結果
問題 | No.2222 Respawn |
ユーザー | leaf_1415 |
提出日時 | 2023-03-02 17:10:49 |
言語 | C++11 (gcc 11.4.0) |
結果 |
AC
|
実行時間 | 16 ms / 2,000 ms |
コード長 | 8,913 bytes |
コンパイル時間 | 2,230 ms |
コンパイル使用メモリ | 109,780 KB |
実行使用メモリ | 8,704 KB |
最終ジャッジ日時 | 2024-09-17 11:33:43 |
合計ジャッジ時間 | 2,879 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 2 ms
6,940 KB |
testcase_02 | AC | 2 ms
6,940 KB |
testcase_03 | AC | 2 ms
6,944 KB |
testcase_04 | AC | 2 ms
6,944 KB |
testcase_05 | AC | 2 ms
5,376 KB |
testcase_06 | AC | 3 ms
5,376 KB |
testcase_07 | AC | 2 ms
5,376 KB |
testcase_08 | AC | 3 ms
5,376 KB |
testcase_09 | AC | 3 ms
5,376 KB |
testcase_10 | AC | 2 ms
5,376 KB |
testcase_11 | AC | 2 ms
5,376 KB |
testcase_12 | AC | 2 ms
5,376 KB |
testcase_13 | AC | 6 ms
7,040 KB |
testcase_14 | AC | 4 ms
6,144 KB |
testcase_15 | AC | 3 ms
5,376 KB |
testcase_16 | AC | 4 ms
5,888 KB |
testcase_17 | AC | 3 ms
5,376 KB |
testcase_18 | AC | 6 ms
8,448 KB |
testcase_19 | AC | 6 ms
8,576 KB |
testcase_20 | AC | 6 ms
8,704 KB |
testcase_21 | AC | 7 ms
8,608 KB |
testcase_22 | AC | 6 ms
8,576 KB |
testcase_23 | AC | 6 ms
8,476 KB |
testcase_24 | AC | 7 ms
8,576 KB |
testcase_25 | AC | 7 ms
8,476 KB |
testcase_26 | AC | 6 ms
8,576 KB |
testcase_27 | AC | 8 ms
8,576 KB |
testcase_28 | AC | 7 ms
8,576 KB |
testcase_29 | AC | 7 ms
8,448 KB |
testcase_30 | AC | 9 ms
8,616 KB |
testcase_31 | AC | 5 ms
8,704 KB |
testcase_32 | AC | 16 ms
8,704 KB |
ソースコード
#include <iostream> #include <iomanip> #include <cstdio> #include <cmath> #include <ctime> #include <cstdlib> #include <cassert> #include <vector> #include <list> #include <stack> #include <queue> #include <deque> #include <map> #include <set> #include <bitset> #include <string> #include <algorithm> #include <utility> #include <complex> #include <array> #include <unordered_set> #include <unordered_map> #define rep(x, s, t) for(ll x = (s); (x) <= (t); (x)++) #define per(x, s, t) for(ll x = (s); (x) >= (t); (x)--) #define reps(x, s) for(ll x = 0; (x) < (ll)(s).size(); (x)++) #define chmin(x, y) (x) = min((x), (y)) #define chmax(x, y) (x) = max((x), (y)) #define sz(x) ((ll)(x).size()) #define all(x) (x).begin(),(x).end() #define rall(x) (x).rbegin(),(x).rend() #define outl(...) dump_func(__VA_ARGS__) #define outf(x) cout << fixed << setprecision(16) << (x) << endl #define pb push_back #define fi first #define se second #define inf 2e18 #define eps 1e-9 const double PI = 3.1415926535897932384626433; using namespace std; typedef long long ll; typedef unsigned long long ull; typedef pair<ll, ll> P; struct edge{ ll to, cost; edge(){} edge(ll a, ll b){ to = a, cost = b;} }; const int dx[] = {1, 0, -1, 0}, dy[] = {0, -1, 0, 1}; const int mod = 1000000007; //const int mod = 998244353; struct mint{ int x; mint(ll y = 0){if(y < 0 || y >= mod) y = (y%mod+mod)%mod; x = y;} mint(const mint &ope) {x = ope.x;} mint operator-(){return mint(-x);} mint operator+(const mint &ope){return mint(x) += ope;} mint operator-(const mint &ope){return mint(x) -= ope;} mint operator*(const mint &ope){return mint(x) *= ope;} mint operator/(const mint &ope){return mint(x) /= ope;} mint& operator+=(const mint &ope){x += ope.x; if(x >= mod) x -= mod; return *this;} mint& operator-=(const mint &ope){x += mod - ope.x; if(x >= mod) x -= mod; return *this;} mint& operator*=(const mint &ope){ll tmp = x; tmp *= ope.x, tmp %= mod; x = tmp; return *this;} mint& operator/=(const mint &ope){ ll n = mod-2; mint mul = ope; while(n){if(n & 1) *this *= mul; mul *= mul; n >>= 1;} return *this; } mint inverse(){return mint(1) / *this;} bool operator ==(const mint &ope){return x == ope.x;} bool operator !