結果

問題 No.2279 OR Insertion
ユーザー woodywoodywoodywoody
提出日時 2023-04-22 14:14:53
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 4,994 bytes
コンパイル時間 3,938 ms
コンパイル使用メモリ 232,148 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-11-07 03:01:53
合計ジャッジ時間 17,244 ms
ジャッジサーバーID
(参考情報)
judge4 / judge3
このコードへのチャレンジ
(要ログイン)

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
5,248 KB
testcase_01 AC 2 ms
5,248 KB
testcase_02 AC 57 ms
5,248 KB
testcase_03 WA -
testcase_04 WA -
testcase_05 WA -
testcase_06 WA -
testcase_07 WA -
testcase_08 AC 60 ms
5,248 KB
testcase_09 AC 257 ms
5,248 KB
testcase_10 AC 434 ms
5,248 KB
testcase_11 AC 47 ms
5,248 KB
testcase_12 AC 336 ms
5,248 KB
testcase_13 WA -
testcase_14 AC 23 ms
5,248 KB
testcase_15 AC 214 ms
5,248 KB
testcase_16 AC 4 ms
5,248 KB
testcase_17 AC 176 ms
5,248 KB
testcase_18 WA -
testcase_19 WA -
testcase_20 AC 197 ms
5,248 KB
testcase_21 WA -
testcase_22 AC 2 ms
5,248 KB
testcase_23 AC 2 ms
5,248 KB
testcase_24 WA -
testcase_25 WA -
testcase_26 AC 2 ms
5,248 KB
testcase_27 WA -
testcase_28 WA -
testcase_29 AC 2 ms
5,248 KB
testcase_30 AC 2 ms
5,248 KB
testcase_31 AC 2 ms
5,248 KB
testcase_32 AC 490 ms
5,248 KB
testcase_33 WA -
testcase_34 AC 478 ms
5,248 KB
testcase_35 AC 483 ms
5,248 KB
testcase_36 WA -
testcase_37 WA -
testcase_38 AC 477 ms
5,248 KB
testcase_39 WA -
testcase_40 AC 479 ms
5,248 KB
testcase_41 WA -
testcase_42 AC 474 ms
5,248 KB
testcase_43 WA -
testcase_44 WA -
testcase_45 WA -
testcase_46 AC 384 ms
5,248 KB
testcase_47 AC 384 ms
5,248 KB
testcase_48 WA -
testcase_49 AC 348 ms
5,248 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,b) for(int i=0;i<b;i++)
#define rrep(i,b) for(int i=b-1;i>=0;i--)
#define rep1(i,b) for(int i=1;i<b;i++)
#define repx(i,x,b) for(int i=x;i<b;i++)
#define rrepx(i,x,b) for(int i=b-1;i>=x;i--)
#define fore(i,a) for(auto i:a)
#define fore1(i,a) for(auto &i:a)
#define rng(x) (x).begin(), (x).end()
#define rrng(x) (x).rbegin(), (x).rend()
#define sz(x) ((int)(x).size())
#define pb push_back
#define fi first
#define se second
#define pcnt __builtin_popcountll

using namespace std;
using namespace atcoder;

