結果
問題 | No.1097 Remainder Operation |
ユーザー |
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提出日時 | 2023-03-17 13:05:44 |
言語 | Java (openjdk 23) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,436 bytes |
コンパイル時間 | 2,643 ms |
コンパイル使用メモリ | 91,868 KB |
実行使用メモリ | 123,772 KB |
最終ジャッジ日時 | 2024-09-18 09:56:40 |
合計ジャッジ時間 | 13,676 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 WA * 1 |
other | AC * 2 WA * 19 |
ソースコード
import java.io.*;import java.util.*;import java.util.stream.*;public class Main {public static void main(String[] args) throws Exception {Scanner sc = new Scanner();int n = sc.nextInt();int[][] nexts = new int[40][n];long[][] values = new long[40][n];for (int i = 0; i < n; i++) {values[0][i] = sc.nextInt();nexts[0][i] = (int)(values[0][i] % n);}for (int i = 1; i < 40; i++) {for (int j = 0; j < n; j++) {values[i][j] = values[i - 1][j] + values[i - 1][nexts[i - 1][j]];nexts[i][j] = (int)(values[i][j] % n);}}int q = sc.nextInt();StringBuilder sb = new StringBuilder();while (q-- > 0) {long k = sc.nextLong();long ans = 0;int current = 0;for (int i = 39; i >= 0; i--) {if (k >= (1L << i)) {k -= (1L << i);ans += values[i][current];current = nexts[i][current];}}sb.append(ans).append("\n");}System.out.print(sb);}}class Utilities {static String arrayToLineString(Object[] arr) {return Arrays.stream(arr).map(x -> x.toString()).collect(Collectors.joining("\n"));}static String arrayToLineString(int[] arr) {return String.join("\n", Arrays.stream(arr).mapToObj(String::valueOf).toArray(String[]::new));}}class Scanner {BufferedReader br = new BufferedReader(new InputStreamReader(System.in));StringTokenizer st = new StringTokenizer("");StringBuilder sb = new StringBuilder();public Scanner() throws Exception {}public int nextInt() throws Exception {return Integer.parseInt(next());}public long nextLong() throws Exception {return Long.parseLong(next());}public double nextDouble() throws Exception {return Double.parseDouble(next());}public int[] nextIntArray() throws Exception {return Stream.of(br.readLine().split(" ")).mapToInt(Integer::parseInt).toArray();}public String next() throws Exception {while (!st.hasMoreTokens()) {st = new StringTokenizer(br.readLine());}return st.nextToken();}}