結果
問題 | No.2308 [Cherry 5th Tune B] もしかして、真? |
ユーザー |
|
提出日時 | 2023-05-19 22:20:08 |
言語 | PyPy3 (7.3.15) |
結果 |
WA
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実行時間 | - |
コード長 | 5,355 bytes |
コンパイル時間 | 229 ms |
コンパイル使用メモリ | 82,188 KB |
実行使用メモリ | 253,044 KB |
最終ジャッジ日時 | 2024-12-18 03:04:31 |
合計ジャッジ時間 | 66,071 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge3 |
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ファイルパターン | 結果 |
---|---|
other | AC * 16 WA * 17 TLE * 6 |
ソースコード
import sysfrom collections import deque, Counterinput = lambda: sys.stdin.readline().rstrip()ii = lambda: int(input())mi = lambda: map(int, input().split())li = lambda: list(mi())inf = 2 ** 63 - 1mod = 998244353# https://github.com/tatyam-prime/SortedSet/blob/main/SortedMultiset.pyimport mathfrom bisect import bisect_left, bisect_right, insortfrom typing import Generic, Iterable, Iterator, TypeVar, Union, ListT = TypeVar('T')class SortedMultiset(Generic[T]):BUCKET_RATIO = 50REBUILD_RATIO = 170def _build(self, a=None) -> None:"Evenly divide `a` into buckets."if a is None: a = list(self)size = self.size = len(a)bucket_size = int(math.ceil(math.sqrt(size / self.BUCKET_RATIO)))self.a = [a[size * i // bucket_size : size * (i + 1) // bucket_size] for i in range(bucket_size)]def __init__(self, a: Iterable[T] = []) -> None:"Make a new SortedMultiset from iterable. / O(N) if sorted / O(N log N)"a = list(a)if not all(a[i] <= a[i + 1] for i in range(len(a) - 1)):a = sorted(a)self._build(a)def __iter__(self) -> Iterator[T]:for i in self.a:for j in i: yield jdef __reversed__(self) -> Iterator[T]:for i in reversed(self.a):for j in reversed(i): yield jdef __len__(self) -> int:return self.sizedef __repr__(self) -> str:return "SortedMultiset" + str(self.a)def __str__(self) -> str:s = str(list(self))return "{" + s[1 : len(s) - 1] + "}"def _find_bucket(self, x: T) -> List[T]:"Find the bucket which should contain x. self must not be empty."for a in self.a:if x <= a[-1]: return areturn adef __contains__(self, x: T) -> bool:if self.size == 0: return Falsea = self._find_bucket(x)i = bisect_left(a, x)return i != len(a) and a[i] == xdef count(self, x: T) -> int:"Count the number of x."return self.index_right(x) - self.index(x)def add(self, x: T) -> None:"Add an element. / O(√N)"if self.size == 0:self.a = [[x]]self.size = 1returna = self._find_bucket(x)insort(a, x)self.size += 1if len(a) > len(self.a) * self.REBUILD_RATIO:self._build()def discard(self, x: T) -> bool:"Remove an element and return True if removed. / O(√N)"if self.size == 0: return Falsea = self._find_bucket(x)i = bisect_left(a, x)if i == len(a) or a[i] != x: return Falsea.pop(i)self.size -= 1if len(a) == 0: self._build()return Truedef lt(self, x: T) -> Union[T, None]:"Find the largest element < x, or None if it doesn't exist."for a in reversed(self.a):if a[0] < x:return a[bisect_left(a, x) - 1]def le(self, x: T) -> Union[T, None]:"Find the largest element <= x, or None if it doesn't exist."for a in reversed(self.a):if a[0] <= x:return a[bisect_right(a, x) - 1]def gt(self, x: T) -> Union[T, None]:"Find the smallest element > x, or None if it doesn't exist."for a in self.a:if a[-1] > x:return a[bisect_right(a, x)]def ge(self, x: T) -> Union[T, None]:"Find the smallest element >= x, or None if it doesn't exist."for a in self.a:if a[-1] >= x:return a[bisect_left(a, x)]def __getitem__(self, x: int) -> T:"Return the x-th element, or IndexError if it doesn't exist."if x < 0: x += self.sizeif x < 0: raise IndexErrorfor a in self.a:if x < len(a): return a[x]x -= len(a)raise IndexErrordef index(self, x: T) -> int:"Count the number of elements < x."ans = 0for a in self.a:if a[-1] >= x:return ans + bisect_left(a, x)ans += len(a)return ansdef index_right(self, x: T) -> int:"Count the number of elements <= x."ans = 0for a in self.a:if a[-1] > x:return ans + bisect_right(a, x)ans += len(a)return ansdef solve():n = ii()x = [1 if v == 'True' else 0 for v in input().split()]y = list(input().split())s = li()X = SortedMultiset()Y = SortedMultiset()V = ['and', 'or', 'xor', 'imp']for i in range(len(x)):X.add((10 * i+x[i]))for i in range(len(y)):Y.add((10 * i+V.index(y[i])))for v in s:now = R = Y[v - 1]now %= 10now = V[now]i = Y.index(R)Y.discard(R)a = P = X[i]b = Q = X[i + 1]a %= 10b %= 10X.discard(P)X.discard(Q)if now == 'and':X.add((10 * i+ (a & b)))if now == 'or':X.add((10 * i + (a | b)))if now == 'xor':X.add((10 * i + (a ^ b)))if now == 'imp':X.add((10 * i+ (0 if (a == 1 and b == 0) else 1)))print(bool(X[0] % 10))for _ in range(ii()):solve()