結果
| 問題 |
No.2277 Honest or Dishonest ?
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-04-21 21:57:29 |
| 言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 55 ms / 2,000 ms |
| コード長 | 3,221 bytes |
| コンパイル時間 | 12,198 ms |
| コンパイル使用メモリ | 308,728 KB |
| 最終ジャッジ日時 | 2025-02-12 11:37:02 |
|
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 50 |
ソースコード
#pragma GCC target ("avx2")
#pragma GCC optimize ("O3")
#pragma GCC optimize("Ofast")
#pragma GCC optimize ("unroll-loops")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
using namespace std;
#define io ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define endl '\n'
typedef long long ll;
// #define mod1 (ll)1000000007
#define mod2 (ll)998244353
#define pll pair<ll,ll>
typedef long double lb;
typedef tree<
pair<ll, ll>,
null_type,
less<pair<ll, ll>>,
rb_tree_tag,
tree_order_statistics_node_update> ordered_set;
#define eps (lb)(1e-9)
struct custom_hash {
static uint64_t splitmix64(uint64_t x) {
x += 0x9e3779b97f4a7c15;
x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;
x = (x ^ (x >> 27)) * 0x94d049bb133111eb;
return x ^ (x >> 31);
}
size_t operator()(uint64_t x) const {
static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();
return splitmix64(x + FIXED_RANDOM);
}
};
// Operator overloads
template<typename T1, typename T2> // cin >> pair<T1, T2>
istream& operator>>(istream &istream, pair<T1, T2> &p) { return (istream >> p.first >> p.second); }
template<typename T> // cin >> vector<T>
istream& operator>>(istream &istream, vector<T> &v)
{
for (auto &it : v)
cin >> it;
return istream;
}
template<typename T1, typename T2> // cout << pair<T1, T2>
ostream& operator<<(ostream &ostream, const pair<T1, T2> &p) { return (ostream << p.first << " " << p.second); }
template<typename T> // cout << vector<T>
ostream& operator<<(ostream &ostream, const vector<T> &c) { for (auto &it : c) cout << it << " "; return ostream; }
// Utility functions
template <typename T>
void print(T &&t) { cout << t << "\n"; }
template <typename T, typename... Args>
void print(T &&t, Args &&... args)
{
cout << t << " ";
print(forward<Args>(args)...);
}
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
ll random(ll p){ // gives random number in [0,p]
return uniform_int_distribution<ll>(0, p)(rng);
}
ll mod=mod2;
ll mod1=mod2;
ll n,m;
vector<pll>adj[1<<17];
ll vis[1<<17];
ll col[1<<17];
ll dfs(ll cur,ll val){
col[cur]=val;
vis[cur]=1;
for(auto j:adj[cur]){
ll node=j.first;
ll x=j.second;
if(!vis[node]){
if(!dfs(node,val^x)){return 0;}
}
else if((col[node]^x)!=val){return 0;}
}
return 1;
}
void solve();
int main() {
io;
ll t=1,n=1;
// cin>>t;
while (t--){
solve();
}
return 0;
}
void solve(){
ll ans=1;
cin>>n>>m;
for(ll i(0);i<m;++i){
ll a,b,c;
cin>>a>>b>>c;
a--,--b;
adj[a].push_back({b,c});
adj[b].push_back({a,c});
}
ll cur=2;
for(ll i(0);i<n;++i){
if(!vis[i]){
ll g=dfs(i,cur);
if(!g){cout<<0<<endl; return;}
ans*=2;
ans%=mod;
}
}
cout<<ans<<endl;
}
// Do not get stuck on a single approach for long, think of multiple ways