結果
問題 | No.875 Range Mindex Query |
ユーザー |
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提出日時 | 2023-02-21 16:38:38 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 215 ms / 2,000 ms |
コード長 | 3,458 bytes |
コンパイル時間 | 1,918 ms |
コンパイル使用メモリ | 175,260 KB |
実行使用メモリ | 6,944 KB |
最終ジャッジ日時 | 2024-07-22 03:18:53 |
合計ジャッジ時間 | 5,272 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 18 |
ソースコード
#include <bits/stdc++.h>using namespace std;#define rep(i,n) for (int i = 0; i < (int)(n); ++i)#define rrep(i,n) for (int i = (int)(n-1); i >= 0; --i)#define Rep(i,a,b) for (int i = a; i < b; ++i)#define rRep(i,a,b) for (int i = a; i > b; --i)#define fore(i,a) for(auto &i:a)#define all(x) (x).begin(),(x).end()#define rall(x) (x).rbegin(),(x).rend()#define Bit(x,i) (((x)>>(i))&1)using ll = long long;using vi = vector<int>;using vll = vector<long long>;using vvi = vector<vi>;using vvll = vector<vll>;using vb = vector<bool>;using vs = vector<string>;using pii = pair<int, int>;using pll = pair<ll, ll>;template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }struct settings{settings(){ios_base::sync_with_stdio(0); cin.tie(0); cout<<fixed<<setprecision(15);};}settingss;const double PI = acos(-1);const int INF = 1001001001;const ll LINF = 1001001001001001001LL;template <typename T>struct SegTree {T base = 0;function<T(T, T)> fx = [](T x1, T x2) -> T { return min(x1, x2); };int n;vector<T> dat;SegTree(int n_, T ini) : n(), dat(n_ * 4, ini) {base = ini;int x = 1;while (n_ > x) {x *= 2;}n = x;}void set(int i, T x) { dat[i + n - 1] = x; }void build() {for (int k = n - 2; k >= 0; k--) dat[k] = fx(dat[2 * k + 1], dat[2 * k + 2]);}void update(int i, T x) {i += n - 1;dat[i] = x;while (i > 0) {i = (i - 1) / 2;dat[i] = fx(dat[i * 2 + 1], dat[i * 2 + 2]);}}T query(int a, int b) { return query_sub(a, b, 0, 0, n); }T query_sub(int a, int b, int k, int l, int r) {if (r <= a || b <= l) {return base;} else if (a <= l && r <= b) {return dat[k];} else {T vl = query_sub(a, b, k * 2 + 1, l, (l + r) / 2);T vr = query_sub(a, b, k * 2 + 2, (l + r) / 2, r);return fx(vl, vr);}}int find_rightest(int a, int b, T x) { return find_rightest_sub(a, b, x, 0, 0, n); }int find_leftest(int a, int b, T x) { return find_leftest_sub(a, b, x, 0, 0, n); }int find_rightest_sub(int a, int b, T x, int k, int l, int r) {if (dat[k] > x || r <= a || b <= l) {return a - 1;} else if (k >= n - 1) {return (k - (n - 1));} else {int vr = find_rightest_sub(a, b, x, 2 * k + 2, (l + r) / 2, r);if (vr != a - 1) {return vr;} else {return find_rightest_sub(a, b, x, 2 * k + 1, l, (l + r) / 2);}}}int find_leftest_sub(int a, int b, T x, int k, int l, int r) {if (dat[k] > x || r <= a || b <= l) {return b;} else if (k >= n - 1) {return (k - (n - 1));} else {int vl = find_leftest_sub(a, b, x, 2 * k + 1, l, (l + r) / 2);if (vl != b) {return vl;} else {return find_leftest_sub(a, b, x, 2 * k + 2, (l + r) / 2, r);}}}};SegTree<int> seg(100100, INF);int main() {int N, Q; cin >> N >> Q;rep(i, N) {int a; cin >> a;seg.set(i, a);}seg.build();rep(i, Q) {int op, l, r; cin >> op >> l >> r; --l; --r;if(op == 1) {int a = seg.query(l, l+1);int b = seg.query(r, r+1);seg.update(l, b);seg.update(r, a);} else {int mn = seg.query(l, r+1);int idx = seg.find_leftest(l, r+1, mn);cout << idx+1 << endl;}}}