結果
問題 | No.5015 Escape from Labyrinth |
ユーザー | 👑 p-adic |
提出日時 | 2023-04-29 16:34:22 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
WA
|
実行時間 | - |
コード長 | 2,908 bytes |
コンパイル時間 | 3,929 ms |
コンパイル使用メモリ | 226,476 KB |
実行使用メモリ | 4,500 KB |
スコア | 0 |
最終ジャッジ日時 | 2023-04-29 16:34:58 |
合計ジャッジ時間 | 9,625 ms |
ジャッジサーバーID (参考情報) |
judge15 / judge11 |
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テストケース
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コンパイルメッセージ
main.cpp: 関数 ‘int main()’ 内: main.cpp:116:9: 警告: ‘key[0]’ may be used uninitialized [-Wmaybe-uninitialized] 116 | search( S , key[0] , key[1] , goal[0] , goal[1] ); | ~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ main.cpp:97:7: 備考: ‘key[0]’ はここで定義されています 97 | int key[2]; | ^~~ main.cpp:116:9: 警告: ‘goal[1]’ may be used uninitialized [-Wmaybe-uninitialized] 116 | search( S , key[0] , key[1] , goal[0] , goal[1] ); | ~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ main.cpp:96:7: 備考: ‘goal[1]’ はここで定義されています 96 | int goal[2]; | ^~~~ main.cpp:116:9: 警告: ‘goal[0]’ may be used uninitialized [-Wmaybe-uninitialized] 116 | search( S , key[0] , key[1] , goal[0] , goal[1] ); | ~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ main.cpp:96:7: 備考: ‘goal[0]’ はここで定義されています 96 | int goal[2]; | ^~~~ main.cpp:116:9: 警告: ‘key[1]’ may be used uninitialized [-Wmaybe-uninitialized] 116 | search( S , key[0] , key[1] , goal[0] , goal[1] ); | ~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ main.cpp:97:7: 備考: ‘key[1]’ はここで定義されています 97 | int key[2]; | ^~~ main.cpp:115:9: 警告: ‘start[1]’ may be used uninitialized [-Wmaybe-uninitialized] 115 | search( S , start[0] , start[1] , key[0] , key[1] ); | ~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ main.cpp:95:7: 備考: ‘start[1]’ はここで定義されています 95 | int start[2]; | ^~~~~ main.cpp:115:9: 警告: ‘start[0]’ may be used uninitialized [-Wmaybe-uninitialized] 115 | search( S , start[0] , start[1] , key[0] , key[1] ); | ~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ main.cpp:95:7: 備考: ‘start[0]’ はここで定義されています 95 | int start[2]; | ^~~~~
ソースコード
#pragma GCC optimize ( "O3" ) #pragma GCC optimize( "unroll-loops" ) #pragma GCC target ( "sse4.2,fma,avx2,popcnt,lzcnt,bmi2" ) #include <bits/stdc++.h> using namespace std; #define TYPE_OF( VAR ) remove_const<remove_reference<decltype( VAR )>::type >::type #define UNTIE ios_base::sync_with_stdio( false ); cin.tie( nullptr ) #define CEXPR( LL , BOUND , VALUE ) constexpr LL BOUND = VALUE #define GETLINE( A ) string A; getline( cin , A ) #define FOR( VAR , INITIAL , FINAL_PLUS_ONE ) for( TYPE_OF( FINAL_PLUS_ONE ) VAR = INITIAL ; VAR < FINAL_PLUS_ONE ; VAR ++ ) #define FOR_ITR( ARRAY , ITR , END ) for( auto ITR = ARRAY .begin() , END = ARRAY .end() ; ITR != END ; ITR ++ ) #define QUIT return 0 inline CEXPR( int , N , 60 ); void search( string ( &S )[N] , int i0 , int j0 , int i1 , int j1 ) { list<list<pair<int,int> > > path{}; path.push_back( list<pair<int,int> >() ); path.front().push_back( pair<int,int>( i0 , j0 ) ); string d[4] = { "U" , "R" , "D" , "L" }; int di[4] = { -1 , 0 , 1 , 0 }; int dj[4] = { 0 , 1 , 0 , -1 }; string w = "#"; bool reach[N][N] = {}; pair<int,int> c{}; int& i = c.first; int& j = c.second; list<int> direction{}; bool found = false; while( !found ){ list<pair<int,int> >& last = path.back(); list<pair<int,int> > next{}; FOR_ITR( last , itr , end ){ FOR( n , 0 , 4 ){ i = itr->first + di[n]; j = itr->second + dj[n]; if( i == i1 && j == j1 ){ direction.push_front( n ); i1 = itr->first; j1 = itr->second; path.pop_back(); found = true; break; } if( 0 <= i && i < N && 0 <= j && j < N && ! reach[i][j] && S[i].substr( j , 1 ) != w ){ reach[i][j] = true; next.push_back( c ); } } if( found ){ break; } } if( !found ){ assert( ! next.empty() ); path.push_back( next ); } } while( ! path.empty() ){ list<pair<int,int> >& last = path.back(); found = false; FOR_ITR( last , itr , end ){ FOR( n , 0 , 4 ){ i = itr->first + di[n]; j = itr->second + dj[n]; if( i == i1 && j == j1 ){ direction.push_front( n ); i1 = itr->first; j1 = itr->second; path.pop_back(); found = true; break; } } if( found ){ break; } } } FOR_ITR( direction , itr , end ){ cout << "M " << d[*itr] << "\n"; } return; } int main() { UNTIE; GETLINE( NDH ); string S[N]; string s = "S"; string g = "G"; string k = "K"; int start[2]; int goal[2]; int key[2]; FOR( i , 0 , N ){ string& Si = S[i]; getline( cin , Si ); FOR( j , 0 , N ){ string Sij = Si.substr( j , 1 ); if( Sij == s ){ start[0] = i; start[1] = j; } else if( Sij == g ){ goal[0] = i; goal[1] = j; } else if( Sij == k ){ key[0] = i; key[1] = j; } } } search( S , start[0] , start[1] , key[0] , key[1] ); search( S , key[0] , key[1] , goal[0] , goal[1] ); QUIT; }