結果
| 問題 | No.122 傾向と対策:門松列(その3) | 
| コンテスト | |
| ユーザー |  koyumeishi | 
| 提出日時 | 2016-04-04 23:31:43 | 
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) | 
| 結果 | 
                                AC
                                 
                             | 
| 実行時間 | 19 ms / 5,000 ms | 
| コード長 | 3,605 bytes | 
| コンパイル時間 | 1,151 ms | 
| コンパイル使用メモリ | 117,768 KB | 
| 実行使用メモリ | 7,680 KB | 
| 最終ジャッジ日時 | 2024-10-10 23:53:53 | 
| 合計ジャッジ時間 | 1,846 ms | 
| ジャッジサーバーID (参考情報) | judge5 / judge1 | 
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| ファイルパターン | 結果 | 
|---|---|
| other | AC * 8 | 
ソースコード
#include <iostream>
#include <vector>
#include <cstdio>
#include <sstream>
#include <map>
#include <string>
#include <algorithm>
#include <queue>
#include <cmath>
#include <functional>
#include <set>
#include <ctime>
#include <random>
#include <chrono>
#include <cassert>
using namespace std;
namespace my_io{
	template<class T> istream& operator >> (istream& is, vector<T>& vec){for(T& val: vec) is >> val; return is;}
	template<class T> istream& operator ,  (istream& is, T& val){ return is >> val;}
	template<class T> ostream& operator << (ostream& os, const vector<T>& vec){for(int i=0; i<vec.size(); i++) os << vec[i] << (i==vec.size()-1?"":" "); return os;}
	template<class T> ostream& operator ,  (ostream& os, const T& val){ return os << " " << val;}
	template<class T> ostream& operator >> (ostream& os, const T& val){ return os << " " << val;}
	template<class H> void println(const H& head){ cout << head << endl; }
	template<class H, class ... T> void println(const H& head, const T& ... tail){ cout << head << " "; println(tail...); }
}
using namespace my_io;
const long long MOD = 1000000007;
int main(){
	vector<vector<int>> v(7, vector<int>(2));
	cin >> v;
	int low  = 1;
	int high = 20000;
	vector<int> A = {0,2,4,6};
	vector<int> B = {1,3,5};
	long long ans = 0;
	{//A < B
		vector<vector<long long>> dp_A(1<<4, vector<long long>(20005,0));
		vector<vector<char>>   dp_A_ok(1<<4, vector<char>(20005,0));
		vector<vector<long long>> dp_B(1<<3, vector<long long>(20005,0));
		vector<vector<char>>   dp_B_ok(1<<3, vector<char>(20005,0));
		for(int a=low; a<=high; a++){
			for(int k=0; k<(1<<4)-1; k++){
				dp_A[k][a] += dp_A[k][a-1];
				dp_A[k][a] %= MOD;
				for(int x=0; x<4; x++){
					if((k>>x)&1) continue;
					if(a < v[A[x]][0] || v[A[x]][1] < a) continue;
					dp_A[k|(1<<x)][a] += dp_A[k][a-1] + (k==0?1:0);
					dp_A[k|(1<<x)][a] %= MOD;
					dp_A_ok[k|(1<<x)][a] = 1;
				}
			}
		}
		for(int a=high; a>=low; a--){
			for(int k=0; k<(1<<3); k++){
				dp_B[k][a] += dp_B[k][a+1];
				dp_B[k][a] %= MOD;
				for(int x=0; x<3; x++){
					if((k>>x)&1) continue;
					if(a < v[B[x]][0] || v[B[x]][1] < a) continue;
					dp_B[k|(1<<x)][a] += dp_B[k][a+1] + (k==0?1:0);
					dp_B[k|(1<<x)][a] %= MOD;
					dp_B_ok[k|(1<<x)][a] = 1;
				}
			}
		}
		for(int a=low; a<=high; a++){
			if(dp_A_ok[0b1111][a] == 0) continue;
			ans += dp_A[0b1111][a] * dp_B[0b111][a+1] % MOD;
			ans %= MOD;
		}
	}
	{//A > B
		vector<vector<long long>> dp_A(1<<4, vector<long long>(20005,0));
		vector<vector<char>>   dp_A_ok(1<<4, vector<char>(20005,0));
		vector<vector<long long>> dp_B(1<<3, vector<long long>(20005,0));
		vector<vector<char>>   dp_B_ok(1<<3, vector<char>(20005,0));
		for(int a=high; a>=low; a--){
			for(int k=0; k<(1<<4); k++){
				dp_A[k][a] += dp_A[k][a+1];
				dp_A[k][a] %= MOD;
				for(int x=0; x<4; x++){
					if((k>>x)&1) continue;
					if(a < v[A[x]][0] || v[A[x]][1] < a) continue;
					dp_A[k|(1<<x)][a] += dp_A[k][a+1] + (k==0?1:0);
					dp_A[k|(1<<x)][a] %= MOD;
					dp_A_ok[k|(1<<x)][a] = 1;
				}
			}
		}
		for(int a=low; a<=high; a++){
			for(int k=0; k<(1<<3)-1; k++){
				dp_B[k][a] += dp_B[k][a-1];
				dp_B[k][a] %= MOD;
				for(int x=0; x<3; x++){
					if((k>>x)&1) continue;
					if(a < v[B[x]][0] || v[B[x]][1] < a) continue;
					dp_B[k|(1<<x)][a] += dp_B[k][a-1] + (k==0?1:0);
					dp_B[k|(1<<x)][a] %= MOD;
					dp_B_ok[k|(1<<x)][a] = 1;
				}
			}
		}
		for(int a=low; a<=high; a++){
			if(dp_B_ok[0b111][a] == 0) continue;
			ans += dp_B[0b111][a] * dp_A[0b1111][a+1] % MOD;
			ans %= MOD;
		}
	}
	println(ans);
	return 0;
}
            
            
            
        