=(const mint &ope){return x != ope.x;} bool operator <(const mint &ope)const{return x < ope.x;} }; mint modpow(mint a, ll n){ if(n == 0) return mint(1); if(n % 2) return a * modpow(a, n-1); else return modpow(a*a, n/2); } istream& operator >>(istream &is, mint &ope){ll t; is >> t, ope = mint(t); return is;} ostream& operator <<(ostream &os, mint &ope){return os << ope.x;} ostream& operator <<(ostream &os, const mint &ope){return os << ope.x;} ll modpow(ll a, ll n, ll mod){ if(n == 0) return 1; if(n % 2) return ((a%mod) * (modpow(a, n-1, mod)%mod)) % mod; else return modpow((a*a)%mod, n/2, mod) % mod; } vector<mint> fact, fact_inv; void make_fact(int n){ fact.resize(n+1), fact_inv.resize(n+1); fact[0] = mint(1); rep(i, 1, n) fact[i] = fact[i-1] * mint(i); fact_inv[n] = fact[n].inverse(); per(i, n-1, 0) fact_inv[i] = fact_inv[i+1] * mint(i+1); } mint comb(int n, int k){ if(n < 0 || k < 0 || n < k) return mint(0); return fact[n] * fact_inv[k] * fact_inv[n-k];} mint perm(int n, int k){ return comb(n, k) * fact[k]; } mint divide(int n, int k){ return comb(n+k-1, k-1); } template<typename T> T comb2(ll n, ll k){ if(n < 0 || k < 0 || n < k) return T(0); T ret = 1; rep(i, 1, k) ret *= n-k+i, ret /= i; return ret;} vector<ll> prime, pvec, qrime; void make_prime(int n){ prime.resize(n+1); rep(i, 2, n){ if(prime[i] == 0) pvec.push_back(i), prime[i] = i; for(auto p : pvec){ if(i*p > n || p > prime[i]) break; prime[i*p] = p;} } } void make_qrime(int n){ qrime.resize(n+1); rep(i, 2, n){int ni = i / prime[i]; if(prime[i] == prime[ni]) qrime[i] = qrime[ni] * prime[i]; else qrime[i] = prime[i];} } void factorize(ll n, map<ll, ll> &mp){ mp.clear(); for(auto p : pvec) while(n % p == 0) mp[p]++, n /= p; if(n > 1) mp[n]++; } bool exceed(ll x, ll y, ll m){return y > 0 && x >= m / y + 1;} void mark(){ cout << "*" << endl; } void yes(){ cout << "YES" << endl; } void no(){ cout << "NO" << endl; } ll floor(ll a, ll b){ if(b < 0) a *= -1, b *= -1; if(a >= 0) return a/b; else return -((-a+b-1)/b); } ll ceil(ll a, ll b){ if(b < 0) a *= -1, b *= -1; if(a >= 0) return (a+b-1)/b; else return -((-a)/b); } ll modulo(ll a, ll b){ b = abs(b); return a - floor(a, b) * b;} ll sgn(ll x){ if(x > 0) return 1; if(x < 0) return -1; return 0;} ll gcd(ll a, ll b){if(b == 0) return a; return gcd(b, a%b);} ll lcm(ll a, ll b){return a/gcd(a, b)*b;} template<typename T> T arith(T x){return x*(x+1)/2;} template<typename T> T arith2(T x){return x*(x+1)*(x*2+1)/6;} ll digitnum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret++; return ret;} ll digitsum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret += x % b; return ret;} string lltos(ll x, ll b = 10){if(x == 0) return "0"; string ret; for(;x;x/=b) ret += x % b + '0'; reverse(all(ret)); return ret;} ll stoll(string &s, ll b = 10){ll ret = 0; for(auto c : s) ret *= b, ret += c - '0'; return ret;} template<typename T> void uniq(T &vec){sort(all(vec)); vec.erase(unique(all(vec)), vec.end());} int popcount(ull x){ x -= ((x>>1)&0x5555555555555555ULL), x = (x & 0x3333333333333333ULL) + ((x>>2) & 0x3333333333333333ULL); return (((x + (x>>4)) & 0x0F0F0F0F0F0F0F0FULL) * 0x0101010101010101ULL) >> 56; } template<class S, class T> pair<S, T>& operator+=(pair<S, T> &s, const