結果
問題 |
No.1036 Make One With GCD 2
|
ユーザー |
|
提出日時 | 2023-03-10 18:28:13 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 767 ms / 2,000 ms |
コード長 | 2,283 bytes |
コンパイル時間 | 213 ms |
コンパイル使用メモリ | 82,032 KB |
実行使用メモリ | 253,808 KB |
最終ジャッジ日時 | 2024-09-18 03:20:40 |
合計ジャッジ時間 | 19,543 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 4 |
other | AC * 41 |
ソースコード
from math import gcd from typing import Callable, Generic, List, TypeVar E = TypeVar("E") class SlidingWindowAggregation(Generic[E]): """SlidingWindowAggregation Api: 1. append value to tail,O(1). 2. pop value from head,O(1). 3. query aggregated value in window,O(1). """ __slots__ = ["_stack0", "_stack1", "_stack2", "_stack3", "_e0", "_e1", "_size", "_op", "_e"] def __init__(self, e: Callable[[], E], op: Callable[[E, E], E]): """ Args: e: unit element op: merge function """ self._stack0 = [] self._stack1 = [] self._stack2 = [] self._stack3 = [] self._e = e self._e0 = e() self._e1 = e() self._size = 0 self._op = op def append(self, value: E) -> None: if not self._stack0: self._push0(value) self._transfer() else: self._push1(value) self._size += 1 def popleft(self) -> None: if not self._size: return if not self._stack0: self._transfer() self._stack0.pop() self._stack2.pop() self._e0 = self._stack2[-1] if self._stack2 else self._e() self._size -= 1 def query(self) -> E: return self._op(self._e0, self._e1) def _push0(self, value): self._stack0.append(value) self._e0 = self._op(value, self._e0) self._stack2.append(self._e0) def _push1(self, value): self._stack1.append(value) self._e1 = self._op(self._e1, value) self._stack3.append(self._e1) def _transfer(self): while self._stack1: self._push0(self._stack1.pop()) while self._stack3: self._stack3.pop() self._e1 = self._e() @property def size(self): return self._size if __name__ == "__main__": n = int(input()) nums = list(map(int, input().split())) S = SlidingWindowAggregation(lambda: 0, gcd) res = 0 right = 0 for left in range(n): right = max(right, left) while right < n and gcd(S.query(), nums[right]) != 1: S.append(nums[right]) right += 1 res += n - right S.popleft() print(res)