結果

問題 No.2262 Fractions
ユーザー milanis48663220
提出日時 2023-04-07 23:15:02
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
TLE  
(最新)
AC  
(最初)
実行時間 -
コード長 5,300 bytes
コンパイル時間 1,521 ms
コンパイル使用メモリ 128,472 KB
最終ジャッジ日時 2025-02-12 02:38:56
ジャッジサーバーID
(参考情報)
judge2 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 1
other AC * 23 TLE * 22
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <algorithm>
#include <iomanip>
#include <vector>
#include <queue>
#include <deque>
#include <set>
#include <map>
#include <tuple>
#include <cmath>
#include <numeric>
#include <functional>
#include <cassert>
#define debug_value(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << #x << "=" << x << endl;
#define debug(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << x << endl;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
using namespace std;
typedef long long ll;
template<typename T>
vector<vector<T>> vec2d(int n, int m, T v){
return vector<vector<T>>(n, vector<T>(m, v));
}
template<typename T>
vector<vector<vector<T>>> vec3d(int n, int m, int k, T v){
return vector<vector<vector<T>>>(n, vector<vector<T>>(m, vector<T>(k, v)));
}
template<typename T>
void print_vector(vector<T> v, char delimiter=' '){
if(v.empty()) {
cout << endl;
return;
}
for(int i = 0; i+1 < v.size(); i++) cout << v[i] << delimiter;
cout << v.back() << endl;
}
/**
* dn
* atcodermodintProject Euler使
*/
template <typename T>
class frac{
public:
T n, d;
frac(T _n, T _d){
T g = gcd(_n, _d);
n = _n/g;
d = _d/g;
if(d < 0) {
d *= -1;
n *= -1;
}
}
frac operator+(frac f){
return frac(n*f.d+d*f.n, f.d*d);
}
frac operator-(frac f){
return frac(n*f.d-d*f.n, f.d*d);
}
frac operator*(frac f){
return frac(f.n*n, f.d*d);
}
frac inv(){
return frac(d, n);
}
bool operator<(frac f){
if(d*f.d < 0) return n*f.d-d*f.n > 0;
else return n*f.d-d*f.n < 0;
}
bool operator>(frac f){
if(d*f.d < 0) return n*f.d-d*f.n < 0;
else return n*f.d-d*f.n > 0;
}
bool operator==(frac f){
return n*f.d-d*f.n == 0;
}
void operator+=(frac f){
n = n*f.d+d*f.n, d = f.d*d;
reduction();
}
void operator-=(frac f){
n = n*f.d-d*f.n, d = f.d*d;
reduction();
}
void reduction(){
T g = gcd(n, d);
n /= g, d /= g;
}
};
template <typename T>
bool operator<(const frac<T> f1, const frac<T> f2){
if(f1.d*f2.d < 0) return f1.n*f2.d-f1.d*f2.n > 0;
else return f1.n*f2.d-f1.d*f2.n < 0;
}
template <typename T>
bool operator>(const frac<T> f1, const frac<T> f2){
if(f1.d*f2.d < 0) return f1.n*f2.d-f1.d*f2.n > 0;
else return f1.n*f2.d-f1.d*f2.n > 0;
}
template <typename T>
bool operator==(const frac<T> f1, const frac<T> f2){
return f1.n*f2.d-f1.d*f2.n == 0;
}
template <typename T>
ostream& operator<<(ostream& os, const frac<T>& f){
os << f.n << '/' << f.d;
return os;
}
class Eratosthenes{
public:
int m;
vector<bool> is_prime;
vector<int> primes;
Eratosthenes(int m_){
m = m_;
init();
}
private:
void init(){
is_prime.assign(m+1, true);
is_prime[0] = false, is_prime[1] = false;
for(int i = 2; i <= m; i++){
if(is_prime[i]){
primes.push_back(i);
for(int j = 2; i*j <= m; j++) is_prime[i*j] = false;
}
}
}
};
const int N = 300000;
Eratosthenes et(N);
vector<int> facs[N+1];
int meb[N+1];
void init(){
for(int x = 1; x <= N; x++) meb[x] = 1;
for(int p: et.primes){
for(int i = 1; i*p <= N; i++){
if(i%p == 0){
meb[i*p] = 0;
}else{
meb[i*p] *= -1;
}
}
}
for(int x = 1; x <= N; x++){
if(meb[x] == 0) continue;
for(int i = 1; i*x <= N; i++){
facs[i*x].push_back(x);
}
}
}
using F = frac<ll>;
const int M = 1000000000;
void solve(){
ll n; ll k; cin >> n >> k;
ll sum = 0;
// x/n
auto count = [&](ll x){
ll ans = 0;
for(int i = 1; i <= n; i++){
ll tmp = 0;
for(int j: facs[i]){
ll r = min((x*i)/n, n);
tmp += (ll)meb[j]*(r/j);
}
ans += tmp;
}
return ans;
};
if(count(n*n) < k){
cout << -1 << endl;
return;
}
ll l = 0, r = n*n;
while(r-l > 1){
ll x = (l+r)/2;
if(count(x) < k) l = x;
else r = x;
}
ll cnt_r = count(r);
vector<F> fs;
for(int x = 1; x <= n; x++){
// (l/n) < y/x <= (r/n)
ll yl = (l*x)/n;
if(yl > n) continue;
ll yr = (r*x)/n;
chmin(yr, n);
for(ll y = yl; y <= yr; y++){
if(gcd(x, y) != 1) continue;
fs.push_back(F(y, x));
if(x == 407 && y == 2023){
}
}
}
sort(fs.begin(), fs.end());
ll cur = cnt_r;
while(cur > k){
fs.pop_back();
cur--;
}
cout << fs.back() << endl;
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0);
cout << setprecision(10) << fixed;
init();
int t; cin >> t;
while(t--) solve();
}
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