結果
問題 | No.875 Range Mindex Query |
ユーザー |
|
提出日時 | 2023-03-03 14:29:05 |
言語 | Go (1.23.4) |
結果 |
AC
|
実行時間 | 201 ms / 2,000 ms |
コード長 | 3,579 bytes |
コンパイル時間 | 14,784 ms |
コンパイル使用メモリ | 233,332 KB |
実行使用メモリ | 7,912 KB |
最終ジャッジ日時 | 2024-09-17 21:58:54 |
合計ジャッジ時間 | 16,421 ms |
ジャッジサーバーID (参考情報) |
judge6 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 18 |
ソースコード
package mainimport ("bufio""fmt""os")func main() {// https://yukicoder.me/submissions/845112// op1:赋值// !op2:查询区间最小值处的索引(线段树上二分即可)in := bufio.NewReader(os.Stdin)out := bufio.NewWriter(os.Stdout)defer out.Flush()var n, q intfmt.Fscan(in, &n, &q)nums := make([]E, n)for i := range nums {fmt.Fscan(in, &nums[i])}seg := NewSegmentTree(nums)for i := 0; i < q; i++ {var op, left, right intfmt.Fscan(in, &op, &left, &right)if op == 1 {left--right--tmp := seg.Get(left)seg.Set(left, seg.Get(right))seg.Set(right, tmp)} else {left--min_ := seg.Query(left, right)res := seg.MaxRight(left, func(x int) bool { return x > min_ })fmt.Fprintln(out, res+1)}}}const INF int = 1e18// PointSetRangeMintype E = intfunc (*SegmentTree) e() E { return INF }func (*SegmentTree) op(a, b E) E { return min(a, b) }func min(a, b int) int {if a < b {return a}return b}func max(a, b int) int {if a > b {return a}return b}type SegmentTree struct {n, size intseg []E}func NewSegmentTree(leaves []E) *SegmentTree {res := &SegmentTree{}n := len(leaves)size := 1for size < n {size <<= 1}seg := make([]E, size<<1)for i := 0; i < n; i++ {seg[i+size] = leaves[i]}for i := size - 1; i > 0; i-- {seg[i] = res.op(seg[i<<1], seg[i<<1|1])}res.n = nres.size = sizeres.seg = segreturn res}func (st *SegmentTree) Get(index int) E {if index < 0 || index >= st.n {return st.e()}return st.seg[index+st.size]}func (st *SegmentTree) Set(index int, value E) {if index < 0 || index >= st.n {return}index += st.sizest.seg[index] = valuefor index >>= 1; index > 0; index >>= 1 {st.seg[index] = st.op(st.seg[index<<1], st.seg[index<<1|1])}}// [start, end)func (st *SegmentTree) Query(start, end int) E {if start < 0 {start = 0}if end > st.n {end = st.n}if start >= end {return st.e()}leftRes, rightRes := st.e(), st.e()start += st.sizeend += st.sizefor start < end {if start&1 == 1 {leftRes = st.op(leftRes, st.seg[start])start++}if end&1 == 1 {end--rightRes = st.op(st.seg[end], rightRes)}start >>= 1end >>= 1}return st.op(leftRes, rightRes)}func (st *SegmentTree) QueryAll() E { return st.seg[1] }// 二分查询最大的 right 使得切片 [left:right] 内的值满足 predicatefunc (st *SegmentTree) MaxRight(left int, predicate func(E) bool) int {if left == st.n {return st.n}left += st.sizeres := st.e()for {for left&1 == 0 {left >>= 1}if !predicate(st.op(res, st.seg[left])) {for left < st.size {left <<= 1if predicate(st.op(res, st.seg[left])) {res = st.op(res, st.seg[left])left++}}return left - st.size}res = st.op(res, st.seg[left])left++if (left & -left) == left {break}}return st.n}// 二分查询最小的 left 使得切片 [left:right] 内的值满足 predicatefunc (st *SegmentTree) MinLeft(right int, predicate func(E) bool) int {if right == 0 {return 0}right += st.sizeres := st.e()for {right--for right > 1 && right&1 == 1 {right >>= 1}if !predicate(st.op(st.seg[right], res)) {for right < st.size {right = right<<1 | 1if predicate(st.op(st.seg[right], res)) {res = st.op(st.seg[right], res)right--}}return right + 1 - st.size}res = st.op(st.seg[right], res)if right&-right == right {break}}return 0}