結果
| 問題 |
No.650 行列木クエリ
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-03-12 15:24:17 |
| 言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 444 ms / 2,000 ms |
| コード長 | 5,250 bytes |
| コンパイル時間 | 4,472 ms |
| コンパイル使用メモリ | 275,544 KB |
| 最終ジャッジ日時 | 2025-02-11 10:39:18 |
|
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 10 |
ソースコード
#include <atcoder/all>
#include <bits/stdc++.h>
using namespace std;
#define SZ(x) (int) (x).size()
#define REP(i, n) for(int i = 0; i < (n); i++)
#define FOR(i, a, b) for(auto i = (a); i < (b); i++)
#define For(i, a, b, c) \
for(auto i = (a); i != (b); i += (c))
#define REPR(i, n) for(auto i = (n) -1; i >= 0; i--)
#define ALL(s) (s).begin(), (s).end()
#define so(V) sort(ALL(V))
#define rev(V) reverse(ALL(V))
#define uni(v) v.erase(unique(ALL(v)), (v).end())
#define eb emplace_back
typedef unsigned long long ull;
typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<bool> vb;
typedef vector<vi> vvi;
typedef vector<vll> vvll;
typedef pair<int, int> PI;
typedef pair<ll, ll> PL;
const double EPS = 1e-6;
const int MOD = 1e9 + 7;
const int INF = (1 << 30);
const ll LINF = 1e18;
const double math_PI = acos(-1);
template<typename T>
vector<T> make_v(size_t a) {
return vector<T>(a);
}
template<typename T, typename... Ts>
auto make_v(size_t a, Ts... ts) {
return vector<decltype(make_v<T>(ts...))>(
a, make_v<T>(ts...));
}
template<typename T, typename V>
typename enable_if<is_class<T>::value == 0>::type fill_v(
T& t, const V& v) {
t = v;
}
template<typename T, typename V>
typename enable_if<is_class<T>::value != 0>::type fill_v(
T& t, const V& v) {
for(auto& e: t) fill_v(e, v);
}
template<class T>
bool chmax(T& a, const T& b) {
if(a < b) {
a = b;
return true;
}
return false;
}
template<class T>
bool chmin(T& a, const T& b) {
if(a > b) {
a = b;
return true;
}
return false;
}
template<typename S, typename T>
istream& operator>>(istream& is, pair<S, T>& p) {
cin >> p.first >> p.second;
return is;
}
template<typename T>
istream& operator>>(istream& is, vector<T>& vec) {
for(T& x: vec) is >> x;
return is;
}
template<typename T>
string join(vector<T>& vec, string splitter) {
stringstream ss;
REP(i, SZ(vec)) {
if(i != 0) ss << splitter;
ss << vec[i];
}
return ss.str();
}
template<typename T>
ostream& operator<<(ostream& os, vector<T>& vec) {
os << join(vec, " ");
return os;
}
class HLdecomposition {
private:
int V;
vector<vector<int>> G;
vector<int> stsize, parent, pathtop, in, out;
int root;
void BuildStsize(int u, int p) {
stsize[u] = 1, parent[u] = p;
for(int& v: G[u]) {
if(v == p) {
if(v == G[u].back())
break;
else
swap(v, G[u].back());
}
BuildStsize(v, u);
stsize[u] += stsize[v];
if(stsize[v] > stsize[G[u][0]]) {
swap(v, G[u][0]);
}
}
}
void BuildPath(int u, int p, int& tm) {
in[u] = tm++;
for(int v: G[u]) {
if(v == p) continue;
pathtop[v] = (v == G[u][0] ? pathtop[u] : v);
BuildPath(v, u, tm);
}
out[u] = tm;
}
public:
void add_edge(int u, int v) {
G[u].push_back(v), G[v].push_back(u);
}
void build(int _root = 0) {
root = _root;
int tm = 0;
BuildStsize(root, -1);
pathtop[root] = root;
BuildPath(root, -1, tm);
}
//蜈・・鬆らせ縺ョ繧、繝ウ繝・ャ繧ッ繧ケ縺ョ驟榊・荳翫〒縺ョid繧定ソ斐☆
inline int get(int a) {
return in[a];
}
int lca(int a, int b) {
int pa = pathtop[a], pb = pathtop[b];
while(pathtop[a] != pathtop[b]) {
if(in[pa] > in[pb]) {
a = parent[pa], pa = pathtop[a];
} else {
b = parent[pb], pb = pathtop[b];
}
}
if(in[a] > in[b]) swap(a, b);
return a;
}
void subtree_query(
int a, const function<void(int, int)>& func) {
func(in[a], out[a]);
}
// 萓・ hl.path_query(q, r, [&](int l, int r){ seg.range(l, r, s); })
void path_query(int a, int b,
const function<void(int, int)>& func) {
int pa = pathtop[a], pb = pathtop[b];
while(pathtop[a] != pathtop[b]) {
if(in[pa] > in[pb]) {
func(in[pa], in[a] + 1);
a = parent[pa], pa = pathtop[a];
} else {
func(in[pb], in[b] + 1);
b = parent[pb], pb = pathtop[b];
}
}
if(in[a] > in[b]) swap(a, b);
func(in[a], in[b] + 1);
}
HLdecomposition(int node_size)
: V(node_size),
G(V),
stsize(V, 0),
parent(V, -1),
pathtop(V, -1),
in(V, -1),
out(V, -1) {
}
};
using namespace atcoder;
using mint = modint1000000007;
using S = vector<vector<mint>>;
S op(S a, S b) {
S c = S(2, vector<mint>(2));
REP(i, 2) {
REP(j, 2) {
REP(k, 2) {
c[i][j] += a[i][k] * b[k][j];
}
}
}
return c;
}
S e() {
S c = S(2, vector<mint>(2));
c[0][0] = 1;
c[1][1] = 1;
return c;
}
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
int N;
cin >> N;
HLdecomposition hld(N + N - 1);
REP(i, N - 1) {
int A, B;
cin >> A >> B;
hld.add_edge(A, N + i);
hld.add_edge(N + i, B);
}
hld.build();
segtree<S, op, e> seg(2 * N - 1);
int Q;
cin >> Q;
REP(q, Q) {
char c;
cin >> c;
if(c == 'x') {
int i;
cin >> i;
int x1, x2, x3, x4;
cin >> x1 >> x2 >> x3 >> x4;
seg.set(hld.get(N + i),
vector<vector<mint>> {
{ mint(x1), mint(x2) },
{ mint(x3), mint(x4) } });
} else {
int i, j;
cin >> i >> j;
auto c = e();
vector<PI> V;
hld.path_query(i, j, [&](int l, int r) {
V.eb(l, r);
});
rev(V);
for(auto [l, r]: V) {
c = op(c, seg.prod(l, r));
}
cout << c[0][0].val() << " " << c[0][1].val()
<< " " << c[1][0].val() << " "
<< c[1][1].val() << endl;
}
}
return 0;
}