結果

問題 No.2264 Gear Coloring
ユーザー 🍮かんプリン
提出日時 2023-04-08 23:21:51
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 64 ms / 2,000 ms
コード長 6,187 bytes
コンパイル時間 1,954 ms
コンパイル使用メモリ 182,132 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2024-10-03 20:44:15
合計ジャッジ時間 2,999 ms
ジャッジサーバーID
(参考情報)
judge5 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 4
other AC * 18
権限があれば一括ダウンロードができます
コンパイルメッセージ
main.cpp: In function 'int main()':
main.cpp:214:15: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17' [-Wc++17-extensions]
  214 |     for (auto [p,e] : v) {
      |               ^

ソースコード

diff #
プレゼンテーションモードにする

/**
* @FileName a.cpp
* @Author kanpurin
* @Created 2023.04.08 23:21:45
**/
#include "bits/stdc++.h"
using namespace std;
typedef long long ll;
template< int MOD >
struct mint {
public:
unsigned int x;
mint() : x(0) {}
mint(long long v) {
long long w = (long long)(v % (long long)(MOD));
if (w < 0) w += MOD;
x = (unsigned int)(w);
}
mint(std::string &s) {
unsigned int z = 0;
for (int i = 0; i < s.size(); i++) {
z *= 10;
z += s[i] - '0';
z %= MOD;
}
x = z;
}
mint operator+() const { return *this; }
mint operator-() const { return mint() - *this; }
mint& operator+=(const mint &a) {
if ((x += a.x) >= MOD) x -= MOD;
return *this;
}
mint& operator-=(const mint &a) {
if ((x -= a.x) >= MOD) x += MOD;
return *this;
}
mint& operator*=(const mint &a) {
unsigned long long z = x;
z *= a.x;
x = (unsigned int)(z % MOD);
return *this;
}
mint& operator/=(const mint &a) {return *this = *this * a.inv(); }
friend mint operator+(const mint& lhs, const mint& rhs) {
return mint(lhs) += rhs;
}
friend mint operator-(const mint& lhs, const mint& rhs) {
return mint(lhs) -= rhs;
}
friend mint operator*(const mint& lhs, const mint& rhs) {
return mint(lhs) *= rhs;
}
friend mint operator/(const mint& lhs, const mint& rhs) {
return mint(lhs) /= rhs;
}
friend bool operator==(const mint& lhs, const mint& rhs) {
return lhs.x == rhs.x;
}
friend bool operator!=(const mint& lhs, const mint& rhs) {
return lhs.x != rhs.x;
}
friend std::ostream& operator<<(std::ostream &os, const mint &n) {
return os << n.x;
}
friend std::istream &operator>>(std::istream &is, mint &n) {
unsigned int x;
is >> x;
n = mint(x);
return is;
}
mint inv() const {
assert(x);
return pow(MOD-2);
}
mint pow(long long n) const {
assert(0 <= n);
mint p = *this, r = 1;
while (n) {
if (n & 1) r *= p;
p *= p;
n >>= 1;
}
return r;
}
mint sqrt() const {
if (this->x < 2) return *this;
if (this->pow((MOD-1)>>1).x != 1) return mint(0);
mint b = 1, one = 1;
while (b.pow((MOD-1) >> 1) == 1) b += one;
long long m = MOD-1, e = 0;
while (m % 2 == 0) m >>= 1, e += 1;
mint x = this->pow((m - 1) >> 1);
mint y = (*this) * x * x;
x *= (*this);
mint z = b.pow(m);
while (y.x != 1) {
int j = 0;
mint t = y;
while (t != one) j += 1, t *= t;
z = z.pow(1LL << (e-j-1));
x *= z; z *= z; y *= z; e = j;
}
return x;
}
};
constexpr int MOD = 998244353;
bool isprime(long long N) {
if (N <= 1) return false;
if (N == 2) return true;
if (N % 2 == 0) return false;
auto modpow = [](__int128_t a, long long n, long long mo) {
__int128_t r = 1;
a %= mo;
while (n) r = r * ((n % 2) ? a : 1) % mo, a = a * a % mo, n >>= 1;
return r;
};
std::vector<long long> A = {2, 325, 9375, 28178, 450775,
9780504, 1795265022};
long long s = 0, d = N - 1;
while (d % 2 == 0) d >>= 1, s++;
for (long long a : A) {
if (a % N == 0) return true;
long long j, r = modpow(a, d, N);
if (r == 1) continue;
for (j = 0; j < s; j++) {
if (r == N - 1) break;
r = __int128_t(r) * r % N;
}
if (j == s) return false;
}
return true;
}
long long PollardRho(long long N) {
if (N % 2 == 0) return 2;
long long m = 1LL<<(70-__builtin_clrsbll(N))/8;
for (long long c = 1; c < N; c++) {
auto f = [&](long long x) { return ((__int128_t)x*x+c)%N; };
long long x,y,g,q,r,k,ys;
y = k = 0;
g = q = r = 1;
while (g == 1) {
x = y;
while(k < 3*r/4) {
y = f(y);
k += 1;
}
while(k < r && g == 1) {
ys = y;
for (int _ = 0; _ < min(m,r-k); _++) {
y = f(y);
q = (__int128_t)q*abs(x-y)%N;
}
g = __gcd(q,N);
k += m;
}
k = r;
r <<= 1;
}
if (g == N) {
g = 1;
y = ys;
while(g == 1) {
y = f(y);
g = __gcd(abs(x-y),N);
}
}
if (g == N) continue;
if (isprime(g)) return g;
else if (isprime(N/g)) return N/g;
else return PollardRho(g);
}
return -1;
}
vector<pair<long long,int>> prime_factorization(long long N) {
vector<pair<long long,int>> res;
while(!isprime(N) && N > 1) {
long long p = PollardRho(N);
int cnt = 0;
while(N%p==0) {
N /= p;
cnt++;
}
res.push_back({p,cnt});
}
if (N > 1) res.push_back({N,1});
sort(res.begin(), res.end());
return res;
}
int main() {
int n,m;cin >> n >> m;
vector<int> a(n);
int L = 1;
for (int i = 0; i < n; i++) {
cin >> a[i];
L = (ll)L * a[i] / __gcd(a[i],L);
}
auto v = prime_factorization(L);
vector<int> divisor,euler;
divisor.push_back(1);
euler.push_back(1);
for (auto [p,e] : v) {
int sz = divisor.size();
for (int i = 0; i < e; i++) {
for (int j = sz*i; j < sz*(i+1); j++) {
divisor.push_back(divisor[j]*p);
euler.push_back(euler[j]*(p-!i));
}
}
}
mint<MOD> ans = 0;
for (int i = 0; i < euler.size(); i++) {
int d = L/divisor[i];
ll total = 0;
for (int j = 0; j < n; j++) {
total += __gcd(d,a[j]);
}
ans += mint<MOD>(m).pow(total)*euler[i];
}
cout << ans/L << endl;
return 0;
}
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