結果

問題 No.2247 01 ZigZag
ユーザー 👑 p-adicp-adic
提出日時 2023-03-17 22:20:08
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
(最新)
AC  
(最初)
実行時間 -
コード長 7,304 bytes
コンパイル時間 3,658 ms
コンパイル使用メモリ 217,804 KB
実行使用メモリ 4,348 KB
最終ジャッジ日時 2023-10-18 20:13:59
合計ジャッジ時間 4,508 ms
ジャッジサーバーID
（参考情報） 		judge13 / judge12
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
4,348 KB
testcase_01 AC 2 ms
4,348 KB
testcase_02 AC 2 ms
4,348 KB
testcase_03 AC 5 ms
4,348 KB
testcase_04 AC 1 ms
4,348 KB
testcase_05 AC 4 ms
4,348 KB
testcase_06 AC 4 ms
4,348 KB
testcase_07 AC 2 ms
4,348 KB
testcase_08 AC 7 ms
4,348 KB
testcase_09 AC 5 ms
4,348 KB
testcase_10 AC 2 ms
4,348 KB
testcase_11 AC 4 ms
4,348 KB
testcase_12 AC 5 ms
4,348 KB
testcase_13 AC 4 ms
4,348 KB
testcase_14 AC 2 ms
4,348 KB
testcase_15 AC 5 ms
4,348 KB
testcase_16 AC 7 ms
4,348 KB
testcase_17 AC 7 ms
4,348 KB
testcase_18 AC 2 ms
4,348 KB
testcase_19 AC 1 ms
4,348 KB
testcase_20 AC 2 ms
4,348 KB
testcase_21 AC 3 ms
4,348 KB
testcase_22 AC 8 ms
4,348 KB
testcase_23 AC 4 ms
4,348 KB
testcase_24 AC 2 ms
4,348 KB
testcase_25 AC 7 ms
4,348 KB
testcase_26 AC 6 ms
4,348 KB
testcase_27 AC 6 ms
4,348 KB
testcase_28 AC 8 ms
4,348 KB
testcase_29 AC 6 ms
4,348 KB
testcase_30 AC 8 ms
4,348 KB
testcase_31 AC 2 ms
4,348 KB
testcase_32 AC 7 ms
4,348 KB
testcase_33 AC 6 ms
4,348 KB
testcase_34 AC 5 ms
4,348 KB
testcase_35 AC 4 ms
4,348 KB
testcase_36 AC 5 ms
4,348 KB
testcase_37 AC 2 ms
4,348 KB
testcase_38 AC 3 ms
4,348 KB
testcase_39 AC 4 ms
4,348 KB
testcase_40 AC 2 ms
4,348 KB
testcase_41 AC 6 ms
4,348 KB
testcase_42 AC 6 ms
4,348 KB
testcase_43 AC 1 ms
4,348 KB
testcase_44 AC 2 ms
4,348 KB
testcase_45 AC 10 ms
4,348 KB
testcase_46 AC 10 ms
4,348 KB
testcase_47 AC 2 ms
4,348 KB
testcase_48 AC 2 ms
4,348 KB
testcase_49 AC 2 ms
4,348 KB
testcase_50 AC 2 ms
4,348 KB
testcase_51 WA -
権限があれば一括ダウンロードができます

ソースコード

diff # 

#pragma GCC optimize ( "O3" )
#pragma GCC optimize( "unroll-loops" )
#pragma GCC target ( "sse4.2,fma,avx2,popcnt,lzcnt,bmi2" )
#include <bits/stdc++.h>
using namespace std;

using ll = long long;
using uint = unsigned int;

