結果

問題 No.2249 GCDistance
ユーザー unti
提出日時 2023-03-23 14:10:25
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 1,547 ms / 5,000 ms
コード長 6,961 bytes
コンパイル時間 3,038 ms
コンパイル使用メモリ 229,520 KB
最終ジャッジ日時 2025-02-11 16:28:51
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 1
other AC * 10
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
using namespace std;
using ll = long long int ;
using ld = long double ;
using P = pair<ll,ll>;
using Graph= vector<vector<ll>>;
struct edge{ll to ; ll cost ;} ;
using graph =vector<vector<edge>> ;
#define rep(i,n) for (ll i=0; i < (n); ++i)
#define rep2(i,n,m) for(ll i=n;i<=m;i++)
#define rep3(i,n,m) for(ll i=n;i>=m;i--)
#define pb push_back
#define eb emplace_back
#define ppb pop_back
#define mpa make_pair
#define fi first
#define se second
#define set20 cout<<fixed<<setprecision(20) ;
const ll INF=1e18 ;
inline void chmax(ll& a,ll b){a=max(a,b);}
inline void chmin(ll& a,ll b){a=min(a,b);}
long double pi=acos(-1) ;
ll gcd(ll a, ll b) { return b?gcd(b,a%b):a;}
ll lcm(ll a, ll b) { return a/gcd(a,b)*b;}
ll dx[4] {1,0,-1,0} ;
ll dy[4] {0,1,0,-1} ;
#define debug cout<<888<<endl ;
//
//int mod ; //modconst
const int mod =//1e9+7 ;//924844033;
998244353;
struct mint {
ll x; // typedef long long ll;
mint(ll x=0):x((x%mod+mod)%mod){}
mint operator-() const { return mint(-x);}
mint& operator+=(const mint a) {
if ((x += a.x) >= mod) x -= mod;
return *this;
}
mint& operator-=(const mint a) {
if ((x += mod-a.x) >= mod) x -= mod;
return *this;
}
mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}
mint operator+(const mint a) const { return mint(*this) += a;}
mint operator-(const mint a) const { return mint(*this) -= a;}
mint operator*(const mint a) const { return mint(*this) *= a;}
mint pow(ll t) const {
if (!t) return 1;
mint a = pow(t>>1);
a *= a;
if (t&1) a *= *this;
return a;
}
// for prime mod
mint inv() const { return pow(mod-2);}
mint& operator/=(const mint a) { return *this *= a.inv();}
mint operator/(const mint a) const { return mint(*this) /= a;}
};
istream& operator>>(istream& is, const mint& a) { return is >> a.x;}
ostream& operator<<(ostream& os, const mint& a) { return os << a.x;}
//
struct combination {
vector<mint> fact, ifact;
combination(int n):fact(n+1),ifact(n+1) {
//assert(n < mod); //modcombmain
fact[0] = 1;
for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;
ifact[n] = fact[n].inv();
for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;
}
mint operator()(int n, int k) {
if (k < 0 || k > n) return 0;
return fact[n]*ifact[k]*ifact[n-k];
}
mint p(int n,int k){
return fact[n]*ifact[n-k] ; //k
}
} co(1000005)
;
mint modpow(ll a,ll b){
if(b==0) return 1 ;
mint c= modpow(a,b/2) ;
if(b%2==1) return c*c*a ;
else return c*c ;
}
mint mmodpow(mint a,ll b){
if(b==0) return 1ll ;
mint c=mmodpow(a,(b/2)) ;
if(b%2==1) return c*c*a ;
else return c*c ;
}
mint komb(ll n,ll m){
mint x=1 ;mint y=1 ;
rep(i,m){
x*= n-i ;
y*= i+1 ;
}
return x/y ;
}
map<ll,ll> factor(ll n){ //
map <ll,ll> ord ;
for(ll i=2;i*i<=n;i++){
if(n%i==0){
int res=0;
while(n%i==0){
n/=i;
res++;
}
ord[i]=res;
}
}
if(n!=1) ord[n]++;