using ll = long long;
using ld = long double;
template<typename T> using mpq = priority_queue<T, vector<T>, greater<T>>;
template<typename T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<typename T> bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
template<typename T> ll sumv(const vector<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;}
bool yn(bool a) { if(a) {cout << "Yes" << endl; return true;} else {cout << "No" << endl; return false;}}
#define dame { cout << "No" << endl; return;}
#define dame1 { cout << -1 << endl; return;}
#define cout2(x,y) cout << x << " " << y << endl;
#define coutp(p) cout << p.fi << " " << p.se << endl;
#define out cout << ans << endl;
#define outd cout << fixed << setprecision(20) << ans << endl;
#define outm cout << ans.val() << endl;
#define outv fore(yans , ans) cout << yans << "\n";
#define outdv fore(yans , ans) cout << yans.val() << "\n";
#define coutv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;}
#define coutv2(v) fore(vy , v) cout << vy << "\n";
#define coutvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;}
#define coutvm2(v) fore(vy , v) cout << vy.val() << "\n";
using pll = pair<ll,ll>;using pil = pair<int,ll>;using pli = pair<ll,int>;using pii = pair<int,int>;using pdd = pair<ld,ld>;
using tp = tuple<int ,int ,int>;
using vi = vector<int>;using vd = vector<ld>;using vl = vector<ll>;using vs = vector<string>;using vb = vector<bool>;
using vpii = vector<pii>;using vpli = vector<pli>;using vpll = vector<pll>;using vpil = vector<pil>;
using vvi = vector<vector<int>>;using vvl = vector<vector<ll>>;using vvs = vector<vector<string>>;using vvb = vector<vector<bool>>;
using vvpii = vector<vector<pii>>;using vvpli = vector<vector<pli>>;using vvpll = vector<vpll>;using vvpil = vector<vpil>;
using mint = modint998244353;
//using mint = modint1000000007;
//using mint = dynamic_modint<0>;
using vm = vector<mint>;
using vvm = vector<vector<mint>>;
vector<int> dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1};
ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;}
ll lcm(ll a, ll b) { return a/gcd(a,b)*b;}
#define yes {cout <<"Yes"<<endl;}
#define yesr { cout <<"Yes"<<endl; return;}
#define no {cout <<"No"<<endl;}
#define nor { cout <<"No"<<endl; return;}
const double eps = 1e-10;
const ll LINF = 1001002003004005006ll;
const int INF = 1001001001;
#ifdef MY_LOCAL_DEBUG
#define show(x) cerr<<#x<<" = "<<x<<endl
#define showp(p) cerr<<#p<<" = "<<p.fi<<" : "<<p.se<<endl
#define show2(x,y) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<endl
#define show3(x,y,z) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<endl
#define show4(x,y,z,x2) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<" : "<<#x2<<" = "<<x2<<endl
#define test(x) cout << "test" << x << endl
#define showv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;}
#define showv2(v) fore(vy , v) cout << vy << "\n";
#define showvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;}
#define showvm2(v) fore(vy , v) cout << vy.val() << "\n";
#else
#define show(x)
#define showp(p)
#define show2(x,y)
#define show3(x,y,z)
#define show4(x,y,z,x2)
#define test(x)
#define showv(v)
#define showv2(v)
#define showvm(v)
#define showvm2(v)
#endif

void solve(){
    int n; cin>>n;
    string s; cin>>s;
    mint ans = 0;
    mint all = mint(2).pow(n-1);
    if (s[n-1]=='0'){
        int cnt = 0;
        rep(i,n-1) cnt += s[i]-'0';
        ans = all-mint(2).pow(n-1-cnt);
    }
    // outm;
    rep1(i,n){
        // show(i);
        vm dp(n);
        fenwick_tree<mint> fw(n);
        rep(j,n){
            if (j==0){
                dp[0] = 1;
                fw.add(j,1);
                continue;
            }
            dp[j] = fw.sum(0,j) + 1;
            int nj = j-i-1;
            if (nj+1<0){
                fw.add(j,dp[j]);
                continue;
            }
            if (s[nj+1]=='0'){
                fw.add(j,dp[j]);
                continue;
            }
            if (nj==-1) dp[j] -= 1;
            else dp[j] -= fw.sum(0,nj+1)+1;
            fw.add(j,dp[j]);
        }
        // rep(j,n) cout << dp[j].val() << " ";
        // cout << endl;
        ans += (all-dp[n-1]) * (mint(2).pow(i));
        // outm;
    }
    outm;

    return;
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);

    int t = 1;
    //cin>>t;

    rep(i,t){
        solve();
    }

    return 0;
}
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