#define ATT __attribute__( ( target( "sse4.2,fma,avx2,popcnt,lzcnt,bmi2" ) ) )
#define TYPE_OF( VAR ) remove_const<remove_reference<decltype( VAR )>::type >::type
#define UNTIE ios_base::sync_with_stdio( false ); cin.tie( nullptr )
#define CEXPR( LL , BOUND , VALUE ) constexpr LL BOUND = VALUE
#define CIN( LL , A ) LL A; cin >> A
#define ASSERT( A , MIN , MAX ) assert( ( MIN ) <= A && A <= ( MAX ) )
#define CIN_ASSERT( A , MIN , MAX ) CIN( TYPE_OF( MAX ) , A ); ASSERT( A , MIN , MAX )
#define GETLINE( A ) string A; getline( cin , A )
#define GETLINE_SEPARATE( A , SEPARATOR ) string A; getline( cin , A , SEPARATOR )
#define FOR( VAR , INITIAL , FINAL_PLUS_ONE ) for( TYPE_OF( FINAL_PLUS_ONE ) VAR = INITIAL ; VAR < FINAL_PLUS_ONE ; VAR ++ )
#define FOREQ( VAR , INITIAL , FINAL ) for( TYPE_OF( FINAL ) VAR = INITIAL ; VAR <= FINAL ; VAR ++ )
#define FOREQINV( VAR , INITIAL , FINAL ) for( TYPE_OF( INITIAL ) VAR = INITIAL ; VAR >= FINAL ; VAR -- )
#define FOR_ITR( ARRAY , ITR , END ) for( auto ITR = ARRAY .begin() , END = ARRAY .end() ; ITR != END ; ITR ++ )
#define REPEAT( HOW_MANY_TIMES ) FOR( VARIABLE_FOR_REPEAT , 0 , HOW_MANY_TIMES )
#define QUIT return 0
#define COUT( ANSWER ) cout << ( ANSWER ) << "\n"
#define RETURN( ANSWER ) COUT( ANSWER ); QUIT
#define DOUBLE( PRECISION , ANSWER ) cout << fixed << setprecision( PRECISION ) << ( ANSWER ) << "\n"; QUIT

// ARGUMENTの型がintやuintでないように注意
#define POWER( ANSWER , ARGUMENT , EXPONENT )				\
  TYPE_OF( ARGUMENT ) ANSWER{ 1 };					\
  {									\
    TYPE_OF( ARGUMENT ) ARGUMENT_FOR_SQUARE_FOR_POWER = ( ARGUMENT );	\
    TYPE_OF( EXPONENT ) EXPONENT_FOR_SQUARE_FOR_POWER = ( EXPONENT );	\
    while( EXPONENT_FOR_SQUARE_FOR_POWER != 0 ){			\
      if( EXPONENT_FOR_SQUARE_FOR_POWER % 2 == 1 ){			\
	ANSWER *= ARGUMENT_FOR_SQUARE_FOR_POWER;			\
      }									\
      ARGUMENT_FOR_SQUARE_FOR_POWER *= ARGUMENT_FOR_SQUARE_FOR_POWER;	\
      EXPONENT_FOR_SQUARE_FOR_POWER /= 2;				\
    }									\
  }									\

#define POWER_MOD( ANSWER , ARGUMENT , EXPONENT , MODULO )		\
  ll ANSWER{ 1 };					\
  {									\
    ll ARGUMENT_FOR_SQUARE_FOR_POWER = ( MODULO + ( ( ARGUMENT ) % MODULO ) ) % MODULO; \
    TYPE_OF( EXPONENT ) EXPONENT_FOR_SQUARE_FOR_POWER = ( EXPONENT );	\
    while( EXPONENT_FOR_SQUARE_FOR_POWER != 0 ){			\
      if( EXPONENT_FOR_SQUARE_FOR_POWER % 2 == 1 ){			\
	ANSWER = ( ANSWER * ARGUMENT_FOR_SQUARE_FOR_POWER ) % MODULO;	\
      }									\
      ARGUMENT_FOR_SQUARE_FOR_POWER = ( ARGUMENT_FOR_SQUARE_FOR_POWER * ARGUMENT_FOR_SQUARE_FOR_POWER ) % MODULO; \
      EXPONENT_FOR_SQUARE_FOR_POWER /= 2;				\
    }									\
  }									\

#define FACTORIAL_MOD( ANSWER , ANSWER_INV , INVERSE , MAX_I , LENGTH , MODULO ) \
  static ll ANSWER[LENGTH];						\
  static ll ANSWER_INV[LENGTH];						\
  static ll INVERSE[LENGTH];						\
  {									\
    ll VARIABLE_FOR_PRODUCT_FOR_FACTORIAL = 1;				\
    ANSWER[0] = VARIABLE_FOR_PRODUCT_FOR_FACTORIAL;			\
    FOREQ( i , 1 , MAX_I ){						\
      ANSWER[i] = ( VARIABLE_FOR_PRODUCT_FOR_FACTORIAL *= i ) %= MODULO; \
    }									\
    ANSWER_INV[0] = ANSWER_INV[1] = INVERSE[1] = VARIABLE_FOR_PRODUCT_FOR_FACTORIAL = 1; \
    FOREQ( i , 2 , MAX_I ){						\
      ANSWER_INV[i] = ( VARIABLE_FOR_PRODUCT_FOR_FACTORIAL *= INVERSE[i] = MODULO - ( ( ( MODULO / i ) * INVERSE[MODULO % i] ) % MODULO ) ) %= MODULO; \
    }									\
  }									\

