結果

問題 No.2270 T0空間
ユーザー cutmdocutmdo
提出日時 2023-04-14 23:03:12
言語 C++17
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 202 ms / 2,000 ms
コード長 5,262 bytes
コンパイル時間 3,449 ms
コンパイル使用メモリ 261,332 KB
実行使用メモリ 162,560 KB
最終ジャッジ日時 2024-04-27 04:43:06
合計ジャッジ時間 6,062 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,816 KB
testcase_01 AC 1 ms
6,940 KB
testcase_02 AC 2 ms
6,944 KB
testcase_03 AC 2 ms
6,940 KB
testcase_04 AC 2 ms
6,940 KB
testcase_05 AC 2 ms
6,940 KB
testcase_06 AC 2 ms
6,940 KB
testcase_07 AC 2 ms
6,944 KB
testcase_08 AC 2 ms
6,944 KB
testcase_09 AC 2 ms
6,944 KB
testcase_10 AC 2 ms
6,944 KB
testcase_11 AC 11 ms
7,040 KB
testcase_12 AC 11 ms
7,936 KB
testcase_13 AC 32 ms
20,096 KB
testcase_14 AC 18 ms
10,368 KB
testcase_15 AC 32 ms
20,096 KB
testcase_16 AC 42 ms
24,320 KB
testcase_17 AC 43 ms
22,656 KB
testcase_18 AC 61 ms
32,512 KB
testcase_19 AC 202 ms
162,560 KB
testcase_20 AC 124 ms
92,544 KB
testcase_21 AC 201 ms
162,560 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,avx512f")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <iostream>
#include <iomanip>
#include <string>
#include <cmath>
#include <algorithm>
#include <vector>
#include <set>
#include <map>
#include <unordered_map>
#include <unordered_set>
#include <list>
#include <stack>
#include <queue>
#include <bitset>
#include <numeric>
#include <cassert>
#include <memory>
#include <random>
#include <functional>
#include <complex>
#include <immintrin.h>
#include <stdexcept>
#ifdef DEBUG
#include "./CompetitiveProgrammingCpp/Utils/debug.hpp"
#include "./CompetitiveProgrammingCpp/Utils/Timer.hpp"
#include "./CompetitiveProgrammingCpp/Utils/sample.hpp"
#else
#define dump(...)
template<class T>constexpr inline auto d_val(T a, T b) { return a; }
#endif

/* macro */
#define FOR(i, b, e) for(ll i = (ll)(b); i < (ll)(e); ++i)
#define RFOR(i, b, e) for(ll i = (ll)((e)-1); i >= (ll)(b); --i)
#define REP(i, n) FOR(i, 0, (n))
#define RREP(i, n) RFOR(i, 0, (n))
#define REPC(x,c) for(const auto& x:(c))
#define REPI2(it,b,e) for(auto it = (b); it != (e); ++it)
#define REPI(it,c) REPI2(it, (c).begin(), (c).end())
#define RREPI(it,c) REPI2(it, (c).rbegin(), (c).rend())
#define REPI_ERACE2(it, b, e) for(auto it = (b); it != (e);)
#define REPI_ERACE(it, c) REPI_ERACE2(it, (c).begin(), (c).end())
#define ALL(x) (x).begin(),(x).end()
#define cauto const auto&
/* macro func */
template<class T>
inline auto sort(T& t) { std::sort(ALL(t)); }
template<class T>
inline auto rsort(T& t) { std::sort((t).rbegin(), (t).rend()); }
template<class T>
inline auto unique(T& t) { (t).erase(unique((t).begin(), (t).end()), (t).end()); }
template<class T, class S>
inline auto chmax(T& t, const S& s) { if(s > t) { t = s; return true; } return false; }
template<class T, class S>
inline auto chmin(T& t, const S& s) { if(s < t) { t = s; return true; } return false; }
inline auto BR() { std::cout << "\n"; }

/* type define */
using ll = long long;
using VS = std::vector<std::string>;
using VL = std::vector<long long>;
using VVL = std::vector<VL>;
using VVVL = std::vector<VVL>;
using VVVVL = std::vector<VVVL>;
using VVVVVL = std::vector<VVVVL>;
using VD = std::vector<double>;
template<class T>
using V = std::vector<T>;
template<class T = ll, class U = T>
using P = std::pair<T, U>;
using PAIR = P<ll>;

/* using std */
using std::cout;
constexpr char endl = '\n';
using std::cin;
using std::pair;
using std::string;
using std::stack;
using std::queue;
using std::deque;
using std::vector;
using std::list;
using std::map;
using std::unordered_map;
using std::multimap;
using std::unordered_multimap;
using std::set;
using std::unordered_set;
using std::unordered_multiset;
using std::multiset;
using std::bitset;
using std::priority_queue;

/* Initial processing  */
struct Preprocessing { Preprocessing() { std::cin.tie(0); std::ios::sync_with_stdio(0); }; }_Preprocessing;

/* define hash */
namespace std {
template <>	class hash<std::pair<ll, ll>> { public:	size_t operator()(const std::pair<ll, ll>& x) const { return hash<ll>()(1000000000 * x.first + x.second); } };
}

/* input */
template<class T> std::istream& operator >> (std::istream& is, vector<T>& vec) { for(T& x : vec) is >> x; return is; }

/* constant value */
// constexpr ll MOD = 1000000007;
constexpr ll MOD = 998244353;

//=============================================================================================

auto Y = [](auto f) {
    return [=](auto&&... args) {
        return f(f, std::forward<decltype(args)>(args)...);
    };
};

auto solve(ll n, ll m, const VS& v) {

    auto rec = Y([&](auto&& self, const VL& st, ll idx) {
        if(idx == m) { return (st.size() == 1); }
        ll size = st.size();
        VL l, r;
        REPC(i, st) { ((v[idx][i] == '0') ? l : r).emplace_back(i); }
        bool ans = true;
        if(!l.empty() && l.size() > 1) { ans &= self(self, l, idx + 1); }
        if(!r.empty() && r.size() > 1) { ans &= self(self, r, idx + 1); }
        return ans;
    });

    VL all(n);
    std::iota(ALL(all), 0);
    return rec(all, 0);
}

auto solve_c(ll n, ll m, const VS& v) {
    REP(i, n)FOR(j, i + 1, n) {
        bool ok = false;
        REPC(s, v) {
            if(s[i] != s[j]) { ok = true; break; }
        }
        if(!ok) { return false; }
    }
    return true;
}

signed main() {
    #ifndef TEST
    ll n, m;
    cin >> n >> m;
    VS v(m);
    cin >> v;
    auto ans = solve(n, m, v);
    cout << (ans ? "Yes" : "No") << endl;
    #else
    auto gen = Sample::SampleGenerator();
    REP(_, 10000) {
        constexpr ll LEN = 100;
        constexpr ll MAX = 100;
        auto [n, m] = gen.generate(PAIR{1,LEN}, PAIR{1,MAX});
        chmin(m, std::pow(2, n));
        VS v; v.reserve(m);
        REP(_, m) {
            auto [s_] = gen.generate(V<PAIR>(n, {'0','1'}));
            v.emplace_back(ALL(s_));
        }
        auto ans = solve(n, m, v);
        auto ans_c = solve_c(n, m, v);
        if(ans != ans_c) {
            cout << n << endl << m << endl;
            REPC(s, v) { cout << s << endl; }
            dump(ans, ans_c);
            return 0;
        }
    }
    #endif

}
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