結果

問題 No.125 悪の花弁
ユーザー mkawa2
提出日時 2023-03-20 15:48:09
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 163 ms / 5,000 ms
コード長 1,949 bytes
コンパイル時間 199 ms
コンパイル使用メモリ 81,920 KB
実行使用メモリ 169,860 KB
最終ジャッジ日時 2024-09-18 14:06:37
合計ジャッジ時間 1,520 ms
ジャッジサーバーID
(参考情報)
judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 6
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys
# sys.setrecursionlimit(200005)
int1 = lambda x: int(x)-1
pDB = lambda *x: print(*x, end="\n", file=sys.stderr)
p2D = lambda x: print(*x, sep="\n", end="\n\n", file=sys.stderr)
def II(): return int(sys.stdin.readline())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LI1(): return list(map(int1, sys.stdin.readline().split()))
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def SI(): return sys.stdin.readline().rstrip()
dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
inf = (1 << 63)-1
# inf = (1 << 31)-1
md = 10**9+7
# md = 998244353
def factors(a):
if a <= 0: return [0]
dd0, dd1 = [], []
for d in range(1, round(a**0.5)+1):
if a%d: continue
dd0.append(d)
dd1.append(a//d)
if dd0[-1] == dd1[-1]: dd1.pop()
return dd0+dd1[::-1]
def nPr(com_n, com_r):
if com_r < 0: return 0
if com_n < com_r: return 0
return fac[com_n]*ifac[com_n-com_r]%md
def nCr(com_n, com_r):
if com_r < 0: return 0
if com_n < com_r: return 0
return fac[com_n]*ifac[com_r]%md*ifac[com_n-com_r]%md
n_max = 1000005
fac = [1]
for i in range(1, n_max+1): fac.append(fac[-1]*i%md)
ifac = [1]*(n_max+1)
ifac[n_max] = pow(fac[n_max], md-2, md)
for i in range(n_max-1, 1, -1): ifac[i] = ifac[i+1]*(i+1)%md
from math import gcd
k = LI()
cc = LI()
s = sum(cc)
g = 0
for c in cc: g = gcd(g, c)
ff = factors(g)[::-1]
rr = [s//f for f in ff]
rn = len(rr)
# print(rr)
# print(ff)
for i in range(rn)[::-1]:
for j in range(i+1, rn):
if rr[j]%rr[i] == 0: ff[i] -= ff[j]
# print(rr)
# print(ff)
ans = 0
for r, f in zip(rr, ff):
p = s//r
cur = 1
for c in cc:
c //= p
cur *= nCr(r, c)
cur %= md
r -= c
ans += cur*f%md
ans %= md
ans *= pow(s, md-2, md)
print(ans%md)
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