結果

問題 No.2277 Honest or Dishonest ?
ユーザー shotoyoo
提出日時 2023-04-21 21:48:53
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 361 ms / 2,000 ms
コード長 2,571 bytes
コンパイル時間 278 ms
コンパイル使用メモリ 82,048 KB
実行使用メモリ 110,848 KB
最終ジャッジ日時 2024-11-08 06:29:01
合計ジャッジ時間 14,721 ms
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 50
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import sys, random
input = lambda : sys.stdin.readline().rstrip()
write = lambda x: sys.stdout.write(x+"\n"); writef = lambda x: print("{:.12f}".format(x))
debug = lambda x: sys.stderr.write(x+"\n")
YES="Yes"; NO="No"; pans = lambda v: print(YES if v else NO); INF=10**18
LI = lambda : list(map(int, input().split())); II=lambda : int(input()); SI=lambda : [ord(c)-ord("a") for c in input()]
def debug(_l_):
for s in _l_.split():
print(f"{s}={eval(s)}", end=" ")
print()
def dlist(*l, fill=0):
if len(l)==1:
return [fill]*l[0]
ll = l[1:]
return [dlist(*ll, fill=fill) for _ in range(l[0])]
class UF:
# unionfind
def __init__(self, n):
self.n = n
self.parent = list(range(n))
self.size = [1] * n
# self.es = [0] * n
def check(self):
return [self.root(i) for i in range(self.n)]
def root(self, i):
inter = set()
while self.parent[i]!=i:
inter.add(i)
i = self.parent[i]
r = i
for i in inter:
self.parent[i] = r
return r
def merge(self, i, j):
#
ri = self.root(i)
rj = self.root(j)
if ri==rj:
# self.es[ri] += 1
return False
if self.size[ri]>self.size[rj]:
ri,rj = rj,ri
self.parent[ri] = rj
self.size[rj] += self.size[ri]
# self.es[rj] += self.es[ri] + 1
return True
def rs(self):
return sorted(set([self.root(i) for i in range(self.n)]))
n,q = list(map(int, input().split()))
uf = UF(n)
ab = []
for i in range(q):
a,b,c = LI()
a -= 1
b -= 1
if c==0:
uf.merge(a,b)
else:
ab.append((a,b))
rs = uf.rs()
ns = {r: [] for r in rs}
M = 998244353
for a,b in ab:
ra = uf.root(a)
rb = uf.root(b)
if ra==rb:
ans = 0
break
else:
ns[ra].append(rb)
ns[rb].append(ra)
else:
num = 0
done = {}
for r in rs:
if r in done:
continue
q = [r]
done[r] = 0
num += 1
ng = 0
while q:
u = q.pop()
for v in ns[u]:
if v not in done:
done[v] = done[u]^1
q.append(v)
else:
if done[v]==done[u]:
ng = 1
break
if ng:
break
if ng:
ans = 0
break
else:
ans = pow(2, num, M)
print(ans%M)
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