結果
| 問題 | No.2324 Two Countries within UEC |
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2023-05-28 14:19:35 |
| 言語 | C++17 (gcc 15.2.0 + boost 1.90.0) |
| 結果 |
AC
|
| 実行時間 | 103 ms / 2,000 ms |
| コード長 | 871 bytes |
| 記録 | |
| コンパイル時間 | 2,924 ms |
| コンパイル使用メモリ | 273,232 KB |
| 実行使用メモリ | 6,528 KB |
| 最終ジャッジ日時 | 2026-06-30 22:22:15 |
| 合計ジャッジ時間 | 6,794 ms |
|
ジャッジサーバーID (参考情報) |
judge3_0 / judge2_0 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 2 |
| other | AC * 41 |
コンパイルメッセージ
main.cpp: In function 'int main()':
main.cpp:26:36: warning: ignoring return value of 'std::basic_ostream<_CharT, _Traits>* std::basic_ios<_CharT, _Traits>::tie() const [with _CharT = char; _Traits = std::char_traits<char>]', declared with attribute 'nodiscard' [-Wunused-result]
26 | ios::sync_with_stdio(0);cin.tie();
| ~~~~~~~^~
In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/ios:48,
from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/istream:42,
from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/sstream:42,
from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/complex:50,
from /home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/x86_64-pc-linux-gnu/bits/stdc++.h:141,
from main.cpp:1:
/home/linuxbrew/.linuxbrew/Cellar/gcc/15.2.0_1/include/c++/15/bits/basic_ios.h:310:7: note: declared here
310 | tie() const
| ^~~
ソースコード
#include <bits/stdc++.h>
#include <atcoder/all>
using ll = long long;
#define MOD 1000000007
#define Mod 998244353
const int MAX = 1000000005;
const long long INF = 1000000000000000005LL;
using namespace std;
using namespace atcoder;
ll modpow(ll a, ll n, ll m) {
ll res = 1;
while (n > 0) {
if (n & 1) res = res * a % m;
a = a * a % m;
n >>= 1;
}
return res;
}
ll modinv(ll a, ll m) {
return modpow(a, m-2, m);
}
int main() {
ios::sync_with_stdio(0);cin.tie();
int N, M, P, Q;
cin >> N >> M >> P >> Q;
while (Q--) {
int x, f;
cin >> x >> f;
int a = modinv(x, P) * f % P;
if (x % P == 0) {
cout << (f == 0 ? M : 0) << endl;
continue;
}
if (M < a) {
cout << 0 << endl;
} else {
cout << (M - a)/P + 1 - (a == 0) << endl;
}
}
}