結果
問題 | No.2234 palindromer |
ユーザー |
|
提出日時 | 2023-03-16 19:24:44 |
言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 4,818 bytes |
コンパイル時間 | 13,073 ms |
コンパイル使用メモリ | 359,348 KB |
最終ジャッジ日時 | 2025-02-11 11:54:58 |
ジャッジサーバーID (参考情報) |
judge5 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 13 |
ソースコード
#pragma region Macros#pragma GCC target("avx,avx2,fma")#pragma GCC optimize("O3")#pragma GCC optimize("unroll-loops")#include <bits/extc++.h>using namespace std;using namespace __gnu_pbds;// using namespace __gnu_cxx;// #include <boost/multiprecision/cpp_int.hpp>// namespace mp = boost::multiprecision;// using Bint = mp::cpp_int;#define TO_STRING(var) # var#define pb emplace_back#define int ll#define endl '\n'using ll = long long;using ld = long double;const ld PI = acos(-1);const ld EPS = 1e-10;const int INF = 1 << 30;const ll INFL = 1LL << 61;// const int MOD = 998244353;const int MOD = 1000000007;__attribute__((constructor))void constructor() {ios::sync_with_stdio(false);cin.tie(nullptr);// ifstream in("input.txt");// cin.rdbuf(in.rdbuf());cout << fixed << setprecision(15);}class UnionFind {public:UnionFind() = default;UnionFind(int n) : par(n),sz(n, 1) { iota(par.begin(), par.end(), 0); }int root(int x) {if (par[x] == x) return x;return (par[x] = root(par[x]));}bool unite(int x, int y) {int rx = root(x);int ry = root(y);if (rx == ry) return false;if (sz[rx] < sz[ry]) swap(rx, ry);sz[rx] += sz[ry];par[ry] = rx;return true;}bool issame(int x, int y) {return (root(x) == root(y));}int size(int x) {return sz[root(x)];}int get_sum(int x) {return sum[root(x)];}vector<vector<int>> groups(int n) {vector<vector<int>> G(n);for (int x = 0; x < n; x++) {G[root(x)].push_back(x);}G.erase(remove_if(G.begin(), G.end(),[&](const vector<int>& v) { return v.empty(); }),G.end());return G;}private:vector<int> par;vector<int> sz;vector<int> sum;};template<int mod> class modint{public:int val = 0;modint(int x = 0) { while (x < 0) x += mod; val = x % mod; }modint(const modint &r) { val = r.val; }modint operator -() { return modint(-val); }modint operator +(const modint &r) { return modint(*this) += r; }modint operator +(const int &q) {modint r(q); return modint(*this) += r; }modint operator -(const modint &r) { return modint(*this) -= r; }modint operator -(const int &q) {modint r(q); return modint(*this) -= r; }modint operator *(const modint &r) { return modint(*this) *= r; }modint operator *(const int &q) {modint r(q); return modint(*this) *= r; }modint operator /(const modint &r) { return modint(*this) /= r; }modint operator /(const int &q) {modint r(q); return modint(*this) /= r; }modint &operator +=(const modint &r) {val += r.val;if (val >= mod) val -= mod;return *this;}modint &operator -=(const modint &r) {if (val < r.val) val += mod;val -= r.val;return *this;}modint &operator *=(const modint &r) {val = val * r.val % mod;return *this;}modint &operator /=(const modint &r) {int a = r.val, b = mod, u = 1, v = 0;while (b) {int t = a / b;a -= t * b; swap(a, b);u -= t * v; swap(u, v);}val = val * u % mod;if (val < 0) val += mod;return *this;}bool operator ==(const modint& r) { return this -> val == r.val; }bool operator <(const modint& r) { return this -> val < r.val; }bool operator !=(const modint& r) { return this -> val != r.val; }};using mint = modint<MOD>;istream &operator >>(istream &is, mint& x) {int t; is >> t;x = t;return (is);}ostream &operator <<(ostream &os, const mint& x) {return os << x.val;}mint modpow(const mint &a, int n) {if (n == 0) return 1;mint t = modpow(a, n / 2);t = t * t;if (n & 1) t = t * a;return t;}int modpow(int x, int n, int mod) {int ret = 1;while (n > 0) {if (n % 2 == 1) ret = ret * x % mod;x = x * x % mod;n /= 2;}return ret;}int ceil(int x, int y) { return (x > 0 ? (x + y - 1) / y : x / y); }#pragma endregionsigned main() {string S;cin >> S;string T = S;reverse(T.begin(),T.end());int N = S.size();for (int i = 0; i < N; i++) {S += '?';}int ma = 0;for (int i = 0; i < N; i++) {int r = N - 1 + i;int len = 0;for (int j = 0; j < N; j++) {if (S[r - j] == T[N - 1 - j]) len++;else if (S[r - j] == '?') continue;else break;}ma = max(ma, len);}// cout << ma << endl;for (int i = 0; i < N; i++) {cout << S[i];}for (int i = ma; i < N; i++) {cout << T[i];}cout << endl;}