結果

問題 No.2307 [Cherry 5 th Tune *] Cool 46
コンテスト
ユーザー first_vil
提出日時 2023-05-20 09:47:25
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 619 ms / 2,000 ms
コード長 1,844 bytes
コンパイル時間 1,055 ms
コンパイル使用メモリ 81,920 KB
実行使用メモリ 172,064 KB
最終ジャッジ日時 2024-12-21 08:19:44
合計ジャッジ時間 36,483 ms
ジャッジサーバーID
（参考情報） 		judge1 / judge3
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ファイルパターン 結果
other AC * 46
権限があれば一括ダウンロードができます

ソースコード

diff # 

from bisect import bisect_left

mi=lambda: map(int,input().split())
mi1=lambda: map(lambda x: int(x)-1,input().split())
li=lambda: list(mi())
li1=lambda: list(mi1())
ii=lambda: int(input())

def buildCompressedElementsList(a,comp=[]):
	return sorted(set(a+comp))

def compress(a,comp):
	for i in range(len(a)):
		a[i]=bisect_left(comp,a[i])

def countListElements(a,n):
	# assert all(0 <= x < n for x in a)
	res=[0]*n
	for x in a:
		res[x]+=1
	return res


printRed=lambda x: print("Red", x+1)
printBlue=lambda x: print("Blue", x+1)
def printPair(x,redFirst=True):
	if redFirst:
		printRed(x)
		printBlue(x)
	else:
		printBlue(x)
		printRed(x)

def solve():
	n,m=mi()
	a=li1()
	b=li1()
	
	if n==0:
		print("Yes")
		for x in b:
			printBlue(x)
		return
	if m==0:
		print("Yes")
		for x in a:
			printRed(x)
		return
	
	setB=set(b)
	checkAnyPair=lambda: any(x in setB for x in a)
	if not checkAnyPair():
		print("No")
		return
	
	comp=buildCompressedElementsList(a)
	comp=buildCompressedElementsList(b,comp)
	
	compress(a,comp)
	compress(b,comp)
	s=len(comp)
	cntA=countListElements(a,s)
	cntB=countListElements(b,s)
	
	red=[]
	blue=[]
	pair=[]
	for i in range(s):
		mn=min(cntA[i],cntB[i])
		pair+=[i for _ in range(mn)]
		if cntA[i]>cntB[i]:
			red+=[i for _ in range(cntA[i]-cntB[i])]
		else:
			blue+=[i for _ in range(cntB[i]-cntA[i])]
	
	
	print("Yes")
	# step 1: eat red cards which doesn't has partner
	for x in red:
		printRed(comp[x])
	
	# step 2.1: eat a pair of cards (it's guaranteed that there is at least one pair of cards, and this changes previous color to blue)
	printPair(comp[pair[0]], True)
	
	# step 2.2: eat blue cards which doesn't has partner
	for x in blue:
		printBlue(comp[x])
	
	# step 2.3: eat the other pairs of cards
	for i in range(1,len(pair)):
		printPair(comp[pair[i]],(i&1)==0)

for _ in range(ii()):
	solve()
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