pair<S, T> &t){s.first += t.first, s.second += t.second; return s;} template<class S, class T> pair<S, T>& operator-=(pair<S, T> &s, const pair<S, T> &t){s.first -= t.first, s.second -= t.second; return s;} template<class S, class T> pair<S, T> operator+(const pair<S, T> &s, const pair<S, T> &t){return pair<S,T>(s.first+t.first, s.second+t.second);} template<class S, class T> pair<S, T> operator-(const pair<S, T> &s, const pair<S, T> &t){return pair<S,T>(s.first-t.first, s.second-t.second);} template<class T> T dot(const pair<T, T> &s, const pair<T, T> &t){return s.first*t.first + s.second*t.second;} template<class T> T cross(const pair<T, T> &s, const pair<T, T> &t){return s.first*t.second - s.second*t.first;} template<class T> T mdist(pair<T, T> s, pair<T, T> t){return abs(s.first-t.first) + abs(s.second-t.second);} template<class T> T cdist(pair<T, T> s, pair<T, T> t){return max(abs(s.first-t.first), abs(s.second-t.second));} template<class T> T edist2(pair<T, T> s, pair<T, T> t){return (s.first-t.first)*(s.first-t.first) + (s.second-t.second)*(s.second-t.second);} template<typename T> ostream& operator << (ostream& os, vector<T>& vec){reps(i, vec) os << vec[i] << " "; return os;} template<typename T> ostream& operator << (ostream& os, const vector<T>& vec){reps(i, vec) os << vec[i] << " "; return os;} template<typename T> ostream& operator << (ostream& os, list<T>& ls){for(auto x : ls) os << x << " "; return os;} template<typename T> ostream& operator << (ostream& os, const list<T>& ls){for(auto x : ls) os << x << " "; return os;} template<typename T> ostream& operator << (ostream& os, deque<T>& deq){reps(i, deq) os << deq[i] << " "; return os;} template<typename T, typename U> ostream& operator << (ostream& os, pair<T, U>& ope){ os << "(" << ope.first << ", " << ope.second << ")"; return os;} template<typename T, typename U> ostream& operator << (ostream& os, const pair<T, U>& ope){ os << "(" << ope.first << ", " << ope.second << ")"; return os;} template<typename T, typename U> ostream& operator << (ostream& os, map<T, U>& ope){ for(auto p : ope) os << "(" << p.first << ", " << p.second << "),";return os;} template<typename T> ostream& operator << (ostream& os, set<T>& ope){for(auto x : ope) os << x << " "; return os;} template<typename T> ostream& operator << (ostream& os, multiset<T>& ope){for(auto x : ope) os << x << " "; return os;} template<typename T> void outa(T a[], ll s, ll t){rep(i, s, t){ cout << a[i]; if(i < t) cout << " ";} cout << endl;} template<typename T, size_t N> ostream& operator << (ostream& os, array<T, N>& arr){reps(i, arr) os << arr[i] << " "; return os;} template<typename T, size_t N> ostream& operator << (ostream& os, const array<T, N>& arr){reps(i, arr) os << arr[i] << " "; return os;} void dump_func(){cout << endl;} template <class Head, class... Tail> void dump_func(Head &&head, Tail &&... tail){cout << head; if(sizeof...(Tail) > 0) cout << " "; dump_func(std::move(tail)...);} template<typename T> void bssert(bool b, T t){ if(!b) cout << t << endl, exit(0); } ll n; string s; double e[200005], p[200005], q[200005]; int main(void) { ios::sync_with_stdio(0); cin.tie(0); cin >> n >> s; s = "#" + s; p[n+1] = 1, q[n+1] = 0; per(i, n-1, 1){ if(s[i] == '#') p[i] = 1, q[i] = 0; else{ e[i] = (q[i+1]+q[i+2]+3) / (2 - p[i+1]-p[i+2]); p[i] = (p[i+1]+p[i+2]) / 3, q[i] = (q[i+1]+q[i+2]+e[i]) / 3 + 1; } } outf(e[1]); return 0; }