結果

問題 No.1640 簡単な色塗り
ユーザー apricity
提出日時 2023-02-27 23:01:36
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 79 ms / 2,000 ms
コード長 4,700 bytes
コンパイル時間 2,009 ms
コンパイル使用メモリ 146,832 KB
最終ジャッジ日時 2025-02-11 00:00:20
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 53
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<iostream>
#include<string>
#include<vector>
#include<algorithm>
#include<numeric>
#include<cmath>
#include<utility>
#include<tuple>
#include<cstdint>
#include<cstdio>
#include<iomanip>
#include<map>
#include<queue>
#include<set>
#include<stack>
#include<deque>
#include<unordered_map>
#include<unordered_set>
#include<bitset>
#include<cctype>
#include<chrono>
#include<random>
#include<cassert>
#include<cstddef>
#include<iterator>
#include<string_view>
#include<type_traits>
#ifdef LOCAL
# include "debug_print.hpp"
# define debug(...) debug_print::multi_print(#__VA_ARGS__, __VA_ARGS__)
#else
# define debug(...) (static_cast<void>(0))
#endif
using namespace std;
#define rep(i,n) for(int i=0; i<(n); i++)
#define rrep(i,n) for(int i=(n)-1; i>=0; i--)
#define FOR(i,a,b) for(int i=(a); i<(b); i++)
#define RFOR(i,a,b) for(int i=(b-1); i>=(a); i--)
#define ALL(v) v.begin(), v.end()
#define RALL(v) v.rbegin(), v.rend()
#define UNIQUE(v) v.erase( unique(v.begin(), v.end()), v.end() );
#define pb push_back
using ll = long long;
using D = double;
using LD = long double;
using P = pair<int, int>;
template<typename T> using PQ = priority_queue<T,vector<T>>;
template<typename T> using minPQ = priority_queue<T, vector<T>, greater<T>>;
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
void yesno(bool flag) {cout << (flag?"Yes":"No") << "\n";}
template<typename T, typename U>
ostream &operator<<(ostream &os, const pair<T, U> &p) {
os << p.first << " " << p.second;
return os;
}
template<typename T, typename U>
istream &operator>>(istream &is, pair<T, U> &p) {
is >> p.first >> p.second;
return is;
}
template<typename T>
ostream &operator<<(ostream &os, const vector<T> &v) {
int s = (int)v.size();
for (int i = 0; i < s; i++) os << (i ? " " : "") << v[i];
return os;
}
template<typename T>
istream &operator>>(istream &is, vector<T> &v) {
for (auto &x : v) is >> x;
return is;
}
void in() {}
template<typename T, class... U>
void in(T &t, U &...u) {
cin >> t;
in(u...);
}
void out() { cout << "\n"; }
template<typename T, class... U, char sep = ' '>
void out(const T &t, const U &...u) {
cout << t;
if (sizeof...(u)) cout << sep;
out(u...);
}
void outr() {}
template<typename T, class... U, char sep = ' '>
void outr(const T &t, const U &...u) {
cout << t;
outr(u...);
}
#include "atcoder/dsu.hpp"
int main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int n; in(n);
vector<vector<P>> g(n);
vector<P> prev(n,{-1,-1});
vector<int> ans(n);
auto get_path = [&] (int a, int b) -> vector<int> {
vector<int> res = {b};
queue<int> q;
q.push(a);
while(q.size()){
int x = q.front(); q.pop();
for(auto [y,idx] : g[x]){
if(prev[y].first == -1){
prev[y] = {x,idx};
q.push(y);
}
}
}
int now = b;
while(now != a){
auto [nxt, idx] = prev[now];
ans[idx] = now+1;
res.pb(nxt);
now = nxt;
}
return res;
};
atcoder::dsu d(n);
vector<bool> loop(n,false);
vector<bool> seen(n,false);
rep(i,n){
int a,b; in(a,b); a--; b--;
if(a == b){
int u = d.leader(a);
if(loop[u]){
out("No");
return 0;
}
else{
loop[u] = true;
seen[a] = true;
ans[i] = a+1;
}
}
else if(d.same(a,b)){
int u = d.leader(a);
if(loop[u]){
out("No");
return 0;
}
else{
loop[u] = true;
auto vp = get_path(a,b);
for(int v : vp) seen[v] = true;
ans[i] = a+1;
}
}
else{
int u = d.leader(a);
int v = d.leader(b);
if(loop[u]&loop[v]){
out("No");
return 0;
}
int w = d.merge(a,b);
loop[w] = loop[u] | loop[v];
g[a].pb({b,i});
g[b].pb({a,i});
}
}
queue<int> q;
rep(i,n){
if(seen[i]) q.push(i);
}
while(q.size()){
int x = q.front(); q.pop();
for(auto [y,idx] : g[x]){
if(seen[y]) continue;
seen[y] = true;
ans[idx] = y+1;
q.push(y);
}
}
out("Yes");
rep(i,n) out(ans[i]);
}
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