結果

問題 No.1973 Divisor Sequence
ユーザー mkawa2
提出日時 2023-03-18 21:22:42
言語 PyPy3
(7.3.15)
結果
TLE  
実行時間 -
コード長 1,891 bytes
コンパイル時間 396 ms
コンパイル使用メモリ 82,096 KB
実行使用メモリ 464,256 KB
最終ジャッジ日時 2024-09-18 13:35:31
合計ジャッジ時間 7,531 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
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ファイルパターン 結果
sample AC * 3
other AC * 20 TLE * 2
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
# sys.setrecursionlimit(200005)
int1 = lambda x: int(x)-1
pDB = lambda *x: print(*x, end="\n", file=sys.stderr)
p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr)
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()
dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
inf = (1 << 63)-1
# inf = (1 << 31)-1
md = 10**9+7
# md = 998244353
# 行列累乗バージョン
def factors(a):
    if a <= 0: return [0]
    dd0, dd1 = [], []
    for d in range(1, round(a**0.5)+1):
        if a%d: continue
        dd0.append(d)
        dd1.append(a//d)
    if dd0[-1] == dd1[-1]: dd1.pop()
    return dd0+dd1[::-1]
def dot(aa, bb):
    h = len(aa)
    w = len(bb[0])
    res = [[0]*w for _ in range(h)]
    for j, col in enumerate(zip(*bb)):
        for i in range(h):
            v = 0
            # for a, b in zip(row, col): v += a*b
            # res[i][j] = v
            for a, b in zip(aa[i], col):
                v += a*b%md
                v %= md
            res[i][j] = v
    return res
def matpow(mat, e):
    n = len(mat)
    res = [[1 if i == j else 0 for j in range(n)] for i in range(n)]
    while e:
        if e & 1: res = dot(res, mat)
        mat = dot(mat, mat)
        e >>= 1
    return res
n, m = LI()
ff = factors(m)
fn = len(ff)
mat = [[0]*fn for _ in range(fn)]
for i in range(fn):
    for j in range(fn):
        if m//ff[i]%ff[j] == 0:
            mat[i][j] = 1
mat = matpow(mat, n-1)
ans = 0
for row in mat:
    for a in row:
        ans += a
        ans %= md
print(ans)
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