結果

問題 No.2292 Interval Union Find
ユーザー だれ
提出日時 2023-05-05 22:54:14
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 232 ms / 5,000 ms
コード長 7,330 bytes
コンパイル時間 3,748 ms
コンパイル使用メモリ 188,952 KB
最終ジャッジ日時 2025-02-12 19:15:08
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 4
other AC * 44
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <algorithm>
#include <bitset>
#include <cassert>
#include <cmath>
#include <cstdio>
#include <fstream>
#include <functional>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <unordered_set>
using namespace std;
#if __has_include(<atcoder/all>)
#include <atcoder/all>
#endif
#define GET_MACRO(_1, _2, _3, NAME, ...) NAME
#define _rep(i, n) _rep2(i, 0, n)
#define _rep2(i, a, b) for (int i = (int)(a); i < (int)(b); i++)
#define rep(...) GET_MACRO(__VA_ARGS__, _rep2, _rep)(__VA_ARGS__)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define UNIQUE(x) \
std::sort((x).begin(), (x).end()); \
(x).erase(std::unique((x).begin(), (x).end()), (x).end())
using i64 = long long;
template <class T, class U>
bool chmin(T& a, const U& b) {
return (b < a) ? (a = b, true) : false;
}
template <class T, class U>
bool chmax(T& a, const U& b) {
return (b > a) ? (a = b, true) : false;
}
inline void YesNo(bool f = 0, string yes = "Yes", string no = "No") {
std::cout << (f ? yes : no) << "\n";
}
namespace io {
template <typename T>
istream& operator>>(istream& i, vector<T>& v) {
rep(j, v.size()) i >> v[j];
return i;
}
template <typename T>
string join(vector<T>& v) {
stringstream s;
rep(i, v.size()) s << ' ' << v[i];
return s.str().substr(1);
}
template <typename T>
ostream& operator<<(ostream& o, vector<T>& v) {
if (v.size()) o << join(v);
return o;
}
template <typename T>
string join(vector<vector<T>>& vv) {
string s = "\n";
rep(i, vv.size()) s += join(vv[i]) + "\n";
return s;
}
template <typename T>
ostream& operator<<(ostream& o, vector<vector<T>>& vv) {
if (vv.size()) o << join(vv);
return o;
}
template <class T, class U>
istream& operator>>(istream& i, pair<T, U>& p) {
i >> p.first >> p.second;
return i;
}
template <class T, class U>
ostream& operator<<(ostream& o, pair<T, U>& p) {
o << p.first << " " << p.second;
return o;
}
void print() { cout << "\n"; }
template <class Head, class... Tail>
void print(Head&& head, Tail&&... tail) {
cout << head;
if (sizeof...(tail)) cout << ' ';
print(std::forward<Tail>(tail)...);
}
void in() {}
template <class Head, class... Tail>
void in(Head&& head, Tail&&... tail) {
cin >> head;
in(std::forward<Tail>(tail)...);
}
} // namespace io
using namespace io;
namespace useful {
long long modpow(long long a, long long b, long long mod) {
long long res = 1;
while (b) {
if (b & 1) res *= a, res %= mod;
a *= a;
a %= mod;
b >>= 1;
}
return res;
}
bool is_pow2(long long x) { return x > 0 && (x & (x - 1)) == 0; }
template <class T>
void rearrange(vector<T>& a, vector<int>& p) {
vector<T> b = a;
for (int i = 0; i < int(a.size()); i++) {
a[i] = b[p[i]];
}
return;
}
template <class T>
vector<pair<int, int>> rle_sequence(T& a) {
vector<pair<int, int>> res;
int n = a.size();
if (n == 1) return vector<pair<int, int>>{{a[0], 1}};
int l = 1;
rep(i, n - 1) {
if (a[i] == a[i + 1])
l++;
else {
res.emplace_back(a[i], l);
l = 1;
}
}
res.emplace_back(a.back(), l);
return res;
}
vector<pair<char, int>> rle_string(string a) {
vector<pair<char, int>> res;
int n = a.size();
if (n == 1) return vector<pair<char, int>>{{a[0], 1}};
int l = 1;
rep(i, n - 1) {
if (a[i] == a[i + 1])
l++;
else {
res.emplace_back(a[i], l);
l = 1;
}
}
res.emplace_back(a.back(), l);
return res;
}
vector<int> linear_sieve(int n) {
vector<int> primes;
vector<int> res(n + 1);
iota(all(res), 0);
for (int i = 2; i <= n; i++) {
if (res[i] == i) primes.emplace_back(i);
for (auto j : primes) {
if (j * i > n) break;
res[j * i] = j;
}
}
return res;
// return primes;
}
template <class T>
vector<long long> dijkstra(vector<vector<pair<int, T>>>& graph, int start) {
int n = graph.size();
vector<long long> res(n, 2e18);
res[start] = 0;
priority_queue<pair<long long, int>, vector<pair<long long, int>>,
greater<pair<long long, int>>>
que;
que.push({0, start});
while (!que.empty()) {
auto [c, v] = que.top();
que.pop();
if (res[v] < c) continue;
for (auto [nxt, cost] : graph[v]) {
auto x = c + cost;
if (x < res[nxt]) {
res[nxt] = x;
que.push({x, nxt});
}
}
}
return res;
}
} // namespace useful
using namespace useful;
class SegmentMap : public std::map<signed, signed> {
private:
bool flagToMergeAdjacentSegment;
public:
// if merge [l, c] and [c+1, r], set flagToMergeAdjacentSegment to true
SegmentMap(bool f) : flagToMergeAdjacentSegment(f) {}
// __exist -> iterator pair(l, r) (contain p)
// noexist -> map.end()
auto get(signed p) const {
auto it = upper_bound(p);
if (it == begin() || (--it)->second < p) return end();
return it;
}
// insert segment [l, r]
void insert(signed l, signed r) {
auto itl = upper_bound(l),
itr = upper_bound(r + flagToMergeAdjacentSegment);
if (itl != begin()) {
if ((--itl)->second < l - flagToMergeAdjacentSegment) ++itl;
}
if (itl != itr) {
l = std::min(l, itl->first);
r = std::max(r, std::prev(itr)->second);
erase(itl, itr);
}
(*this)[l] = r;
}
// remove segment [l, r]
void remove(signed l, signed r) {
auto itl = upper_bound(l), itr = upper_bound(r);
if (itl != begin()) {
if ((--itl)->second < l) ++itl;
}
if (itl == itr) return;
int tl = std::min(l, itl->first),
tr = std::max(r, std::prev(itr)->second);
erase(itl, itr);
if (tl < l) (*this)[tl] = l - 1;
if (r < tr) (*this)[r + 1] = tr;
}
// Is p and q in same segment?
bool same(signed p, signed q) const {
if (p == q) return true;
const auto&& it = get(p);
return it != end() && it->first <= q && q <= it->second;
}
};
int main() {
cin.tie(nullptr);
ios::sync_with_stdio(false);
int n, q;
in(n, q);
SegmentMap s(true);
rep(i, q) {
int t;
in(t);
if (t == 1) {
int l, r;
in(l, r);
s.insert(2 * l, 2 * r);
}
if (t == 2) {
int l, r;
in(l, r);
s.remove(2 * l + 1, 2 * r - 1);
}
if (t == 3) {
int l, r;
in(l, r);
if (s.same(2 * l, 2 * r)) {
print(1);
} else {
print(0);
}
}
if (t == 4) {
int v;
in(v);
auto it = s.get(2 * v);
if (it == s.end()) {
print(1);
} else {
auto [l, r] = *it;
print((r - l) / 2 + 1);
}
}
}
}
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