結果

問題 No.2197 Same Dish
ユーザー tsugutsugu
提出日時 2023-03-05 16:57:46
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 43 ms / 2,000 ms
コード長 2,663 bytes
コンパイル時間 1,580 ms
コンパイル使用メモリ 176,216 KB
実行使用メモリ 17,068 KB
最終ジャッジ日時 2024-09-18 01:37:13
合計ジャッジ時間 2,725 ms
ジャッジサーバーID
(参考情報)
judge6 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 20
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
const int mod = 998244353;
// const int mod = 1000000007;
struct modint {
long long a = 0;
modint(long long x = 0) {while (x < 0) x += mod; a = x % mod;}
modint(const modint &r) {a = r.a;}
modint operator -(){return modint(-a);}
modint operator +(const modint &r) {return modint(*this) += r;}
modint operator -(const modint &r) {return modint(*this) -= r;}
modint operator *(const modint &r) {return modint(*this) *= r;}
modint &operator +=(const modint &r) {
a += r.a;
if(a >= mod) a -= mod;
return *this;
}
modint &operator -=(const modint &r) {
a -= r.a;
if(a < 0) a += mod;
return *this;
}
modint &operator *=(const modint &r) {
a = a * r.a % mod;
return *this;
}
modint pow(long long r) const {
if (!r) return 1;
modint x = pow(r >> 1);
x *= x;
if (r & 1) x *= *this;
return x;
}
modint inverse() const {
return pow(mod - 2);
}
modint& operator/=(const modint r) {
return (*this) *= r.inverse();
}
modint operator/(const modint r) const {
modint res(*this);
return res /= r;
}
};
istream &operator>>(istream &is, modint &x) {
long long t;
is >> t;
x = t;
return is;
}
ostream &operator<<(ostream &os, const modint& x) {
return os << x.a;
}
const int MAX = 500000;
modint fac[MAX], inv[MAX], finv[MAX];
void cominit() {
fac[0] = fac[1] = 1;
finv[0] = finv[1] = 1;
inv[1] = 1;
for(int i = 2; i < MAX; i++) {
fac[i] = fac[i - 1] * modint(i);
inv[i] = - inv[mod % i] * modint(mod / i);
finv[i] = finv[i - 1] * inv[i];
}
}
modint Com(long long n, long long k) {
if(n < k) return 0;
if(n < 0 || k < 0) return 0;
return fac[n] * finv[k] * finv[n - k];
}
modint Per(long long n, long long k) {
if(n < k) return 0;
if(n < 0 || k < 0) return 0;
return fac[n] * finv[n - k];
}
using Mint = modint;
const int mxN = 2e5 + 4;
int main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int n, k;
cin >> n >> k;
vector<pair<int, int>> a;
for (int i = 0; i < n; i++) {
int l, r;
cin >> l >> r;
a.push_back(make_pair(l, 1));
a.push_back(make_pair(r, -1));
}
sort(a.begin(), a.end());
Mint x = 1;
int cnt = 0;
for (int i = 0; i < 2 * n; i++) {
if (a[i].second == 1) {
cnt++;
x *= Mint(k + 1 - cnt);
} else {
cnt--;
}
}
Mint ans = Mint(k).pow(n) - x;
cout << ans << '\n';
}
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