結果

問題 No.1973 Divisor Sequence
ユーザー mkawa2mkawa2
提出日時 2023-03-19 00:09:37
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 101 ms / 2,000 ms
コード長 2,104 bytes
コンパイル時間 153 ms
コンパイル使用メモリ 81,856 KB
実行使用メモリ 75,824 KB
最終ジャッジ日時 2023-10-18 17:37:16
合計ジャッジ時間 2,383 ms
ジャッジサーバーID
(参考情報)
judge14 / judge13
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 37 ms
53,572 KB
testcase_01 AC 37 ms
53,572 KB
testcase_02 AC 42 ms
59,512 KB
testcase_03 AC 43 ms
59,512 KB
testcase_04 AC 42 ms
59,512 KB
testcase_05 AC 47 ms
59,512 KB
testcase_06 AC 39 ms
53,572 KB
testcase_07 AC 44 ms
59,512 KB
testcase_08 AC 42 ms
59,512 KB
testcase_09 AC 44 ms
59,512 KB
testcase_10 AC 44 ms
61,628 KB
testcase_11 AC 39 ms
53,572 KB
testcase_12 AC 41 ms
59,512 KB
testcase_13 AC 44 ms
59,896 KB
testcase_14 AC 49 ms
63,980 KB
testcase_15 AC 43 ms
59,368 KB
testcase_16 AC 41 ms
59,456 KB
testcase_17 AC 46 ms
61,780 KB
testcase_18 AC 47 ms
61,964 KB
testcase_19 AC 46 ms
61,944 KB
testcase_20 AC 42 ms
59,512 KB
testcase_21 AC 41 ms
59,512 KB
testcase_22 AC 42 ms
59,512 KB
testcase_23 AC 101 ms
75,824 KB
testcase_24 AC 53 ms
66,232 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

import sys

# sys.setrecursionlimit(200005)
int1 = lambda x: int(x)-1
pDB = lambda *x: print(*x, end="\n", file=sys.stderr)
p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr)
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()

dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
inf = (1 << 63)-1
# inf = (1 << 31)-1
md = 10**9+7
# md = 998244353


# 行列累乗バージョン

def prime_factorization(a):
    pp, ee = [], []
    if a & 1 == 0:
        pp += [2]
        ee += [0]
        while a & 1 == 0:
            a >>= 1
            ee[-1] += 1
    p = 3
    while p**2 <= a:
        if a%p == 0:
            pp += [p]
            ee += [0]
            while a%p == 0:
                a //= p
                ee[-1] += 1
        p += 2
    if a > 1:
        pp += [a]
        ee += [1]
    return pp, ee

def dot(aa, bb):
    h = len(aa)
    w = len(bb[0])
    res = [[0]*w for _ in range(h)]
    for j, col in enumerate(zip(*bb)):
        for i in range(h):
            v = 0
            # for a, b in zip(row, col): v += a*b
            # res[i][j] = v
            for a, b in zip(aa[i], col): v += a*b%md
            res[i][j] = v%md
    return res

def matpow(mat, e):
    n = len(mat)
    res = [[1 if i == j else 0 for j in range(n)] for i in range(n)]
    while e:
        if e & 1: res = dot(res, mat)
        mat = dot(mat, mat)
        e >>= 1
    return res

n, m = LI()

ans = 1
_, ee = prime_factorization(m)
for e in ee:
    mat = [[0]*(e+1) for _ in range(e+1)]
    for i in range(e+1):
        for j in range(e+1):
            if i+j <= e: mat[i][j] = 1
    mat = matpow(mat, n-1)
    s = 0
    for row in mat:
        for a in row:
            s += a
            s %= md
    ans = ans*s%md

print(ans)
0