結果

問題 No.219 巨大数の概算
ユーザー karinohito
提出日時 2023-03-24 21:22:23
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 33 ms / 1,500 ms
コード長 2,856 bytes
コンパイル時間 1,851 ms
コンパイル使用メモリ 197,836 KB
最終ジャッジ日時 2025-02-11 16:54:57
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 51
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
//#include <atcoder/all>
//using namespace atcoder;
using ll = long long;
using vll = vector<ll>;
using vvll = vector<vll>;
using vvvll = vector<vvll>;
#define all(A) A.begin(),A.end()
#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)
template<class T>
bool chmax(T& p, T q, bool C = 1) {
if (C == 0 && p == q) {
return 1;
}
if (p < q) {
p = q;
return 1;
}
else {
return 0;
}
}
template<class T>
bool chmin(T& p, T q, bool C = 1) {
if (C == 0 && p == q) {
return 1;
}
if (p > q) {
p = q;
return 1;
}
else {
return 0;
}
}
ll modPow(long long a, long long n, long long p) {
if (n == 0) return 1; // 0
if (n == 1) return a % p;
if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p;
long long t = modPow(a, n / 2, p);
return (t * t) % p;
}
ll gcd(ll(a), ll(b)) {
if (a == 0)return b;
if (b == 0)return a;
ll c = a;
while (a % b != 0) {
c = a % b;
a = b;
b = c;
}
return b;
}
ll sqrtz(ll N) {
ll L = 0;
ll R = sqrt(N) + 10000;
while (abs(R - L) > 1) {
ll mid = (R + L) / 2;
if (mid * mid <= N)L = mid;
else R = mid;
}
return L;
}
/*
using mint = modint1000000007;
using vm = vector<mint>;
using vvm = vector<vm>;
using vvvm = vector<vvm>;
*/
vector<ll> fact, factinv, inv;
const ll mod = 1e9 + 7;
void prenCkModp(ll n) {
fact.resize(n + 5);
factinv.resize(n + 5);
inv.resize(n + 5);
fact[0] = fact[1] = 1;
factinv[0] = factinv[1] = 1;
inv[1] = 1;
for (ll i = 2; i < n + 5; i++) {
fact[i] = (fact[i - 1] * i) % mod;
inv[i] = ((mod - ((inv[mod % i] * (mod / i))) % mod) + mod) % mod;
factinv[i] = (factinv[i - 1] * inv[i]) % mod;
}
}
ll nCk(ll n, ll k) {
if (n < k || k < 0) return 0;
return (fact[n] * ((factinv[k] * factinv[n - k]) % mod)) % mod;
}
ll N,K;
ll score(vll &A){
ll res=0;
rep(i,N){
res+=abs(A[i]-i);
}
return res;
}
ll D(ll x,vll &A){
return abs(x-A[x]);
}
void pr(ll i,ll j,ll k,ll l,ll v){
cout<<i+1<<" "<<j+1<<" "<<k+1<<" "<<l+1<<" "<<v<<endl;
return;
}
bool DEBUG=0;
using ld=long double;
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
ll N;
cin>>N;
rep(i,N){
ld A,B;
cin>>A>>B;
ld M=B*log10(A);
ll Z=floor(M);
ld m=-1;
ll d=-1;
ld EPS=1e-19;
rep(i,101){
if(i<10)continue;
m=ld(i)/10.0;
m=log10(m);
d=i-1;
if(m+ld(Z)>M+EPS){
if(i==10)Z--;
break;
}
}
cout<<d/10<<" "<<d%10<<" "<<Z<<endl;
}
}
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