結果
問題 | No.2167 Fibonacci Knapsack |
ユーザー |
👑 |
提出日時 | 2023-05-21 11:26:24 |
言語 | D (dmd 2.109.1) |
結果 |
AC
|
実行時間 | 9 ms / 2,000 ms |
コード長 | 2,792 bytes |
コンパイル時間 | 995 ms |
コンパイル使用メモリ | 132,000 KB |
実行使用メモリ | 6,948 KB |
最終ジャッジ日時 | 2024-06-22 17:57:18 |
合計ジャッジ時間 | 2,154 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 21 |
ソースコード
import std.conv, std.functional, std.range, std.stdio, std.string;import std.algorithm, std.array, std.bigint, std.bitmanip, std.complex, std.container, std.math, std.mathspecial, std.numeric, std.regex, std.typecons;import core.bitop;class EOFException : Throwable { this() { super("EOF"); } }string[] tokens;string readToken() { for (; tokens.empty; ) { if (stdin.eof) { throw new EOFException; } tokens = readln.split; } auto token = tokens.front; tokens.popFront; return token; }int readInt() { return readToken.to!int; }long readLong() { return readToken.to!long; }real readReal() { return readToken.to!real; }bool chmin(T)(ref T t, in T f) { if (t > f) { t = f; return true; } else { return false; } }bool chmax(T)(ref T t, in T f) { if (t < f) { t = f; return true; } else { return false; } }int binarySearch(alias pred, T)(in T[] as) { int lo = -1, hi = cast(int)(as.length); for (; lo + 1 < hi; ) { const mid = (lo + hi) >> 1;(unaryFun!pred(as[mid]) ? hi : lo) = mid; } return hi; }int lowerBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a >= val)); }int upperBound(T)(in T[] as, T val) { return as.binarySearch!(a => (a > val)); }void main() {enum LIM = 90;auto F = new long[LIM];F[0] = 0;F[1] = 1;foreach (i; 2 .. LIM) {F[i] = F[i - 1] + F[i - 2];}debug {writeln("F = ", F);writeln(cast(real)(F[$ - 1]));}try {for (; ; ) {const numCases = readInt;foreach (caseId; 0 .. numCases) {const N = readInt;const W = readLong;auto A = new long[N + 2];foreach (i; 2 .. N + 2) {A[i] = readLong;}alias Entry = Tuple!(long, "x", long, "cost");Entry[] crt = [Entry(0, 0)];foreach_reverse (i; 2 .. N + 2) {/*will remain: F[2] + ... + F[i-1] = F[i+1] - 2{x, x + F[i]} -> {x, x + F[i], x + 2 F[i]}2 F[i] > F[i+1] - 2{x, x + F[i+1]} -> {x, x + F[i], x + F[i+1], x + F[i+2]}F[i+1] > F[i+1] - 2*/assert(crt.length == 1 ||(crt.length == 2 && (crt[1].x == crt[0].x + F[i] || crt[1].x == crt[0].x + F[i+1])));Entry[] nxt = crt.dup;foreach (e; crt) {if (e.cost + A[i] <= W) {nxt ~= Entry(e.x + F[i], e.cost + A[i]);}}nxt.sort;const x0 = nxt[$ - 1].x - (F[i+1] - 2);crt = [];foreach (e; nxt) if (e.x >= x0) {if (crt.empty || crt[$ - 1].x < e.x) {crt ~= e;}}debug {writeln(crt);}}writeln(crt[$ - 1].x);}}} catch (EOFException e) {}}