結果
| 問題 |
No.898 tri-βutree
|
| コンテスト | |
| ユーザー |
rlangevin
|
| 提出日時 | 2023-05-10 23:18:19 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 1,232 ms / 4,000 ms |
| コード長 | 2,392 bytes |
| コンパイル時間 | 203 ms |
| コンパイル使用メモリ | 82,304 KB |
| 実行使用メモリ | 111,008 KB |
| 最終ジャッジ日時 | 2024-11-27 03:00:15 |
| 合計ジャッジ時間 | 17,160 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 21 |
ソースコード
import sys
input = sys.stdin.readline
class LowestCommonAncestor:
def __init__(self, n):
self._n = n
self._logn = 0
v = 1
while v <= self._n:
v *= 2
self._logn += 1
self._depth = [0] * self._n
self._distance = [0] * self._n
self._ancestor = [[-1] * self._n for _ in range(self._logn)]
self._G = [[] for i in range(self._n)]
def add_edge(self, u, v, w=1):
self._G[u].append((v, w))
self._G[v].append((u, w))
def build(self, root=0):
stack = [root]
while stack:
cur = stack.pop()
for nex, w in self._G[cur]:
if self._ancestor[0][nex] != cur and self._ancestor[0][cur] != nex:
self._ancestor[0][nex] = cur
self._depth[nex] = self._depth[cur] + 1
self._distance[nex] = self._distance[cur] + w
stack.append(nex)
for k in range(1, self._logn):
for i in range(self._n):
if self._ancestor[k - 1][i] == -1:
self._ancestor[k][i] = -1
else:
self._ancestor[k][i] = self._ancestor[k - 1][self._ancestor[k - 1][i]]
def lca(self, u, v):
if self._depth[u] > self._depth[v]:
u, v = v, u
for k in range(self._logn - 1, -1, -1):
if ((self._depth[v] - self._depth[u]) >> k) & 1:
v = self._ancestor[k][v]
if u == v:
return u
for k in range(self._logn - 1, -1, -1):
if self._ancestor[k][u] != self._ancestor[k][v]:
u = self._ancestor[k][u]
v = self._ancestor[k][v]
return self._ancestor[0][u]
def distance(self, u, v):
return self._distance[u] + self._distance[v] - 2 * self._distance[self.lca(u, v)]
N = int(input())
T = LowestCommonAncestor(N)
for i in range(N - 1):
u, v, w = map(int, input().split())
T.add_edge(u, v, w)
T.build()
Q = int(input())
for _ in range(Q):
L = list(map(int, input().split()))
ans = 10 ** 18
for i in range(3):
ans = min(ans, T.distance(L[i], L[(i + 1)%3]) + T.distance(T.lca(L[i], L[(i + 1)%3]), L[(i + 2)%3]))
print(ans)
rlangevin