return ord ;
}
struct UnionFind {
vector<int> d;
UnionFind(int n=0): d(n,-1) {}
int find(int x) {
if (d[x] < 0) return x;
return d[x] = find(d[x]);
}
bool unite(int x, int y) {
x = find(x); y = find(y);
if (x == y) return false;
if (d[x] > d[y]) swap(x,y);
d[x] += d[y];
d[y] = x;
return true;
}
bool same(int x, int y) { return find(x) == find(y);}
int size(int x) { return -d[find(x)];}
};
// sum(x) x
// sum(a,b) ab
template<typename T>
struct BIT {
int n;
vector<T> d;
BIT(int n=0):n(n),d(n+1) {}
void add(int i, T x=1) { //x=1sum
for (i++; i <= n; i += i&-i) {
d[i] += x;
}
}
T sum(int i) {
T x = 0;
for (i++; i; i -= i&-i) {
x += d[i];
}
return x;
}
T sum(int i,int j) {
if(i>0) return sum(j)-sum(i-1);
else return sum(j); }
};
vector<ll> alldiv(ll n){
vector<ll> ans;
if(n<0) n*=-1;
for(ll i=1;i*i<=n;++i){
if(n%i==0){
if(i*i==n) ans.pb(i);
else{ans.pb(i);ans.pb(n/i);}
}
}
return ans;
}
struct SuffixArray {
vector< int > SA;
const string s;
SuffixArray(const string &str) : s(str) {
SA.resize(s.size());
iota(begin(SA), end(SA), 0);
sort(begin(SA), end(SA), [&](int a, int b) {
return s[a] == s[b] ? a > b : s[a] < s[b];
});
vector< int > classes(s.size()), c(s.begin(), s.end()), cnt(s.size());
for(int len = 1; len < s.size(); len <<= 1) {
for(int i = 0; i < s.size(); i++) {
if(i > 0 && c[SA[i - 1]] == c[SA[i]] && SA[i - 1] + len < s.size() && c[SA[i - 1] + len / 2] == c[SA[i] + len / 2]) {
classes[SA[i]] = classes[SA[i - 1]];
} else {
classes[SA[i]] = i;
}
}
iota(begin(cnt), end(cnt), 0);
copy(begin(SA), end(SA), begin(c));
for(int i = 0; i < s.size(); i++) {
int s1 = c[i] - len;
if(s1 >= 0) SA[cnt[classes[s1]]++] = s1;
}
classes.swap(c);
}
}
int operator[](int k) const {
return SA[k];
}
size_t size() const {
return s.size();
}
bool lt_substr(const string &t, int si = 0, int ti = 0) {
int sn = (int) s.size(), tn = (int) t.size();
while(si < sn && ti < tn) {
if(s[si] < t[ti]) return true;
if(s[si] > t[ti]) return false;
++si, ++ti;
}
return si >= sn && ti < tn;
}
int lower_bound(const string &t) {
int low = -1, high = (int) SA.size();
while(high - low > 1) {
int mid = (low + high) / 2;
if(lt_substr(t, SA[mid])) low = mid;
else high = mid;
}
return high;
}
pair< int, int > lower_upper_bound(string &t) {
int idx = lower_bound(t);
int low = idx - 1, high = (int) SA.size();
t.back()++;
while(high - low > 1) {
int mid = (low + high) / 2;
if(lt_substr(t, SA[mid])) low = mid;
else high = mid;
}
t.back()--;
return {idx, high};
}
void output() {
for(int i = 0; i < size(); i++) {
cout << i << ": " << s.substr(SA[i]) << endl;
}
}
};
int main(){
ios::sync_with_stdio(false) ;
cin.tie(nullptr) ;
ll MA=1e7+5;
vector<ll> ans(MA+1);
vector<bool> ch(MA+1);
vector<ll> p;
rep2(i,2,MA){
if(ch[i]) continue;
p.pb(i);
for(ll j=1; i*j<MA; ++j){
ch[i*j]=true;
}
}
rep2(i,1,MA){
ans[i]=i;
}
for(auto u:p){
for(ll j=1; u*j<MA; ++j){
ans[u*j]/=u;
ans[u*j]*=(u-1);
}
}
vector<ll> cum(MA+1);
cum[0]=0ll;
rep2(i,1,MA) cum[i]=cum[i-1]+ans[i];
ll t; cin>>t;
while(t--){
ll n; cin>>n;
ll num=n*(n-1);
num-=cum[n];
cout<<num+1<<endl;
}
return 0;
}
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0