結果
| 問題 | No.1983 [Cherry 4th Tune C] 南の島のマーメイド |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-03-31 00:31:55 |
| 言語 | Go (1.23.4) |
| 結果 |
AC
|
| 実行時間 | 557 ms / 4,000 ms |
| コード長 | 4,635 bytes |
| 記録 | |
| コンパイル時間 | 13,135 ms |
| コンパイル使用メモリ | 235,100 KB |
| 実行使用メモリ | 86,324 KB |
| 最終ジャッジ日時 | 2024-09-22 08:35:53 |
| 合計ジャッジ時間 | 27,402 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| other | AC * 41 |
ソースコード
package main
import (
"bufio"
"fmt"
"os"
"strings"
)
func criticalConnections(n int, connections [][]int) [][]int {
g := make([][]Edge, n)
for i := 0; i < len(connections); i++ {
u, v := connections[i][0], connections[i][1]
g[u] = append(g[u], Edge{from: u, to: v})
g[v] = append(g[v], Edge{from: v, to: u})
}
lowLink := NewLowLink(g)
lowLink.Build()
res := [][]int{}
for i := 0; i < len(lowLink.Bridge); i++ {
res = append(res, []int{lowLink.Bridge[i].from, lowLink.Bridge[i].to})
}
return res
}
func main() {
yuki1983()
}
func yuki1983() {
// https://yukicoder.me/problems/no/1983
// 给定一个无向图
// 对每个查询a,b,问从a到b的路径是否存在且唯一
// !用并查集把所有的桥的端点合并
// 如果起点终点在一个连通分量内,那么答案就是Yes
in := bufio.NewReader(os.Stdin)
out := bufio.NewWriter(os.Stdout)
defer out.Flush()
var n, m, q int
fmt.Fscan(in, &n, &m, &q)
graph := make([][]Edge, n)
for i := 0; i < m; i++ {
var u, v int
fmt.Fscan(in, &u, &v)
u--
v--
graph[u] = append(graph[u], Edge{u, v})
graph[v] = append(graph[v], Edge{v, u})
}
lowlink := NewLowLink(graph)
lowlink.Build()
uf := NewUnionFindArray(n)
for _, e := range lowlink.Bridge {
uf.Union(e.from, e.to)
}
for i := 0; i < q; i++ {
var a, b int
fmt.Fscan(in, &a, &b)
a, b = a-1, b-1
if uf.IsConnected(a, b) {
fmt.Fprintln(out, "Yes")
} else {
fmt.Fprintln(out, "No")
}
}
}
type Edge = struct{ from, to int }
type LowLink struct {
Articulation []int // 関節点
Bridge []Edge // 橋
g [][]Edge
ord, low []int
used []bool
}
func NewLowLink(g [][]Edge) *LowLink {
return &LowLink{g: g}
}
func (ll *LowLink) Build() {
ll.used = make([]bool, len(ll.g))
ll.ord = make([]int, len(ll.g))
ll.low = make([]int, len(ll.g))
k := 0
for i := 0; i < len(ll.g); i++ {
if !ll.used[i] {
k = ll.dfs(i, k, -1)
}
}
}
func (ll *LowLink) dfs(idx, k, par int) int {
ll.used[idx] = true
ll.ord[idx] = k
k++
ll.low[idx] = ll.ord[idx]
isArticulation := false
beet := false
cnt := 0
for _, e := range ll.g[idx] {
if e.to == par {
tmp := beet
beet = true
if !tmp {
continue
}
}
if !ll.used[e.to] {
cnt++
k = ll.dfs(e.to, k, idx)
ll.low[idx] = min(ll.low[idx], ll.low[e.to])
if par >= 0 && ll.low[e.to] >= ll.ord[idx] {
isArticulation = true
}
if ll.ord[idx] < ll.low[e.to] {
ll.Bridge = append(ll.Bridge, e)
}
} else {
ll.low[idx] = min(ll.low[idx], ll.ord[e.to])
}
}
if par == -1 && cnt > 1 {
isArticulation = true
}
if isArticulation {
ll.Articulation = append(ll.Articulation, idx)
}
return k
}
func min(a, b int) int {
if a < b {
return a
}
return b
}
//
//
func NewUnionFindArray(n int) *UnionFindArray {
parent, rank := make([]int, n), make([]int, n)
for i := 0; i < n; i++ {
parent[i] = i
rank[i] = 1
}
return &UnionFindArray{
Part: n,
rank: rank,
n: n,
parent: parent,
}
}
type UnionFindArray struct {
// 连通分量的个数
Part int
rank []int
n int
parent []int
}
func (ufa *UnionFindArray) Union(key1, key2 int) bool {
root1, root2 := ufa.Find(key1), ufa.Find(key2)
if root1 == root2 {
return false
}
if ufa.rank[root1] > ufa.rank[root2] {
root1, root2 = root2, root1
}
ufa.parent[root1] = root2
ufa.rank[root2] += ufa.rank[root1]
ufa.Part--
return true
}
func (ufa *UnionFindArray) UnionWithCallback(key1, key2 int, cb func(big, small int)) bool {
root1, root2 := ufa.Find(key1), ufa.Find(key2)
if root1 == root2 {
return false
}
if ufa.rank[root1] > ufa.rank[root2] {
root1, root2 = root2, root1
}
ufa.parent[root1] = root2
ufa.rank[root2] += ufa.rank[root1]
ufa.Part--
cb(root2, root1)
return true
}
func (ufa *UnionFindArray) Find(key int) int {
for ufa.parent[key] != key {
ufa.parent[key] = ufa.parent[ufa.parent[key]]
key = ufa.parent[key]
}
return key
}
func (ufa *UnionFindArray) IsConnected(key1, key2 int) bool {
return ufa.Find(key1) == ufa.Find(key2)
}
func (ufa *UnionFindArray) GetGroups() map[int][]int {
groups := make(map[int][]int)
for i := 0; i < ufa.n; i++ {
root := ufa.Find(i)
groups[root] = append(groups[root], i)
}
return groups
}
func (ufa *UnionFindArray) Size(key int) int {
return ufa.rank[ufa.Find(key)]
}
func (ufa *UnionFindArray) String() string {
sb := []string{"UnionFindArray:"}
for root, member := range ufa.GetGroups() {
cur := fmt.Sprintf("%d: %v", root, member)
sb = append(sb, cur)
}
sb = append(sb, fmt.Sprintf("Part: %d", ufa.Part))
return strings.Join(sb, "\n")
}