結果

問題 No.2333 Slime Structure
ユーザー hikikomori
提出日時 2023-05-09 02:08:51
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 435 ms / 3,000 ms
コード長 3,021 bytes
コンパイル時間 5,208 ms
コンパイル使用メモリ 322,240 KB
実行使用メモリ 108,616 KB
最終ジャッジ日時 2024-11-25 16:11:11
合計ジャッジ時間 20,999 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 31
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#include <atcoder/all>
using namespace atcoder;
using ll = long long;
using ld = long double;
using P = pair<int, int>;
using Graph = vector<vector<ll>>;
using vi = vector<int>;
using vl = vector<long>;
using vll = vector<long long>;
using vvi = vector<vi>;
using vvl = vector<vl>;
using vvll = vector<vll>;
using vs = vector<string>;
using vc = vector<char>;
using vvc = vector<vc>;
using pll = pair<long long, long long>;
using vpll = vector<pll>;
using mint = modint1000000007;
const long double EPS = 1e-18;
const long long INF = 1e15;
const long double PI = acos(-1.0L);
#define reps(i, a, n) for (ll i = (a); i < (ll)(n); i++)
#define rep(i, n) for (ll i = (0); i < (ll)(n); i++)
#define rrep(i, n) for (ll i = (1); i < (ll)(n + 1); i++)
#define repd(i, n) for (ll i = n - 1; i >= 0; i--)
#define rrepd(i, n) for (ll i = n; i >= 1; i--)
#define ALL(n) begin(n), end(n)
#define IN(a, x, b) (a <= x && x < b)
#define INIT \
std::ios::sync_with_stdio(false); \
std::cin.tie(0);
template <class T>
inline T CHMAX(T& a, const T b) {
return a = (a < b) ? b : a;
}
template <class T>
inline T CHMIN(T& a, const T b) {
return a = (a > b) ? b : a;
}
struct S {
ll left_max;
ll right_max;
ll kukan_max;
ll sum;
};
S op(S a, S b) {
return S{max(a.left_max, a.sum + b.left_max),
max(b.right_max, b.sum + a.right_max),
max(max(a.kukan_max, b.kukan_max), a.right_max + b.left_max),
a.sum + b.sum};
}
S e() { return S{-INF, -INF, -INF, 0ll}; }
int main() {
INIT;
ll N;
cin >> N;
vll A(1e5 + 100), B(1e5 + 100);
rrep(i, N) { cin >> A[i] >> B[i]; }
ll Q;
cin >> Q;
vll q(1e5 + 100), a(1e5 + 100), b(1e5 + 100);
vll num;
num.push_back(0ll);
rrep(i, N) { num.push_back(num[i - 1] + B[i]); }
vll numnum = num;
rrep(i, N) {
num.push_back(numnum[i] - 1);
num.push_back(numnum[i] + 1);
}
rrep(i, Q) {
cin >> q[i] >> a[i] >> b[i];
num.push_back(a[i] - 1);
num.push_back(a[i]);
num.push_back(a[i] + 1);
if (q[i] == 2) {
num.push_back(b[i] - 1);
num.push_back(b[i]);
num.push_back(b[i] + 1);
}
}
sort(ALL(num));
num.erase(unique(ALL(num)), num.end());
ll su = num.size();
segtree<S, op, e> seg(su + 1);
rrep(i, num.size() - 1) {
auto itr = lower_bound(ALL(numnum), num[i]);
ll l = itr - numnum.begin();
ll haba = num[i] - num[i - 1];
seg.set(i, S{A[l] * haba, A[l] * haba, A[l] * haba, A[l] * haba});
}
rrep(i, Q) {
if (q[i] == 1) {
ll l = lower_bound(ALL(num), a[i]) - num.begin();
seg.set(l, S{b[i], b[i], b[i], b[i]});
} else {
ll l = lower_bound(ALL(num), a[i]) - num.begin();
ll r = lower_bound(ALL(num), b[i]) - num.begin();
cout << seg.prod(l, r + 1).kukan_max << endl;
}
}
}
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