// 通常の二分探索（単調関数-目的値が一意実数解を持つ場合にそれを超えない最大の整数を返す）
#define BS( ANSWER , MINIMUM , MAXIMUM , EXPRESSION , TARGET )		\
  ll ANSWER;								\
  {									\
    ll VARIABLE_FOR_BINARY_SEARCH_L = MINIMUM;				\
    ll VARIABLE_FOR_BINARY_SEARCH_U = MAXIMUM + 1;				\
    ANSWER = ( VARIABLE_FOR_BINARY_SEARCH_L + VARIABLE_FOR_BINARY_SEARCH_U ) / 2; \
    ll VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( TARGET ) - ( EXPRESSION ); \
    if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH == 0 ){		\
      VARIABLE_FOR_BINARY_SEARCH_L = ANSWER;				\
    } else {								\
      ANSWER = ( VARIABLE_FOR_BINARY_SEARCH_L + VARIABLE_FOR_BINARY_SEARCH_U ) / 2; \
    }									\
    while( VARIABLE_FOR_BINARY_SEARCH_L != ANSWER ){			\
      VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( TARGET ) - ( EXPRESSION ); \
      if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH == 0 ){		\
	break;								\
      } else {								\
	if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH > 0 ){		\
	  VARIABLE_FOR_BINARY_SEARCH_L = ANSWER;			\
	} else {							\
	  VARIABLE_FOR_BINARY_SEARCH_U = ANSWER;			\
	}								\
	ANSWER = ( VARIABLE_FOR_BINARY_SEARCH_L + VARIABLE_FOR_BINARY_SEARCH_U ) / 2; \
      }									\
    }									\
  }									\
									\

// 二進法の二分探索（単調関数-目的値が一意実数解を持つ場合にそれを超えない最大の整数を返す）
#define BS2( ANSWER , MINIMUM , MAXIMUM , EXPRESSION , TARGET )		\
  ll ANSWER = MINIMUM;							\
  {									\
    ll VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 = 1;			\
    ll VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( MAXIMUM ) - ANSWER; \
    while( VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 <= VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH ){ \
      VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 *= 2;			\
    }									\
    VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 /= 2;			\
    ll VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 = ANSWER;		\
    while( VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 != 0 ){		\
      ANSWER = VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 + VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2; \
      VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH = ( TARGET ) - ( EXPRESSION ); \
      if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH == 0 ){		\
	VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 = ANSWER;		\
	break;								\
      } else if( VARIABLE_FOR_DIFFERENCE_FOR_BINARY_SEARCH > 0 ){	\
	VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2 = ANSWER;		\
      }									\
      VARIABLE_FOR_POWER_FOR_BINARY_SEARCH_2 /= 2;			\
    }									\
    ANSWER = VARIABLE_FOR_ANSWER_FOR_BINARY_SEARCH_2;			\
  }									\
									\


template <typename T> inline T Absolute( const T& a ){ return a > 0 ? a : -a; }
template <typename T> inline T Residue( const T& a , const T& p ){ return a >= 0 ? a % p : p - 1 - ( ( - ( a + 1 ) ) % p ); }

int main()
{
  UNTIE;
  CIN( int , N );
  CIN( int , M );
  CIN( int , K );
  if( K % 2 == 0 ){
    if( N == K / 2 ){
      if( M < ( K / 2 ) + 1 ){
	RETURN( -1 );
      }
      FOR( i , 0 , K ){
	cout << ( i % 2 == 0 ? 1 : 0 );
      }
      FOR( i , K / 2 , M ){
	cout << 1;
      }
      RETURN( "" );
    }
    if( N < ( K / 2 ) + 1 || M < ( K / 2 ) ){
      RETURN( -1 );
    }
    FOR( i , ( K / 2 ) + 1 , N ){
      cout << 0;
    }
    FOR( i , 0 , K ){
      cout << ( i % 2 == 0 ? 0 : 1 );
    }
    FOR( i , K / 2 , M ){
      cout << 1;
    }
    RETURN( 0 );
  }
  if( N < ( K + 1 ) / 2 || M < ( K + 1 ) / 2 ){
    RETURN( -1 );
  }
  FOR( i , ( K + 1 ) / 2 , N ){
    cout << 0;
  }
  FOREQ( i , 0 , K ){
    cout << ( i % 2 == 0 ? 0 : 1 );
  }
  FOR( i , ( K + 1 ) / 2 , M ){
    cout << 1;
  }
  RETURN( "" );
}
0