結果
問題 | No.2308 [Cherry 5th Tune B] もしかして、真? |
ユーザー |
![]() |
提出日時 | 2023-05-19 22:21:24 |
言語 | Python3 (3.13.1 + numpy 2.2.1 + scipy 1.14.1) |
結果 |
WA
|
実行時間 | - |
コード長 | 4,673 bytes |
コンパイル時間 | 494 ms |
コンパイル使用メモリ | 13,184 KB |
実行使用メモリ | 86,724 KB |
最終ジャッジ日時 | 2024-12-18 03:09:30 |
合計ジャッジ時間 | 86,466 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge5 |
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ファイルパターン | 結果 |
---|---|
other | AC * 2 WA * 8 TLE * 29 |
ソースコード
# https://github.com/tatyam-prime/SortedSet/blob/main/SortedSet.pyimport mathfrom bisect import bisect_left, bisect_rightfrom typing import Generic, Iterable, Iterator, TypeVar, Optional, ListT = TypeVar('T')class SortedSet(Generic[T]):BUCKET_RATIO = 50REBUILD_RATIO = 170def _build(self, a=None) -> None:"Evenly divide `a` into buckets."if a is None: a = list(self)size = self.size = len(a)bucket_size = int(math.ceil(math.sqrt(size / self.BUCKET_RATIO)))self.a = [a[size * i // bucket_size : size * (i + 1) // bucket_size] for i in range(bucket_size)]def __init__(self, a: Iterable[T] = []) -> None:"Make a new SortedSet from iterable. / O(N) if sorted and unique / O(N log N)"a = list(a)if not all(a[i] < a[i + 1] for i in range(len(a) - 1)):a = sorted(set(a))self._build(a)def __iter__(self) -> Iterator[T]:for i in self.a:for j in i: yield jdef __reversed__(self) -> Iterator[T]:for i in reversed(self.a):for j in reversed(i): yield jdef __len__(self) -> int:return self.sizedef __repr__(self) -> str:return "SortedSet" + str(self.a)def __str__(self) -> str:s = str(list(self))return "{" + s[1 : len(s) - 1] + "}"def _find_bucket(self, x: T) -> List[T]:"Find the bucket which should contain x. self must not be empty."for a in self.a:if x <= a[-1]: return areturn adef __contains__(self, x: T) -> bool:if self.size == 0: return Falsea = self._find_bucket(x)i = bisect_left(a, x)return i != len(a) and a[i] == xdef add(self, x: T) -> bool:"Add an element and return True if added. / O(√N)"if self.size == 0:self.a = [[x]]self.size = 1return Truea = self._find_bucket(x)i = bisect_left(a, x)if i != len(a) and a[i] == x: return Falsea.insert(i, x)self.size += 1if len(a) > len(self.a) * self.REBUILD_RATIO:self._build()return Truedef discard(self, x: T) -> bool:"Remove an element and return True if removed. / O(√N)"if self.size == 0: return Falsea = self._find_bucket(x)i = bisect_left(a, x)if i == len(a) or a[i] != x: return Falsea.pop(i)self.size -= 1if len(a) == 0: self._build()return Truedef lt(self, x: T) -> Optional[T]:"Find the largest element < x, or None if it doesn't exist."for a in reversed(self.a):if a[0] < x:return a[bisect_left(a, x) - 1]def le(self, x: T) -> Optional[T]:"Find the largest element <= x, or None if it doesn't exist."for a in reversed(self.a):if a[0] <= x:return a[bisect_right(a, x) - 1]def gt(self, x: T) -> Optional[T]:"Find the smallest element > x, or None if it doesn't exist."for a in self.a:if a[-1] > x:return a[bisect_right(a, x)]def ge(self, x: T) -> Optional[T]:"Find the smallest element >= x, or None if it doesn't exist."for a in self.a:if a[-1] >= x:return a[bisect_left(a, x)]def __getitem__(self, x: int) -> T:"Return the x-th element, or IndexError if it doesn't exist."if x < 0: x += self.sizeif x < 0: raise IndexErrorfor a in self.a:if x < len(a): return a[x]x -= len(a)raise IndexErrordef index(self, x: T) -> int:"Count the number of elements < x."ans = 0for a in self.a:if a[-1] >= x:return ans + bisect_left(a, x)ans += len(a)return ansdef index_right(self, x: T) -> int:"Count the number of elements <= x."ans = 0for a in self.a:if a[-1] > x:return ans + bisect_right(a, x)ans += len(a)return ansfor _ in range(int(input())):n = int(input())d = {"False":0,"True":1}x = [d[v] for v in input().split()]y = list(input().split())ss = SortedSet(range(n))for v in map(int,input().split()):l = ss[v-1]; r = ss[v]; ss.discard(r)if y[l]=="and": x[l] &= x[r]if y[l]=="or": x[l] |= x[r]if y[l]=="xor": x[l] ^= x[r]if y[l]=="imp": x[l] = x[r] if x[l] else 1print("True" if x[ss[0]] else "False")