結果
問題 | No.2279 OR Insertion |
ユーザー | au7777 |
提出日時 | 2023-04-26 18:22:31 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 3,149 bytes |
コンパイル時間 | 4,505 ms |
コンパイル使用メモリ | 241,508 KB |
実行使用メモリ | 128,820 KB |
最終ジャッジ日時 | 2024-11-16 01:24:26 |
合計ジャッジ時間 | 10,045 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,816 KB |
testcase_01 | AC | 2 ms
6,816 KB |
testcase_02 | WA | - |
testcase_03 | WA | - |
testcase_04 | WA | - |
testcase_05 | WA | - |
testcase_06 | WA | - |
testcase_07 | WA | - |
testcase_08 | WA | - |
testcase_09 | WA | - |
testcase_10 | WA | - |
testcase_11 | WA | - |
testcase_12 | WA | - |
testcase_13 | WA | - |
testcase_14 | WA | - |
testcase_15 | WA | - |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | WA | - |
testcase_20 | WA | - |
testcase_21 | WA | - |
testcase_22 | AC | 2 ms
5,248 KB |
testcase_23 | AC | 2 ms
5,248 KB |
testcase_24 | AC | 2 ms
5,248 KB |
testcase_25 | AC | 2 ms
5,248 KB |
testcase_26 | AC | 2 ms
5,248 KB |
testcase_27 | AC | 2 ms
5,248 KB |
testcase_28 | AC | 2 ms
5,248 KB |
testcase_29 | AC | 2 ms
5,248 KB |
testcase_30 | AC | 2 ms
5,248 KB |
testcase_31 | AC | 2 ms
5,248 KB |
testcase_32 | WA | - |
testcase_33 | WA | - |
testcase_34 | WA | - |
testcase_35 | WA | - |
testcase_36 | WA | - |
testcase_37 | WA | - |
testcase_38 | WA | - |
testcase_39 | WA | - |
testcase_40 | WA | - |
testcase_41 | WA | - |
testcase_42 | WA | - |
testcase_43 | WA | - |
testcase_44 | WA | - |
testcase_45 | WA | - |
testcase_46 | WA | - |
testcase_47 | WA | - |
testcase_48 | WA | - |
testcase_49 | AC | 156 ms
128,512 KB |
ソースコード
#include <bits/stdc++.h> #include <atcoder/all> typedef long long int ll; using namespace std; typedef pair<ll, ll> P; using namespace atcoder; template<typename T> using min_priority_queue = priority_queue<T, vector<T>, greater<T>>; #define USE998244353 #ifdef USE998244353 const ll MOD = 998244353; // const double PI = 3.141592653589; using mint = modint998244353; #else const ll MOD = 1000000007; using mint = modint1000000007; #endif const int MAX = 3000005; long long fac[MAX], finv[MAX], inv[MAX]; void COMinit() { fac[0] = fac[1] = 1; finv[0] = finv[1] = 1; inv[1] = 1; for (int i = 2; i < MAX; i++){ fac[i] = fac[i - 1] * i % MOD; inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD; finv[i] = finv[i - 1] * inv[i] % MOD; } } long long COM(int n, int k){ if (n < k) return 0; if (n < 0 || k < 0) return 0; return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD; } ll gcd(ll x, ll y) { if (y == 0) return x; else if (y > x) { return gcd (y, x); } else return gcd(x % y, y); } ll lcm(ll x, ll y) { return x / gcd(x, y) * y; } ll my_sqrt(ll x) { // ll m = 0; ll M = 3000000001; while (M - m > 1) { ll now = (M + m) / 2; if (now * now <= x) { m = now; } else { M = now; } } return m; } ll keta(ll num, ll arity) { ll ret = 0; while (num) { num /= arity; ret++; } return ret; } ll ceil(ll n, ll m) { // n > 0, m > 0 ll ret = n / m; if (n % m) ret++; return ret; } ll pow_ll(ll x, ll n) { if (n == 0) return 1; if (n % 2) { return pow_ll(x, n - 1) * x; } else { ll tmp = pow_ll(x, n / 2); return tmp * tmp; } } vector<ll> compress(vector<ll>& v) { // [3 5 5 6 1 1 10 1] -> [1 2 2 3 0 0 4 0] vector<ll> u = v; sort(u.begin(), u.end()); u.erase(unique(u.begin(),u.end()),u.end()); map<ll, ll> mp; for (int i = 0; i < u.size(); i++) { mp[u[i]] = i; } for (int i = 0; i < v.size(); i++) { v[i] = mp[v[i]]; } return v; } int main() { ll n; string s; cin >> n >> s; mint dp[n + 1][n + 1]; mint rui[n + 1][n + 1]; for (int i = 0; i <= n; i++) { dp[i][0] = 1; rui[i][0] = 1; for (int j = 1; j <= n; j++) { dp[i][j] = 0; rui[i][j] = 0; } } // iけた目が全て0になるような for (int i = 0; i < n; i++) { // i個前 for (int j = 1; j <= n; j++) { if ((j - i - 1 < 0) || (s[j - i - 1] == '0')) { // 気にしなくて良い dp[i][j] = rui[i][j - 1]; } else { dp[i][j] = rui[i][j - 1] - rui[i][j - i - 1]; } rui[i][j] = rui[i][j - 1] + dp[i][j]; } } mint all = pow_mod(2, n - 1, MOD); mint ans = 0; for (int i = 0; i < n; i++) { // cout << i << ' ' << dp[i][n].val() << endl; mint num = all - dp[i][n]; ans += num * (1L << i); } cout << ans.val() << endl; return 0; }