range(n):
        print(uf.size(i))
0