結果
問題 | No.2277 Honest or Dishonest ? |
ユーザー | Ujjwal Rana |
提出日時 | 2023-04-21 21:57:29 |
言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 67 ms / 2,000 ms |
コード長 | 3,221 bytes |
コンパイル時間 | 4,012 ms |
コンパイル使用メモリ | 253,500 KB |
実行使用メモリ | 14,160 KB |
最終ジャッジ日時 | 2024-11-15 05:34:20 |
合計ジャッジ時間 | 7,415 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 50 |
ソースコード
#pragma GCC target ("avx2") #pragma GCC optimize ("O3") #pragma GCC optimize("Ofast") #pragma GCC optimize ("unroll-loops") // #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> using namespace __gnu_pbds; using namespace std; #define io ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define endl '\n' typedef long long ll; // #define mod1 (ll)1000000007 #define mod2 (ll)998244353 #define pll pair<ll,ll> typedef long double lb; typedef tree< pair<ll, ll>, null_type, less<pair<ll, ll>>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; #define eps (lb)(1e-9) struct custom_hash { static uint64_t splitmix64(uint64_t x) { x += 0x9e3779b97f4a7c15; x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9; x = (x ^ (x >> 27)) * 0x94d049bb133111eb; return x ^ (x >> 31); } size_t operator()(uint64_t x) const { static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count(); return splitmix64(x + FIXED_RANDOM); } }; // Operator overloads template<typename T1, typename T2> // cin >> pair<T1, T2> istream& operator>>(istream &istream, pair<T1, T2> &p) { return (istream >> p.first >> p.second); } template<typename T> // cin >> vector<T> istream& operator>>(istream &istream, vector<T> &v) { for (auto &it : v) cin >> it; return istream; } template<typename T1, typename T2> // cout << pair<T1, T2> ostream& operator<<(ostream &ostream, const pair<T1, T2> &p) { return (ostream << p.first << " " << p.second); } template<typename T> // cout << vector<T> ostream& operator<<(ostream &ostream, const vector<T> &c) { for (auto &it : c) cout << it << " "; return ostream; } // Utility functions template <typename T> void print(T &&t) { cout << t << "\n"; } template <typename T, typename... Args> void print(T &&t, Args &&... args) { cout << t << " "; print(forward<Args>(args)...); } mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); ll random(ll p){ // gives random number in [0,p] return uniform_int_distribution<ll>(0, p)(rng); } ll mod=mod2; ll mod1=mod2; ll n,m; vector<pll>adj[1<<17]; ll vis[1<<17]; ll col[1<<17]; ll dfs(ll cur,ll val){ col[cur]=val; vis[cur]=1; for(auto j:adj[cur]){ ll node=j.first; ll x=j.second; if(!vis[node]){ if(!dfs(node,val^x)){return 0;} } else if((col[node]^x)!=val){return 0;} } return 1; } void solve(); int main() { io; ll t=1,n=1; // cin>>t; while (t--){ solve(); } return 0; } void solve(){ ll ans=1; cin>>n>>m; for(ll i(0);i<m;++i){ ll a,b,c; cin>>a>>b>>c; a--,--b; adj[a].push_back({b,c}); adj[b].push_back({a,c}); } ll cur=2; for(ll i(0);i<n;++i){ if(!vis[i]){ ll g=dfs(i,cur); if(!g){cout<<0<<endl; return;} ans*=2; ans%=mod; } } cout<<ans<<endl; } // Do not get stuck on a single approach for long, think of multiple ways